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Performing Raster Calculation?


Iterate through all fields in attribute table and multiply by fieldPerforming unweighted overlay on multiple raster layersscript to draw a square where the raster pixels contained within are a certain type and greater than XConditional Combine Rasters and Track which Raster pixel usedReclassify raster based on Z-values in Arcmap 10.4.1Combining two reclassified raster images in ArcGIS Desktop?How to extend Raster layer without pixel value data losingExtracting multi values to raster?calculate 'predicted class' raster in QGISMax value for each cell













0















This is my formal:



("Standort_ger_fre_mosaic" ^ 0.4) *
("Habitattradition_raster_rec.tif" ^ 0.3) *
("Vollständigkeit_rec.tif" ^ 0.1) *
("Vorkommen_ungestörter_Lebensräume_rec.tif" ^ 0.1) *
("Vorkommen_von_Arten_dynamischer_Lebensräume_rec.tif"^ 0.1)


I would like to charge the pixels of the above-mentioned layers together.
As a final product,enter image description here I would like to have a file that has different values ​​for each pixel.
When I do the computation, my final product has only one value in each pixel. This is equal to 0



I am working with ArcMap 10.6










share|improve this question









New contributor




Tim Holst is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
























    0















    This is my formal:



    ("Standort_ger_fre_mosaic" ^ 0.4) *
    ("Habitattradition_raster_rec.tif" ^ 0.3) *
    ("Vollständigkeit_rec.tif" ^ 0.1) *
    ("Vorkommen_ungestörter_Lebensräume_rec.tif" ^ 0.1) *
    ("Vorkommen_von_Arten_dynamischer_Lebensräume_rec.tif"^ 0.1)


    I would like to charge the pixels of the above-mentioned layers together.
    As a final product,enter image description here I would like to have a file that has different values ​​for each pixel.
    When I do the computation, my final product has only one value in each pixel. This is equal to 0



    I am working with ArcMap 10.6










    share|improve this question









    New contributor




    Tim Holst is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      0












      0








      0








      This is my formal:



      ("Standort_ger_fre_mosaic" ^ 0.4) *
      ("Habitattradition_raster_rec.tif" ^ 0.3) *
      ("Vollständigkeit_rec.tif" ^ 0.1) *
      ("Vorkommen_ungestörter_Lebensräume_rec.tif" ^ 0.1) *
      ("Vorkommen_von_Arten_dynamischer_Lebensräume_rec.tif"^ 0.1)


      I would like to charge the pixels of the above-mentioned layers together.
      As a final product,enter image description here I would like to have a file that has different values ​​for each pixel.
      When I do the computation, my final product has only one value in each pixel. This is equal to 0



      I am working with ArcMap 10.6










      share|improve this question









      New contributor




      Tim Holst is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      This is my formal:



      ("Standort_ger_fre_mosaic" ^ 0.4) *
      ("Habitattradition_raster_rec.tif" ^ 0.3) *
      ("Vollständigkeit_rec.tif" ^ 0.1) *
      ("Vorkommen_ungestörter_Lebensräume_rec.tif" ^ 0.1) *
      ("Vorkommen_von_Arten_dynamischer_Lebensräume_rec.tif"^ 0.1)


      I would like to charge the pixels of the above-mentioned layers together.
      As a final product,enter image description here I would like to have a file that has different values ​​for each pixel.
      When I do the computation, my final product has only one value in each pixel. This is equal to 0



      I am working with ArcMap 10.6







      arcgis-desktop spatial-analyst raster-calculator






      share|improve this question









      New contributor




      Tim Holst is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Tim Holst is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 13 hours ago









      PolyGeo

      53.8k1781244




      53.8k1781244






      New contributor




      Tim Holst is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 13 hours ago









      Tim HolstTim Holst

      1




      1




      New contributor




      Tim Holst is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Tim Holst is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Tim Holst is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          2 Answers
          2






          active

          oldest

          votes


















          0














          Instead of using "^", use the "Power" function as follows:



          (Power("Standort_ger_fre_mosaic",0.4)) *
          (Power("Habitattradition_raster_rec.tif",0.3)) *
          ...





          share|improve this answer






























            0














            This is probably a rounding issue. Please try converting your image values to float before the exponent. Also I suggest to use Power.



            Power(Float("Standort_ger_fre_mosaic"),0.4) ) *
            Power(Float("Habitattradition_raster_rec.tif"),0.3) ...





            share|improve this answer























            • I think the Power function alone does the trick. I tried Power("image",0.4) with an uint8 image and it worked just fine

              – kowalski
              13 hours ago










            Your Answer








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            2 Answers
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            active

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            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            Instead of using "^", use the "Power" function as follows:



            (Power("Standort_ger_fre_mosaic",0.4)) *
            (Power("Habitattradition_raster_rec.tif",0.3)) *
            ...





            share|improve this answer



























              0














              Instead of using "^", use the "Power" function as follows:



              (Power("Standort_ger_fre_mosaic",0.4)) *
              (Power("Habitattradition_raster_rec.tif",0.3)) *
              ...





              share|improve this answer

























                0












                0








                0







                Instead of using "^", use the "Power" function as follows:



                (Power("Standort_ger_fre_mosaic",0.4)) *
                (Power("Habitattradition_raster_rec.tif",0.3)) *
                ...





                share|improve this answer













                Instead of using "^", use the "Power" function as follows:



                (Power("Standort_ger_fre_mosaic",0.4)) *
                (Power("Habitattradition_raster_rec.tif",0.3)) *
                ...






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 13 hours ago









                kowalskikowalski

                135210




                135210























                    0














                    This is probably a rounding issue. Please try converting your image values to float before the exponent. Also I suggest to use Power.



                    Power(Float("Standort_ger_fre_mosaic"),0.4) ) *
                    Power(Float("Habitattradition_raster_rec.tif"),0.3) ...





                    share|improve this answer























                    • I think the Power function alone does the trick. I tried Power("image",0.4) with an uint8 image and it worked just fine

                      – kowalski
                      13 hours ago















                    0














                    This is probably a rounding issue. Please try converting your image values to float before the exponent. Also I suggest to use Power.



                    Power(Float("Standort_ger_fre_mosaic"),0.4) ) *
                    Power(Float("Habitattradition_raster_rec.tif"),0.3) ...





                    share|improve this answer























                    • I think the Power function alone does the trick. I tried Power("image",0.4) with an uint8 image and it worked just fine

                      – kowalski
                      13 hours ago













                    0












                    0








                    0







                    This is probably a rounding issue. Please try converting your image values to float before the exponent. Also I suggest to use Power.



                    Power(Float("Standort_ger_fre_mosaic"),0.4) ) *
                    Power(Float("Habitattradition_raster_rec.tif"),0.3) ...





                    share|improve this answer













                    This is probably a rounding issue. Please try converting your image values to float before the exponent. Also I suggest to use Power.



                    Power(Float("Standort_ger_fre_mosaic"),0.4) ) *
                    Power(Float("Habitattradition_raster_rec.tif"),0.3) ...






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 13 hours ago









                    radouxjuradouxju

                    41.2k144121




                    41.2k144121












                    • I think the Power function alone does the trick. I tried Power("image",0.4) with an uint8 image and it worked just fine

                      – kowalski
                      13 hours ago

















                    • I think the Power function alone does the trick. I tried Power("image",0.4) with an uint8 image and it worked just fine

                      – kowalski
                      13 hours ago
















                    I think the Power function alone does the trick. I tried Power("image",0.4) with an uint8 image and it worked just fine

                    – kowalski
                    13 hours ago





                    I think the Power function alone does the trick. I tried Power("image",0.4) with an uint8 image and it worked just fine

                    – kowalski
                    13 hours ago










                    Tim Holst is a new contributor. Be nice, and check out our Code of Conduct.









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