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How do I get all objects in a nested array after performing a calculation in JavaScript?

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7

I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

javascript jquery arrays object

share|improve this question

edited 6 hours ago

Boann

37.4k1290121

asked 19 hours ago

SenthilSenthil

413

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  where did you iterate it?
  
  – M.Hemant
  19 hours ago
  

  
  
  
  

add a comment | 

7

I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

javascript jquery arrays object

share|improve this question

edited 6 hours ago

Boann

37.4k1290121

asked 19 hours ago

SenthilSenthil

413

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  where did you iterate it?
  
  – M.Hemant
  19 hours ago
  

  
  
  
  

add a comment | 

I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

javascript jquery arrays object

share|improve this question

edited 6 hours ago

Boann

37.4k1290121

asked 19 hours ago

SenthilSenthil

413

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

share|improve this question

edited 6 hours ago

Boann

37.4k1290121

asked 19 hours ago

SenthilSenthil

413

share|improve this question

edited 6 hours ago

Boann

37.4k1290121

asked 19 hours ago

SenthilSenthil

413

edited 6 hours ago

Boann

37.4k1290121

edited 6 hours ago

Boann

37.4k1290121

asked 19 hours ago

SenthilSenthil

413

asked 19 hours ago

SenthilSenthil

413

3 Answers
3

active

oldest

votes

3

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited 18 hours ago

answered 19 hours ago

R3tepR3tep

8,10882962

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  doesnot match the expected output..
  
  – Maheer Ali
  19 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Still doesnot match expected output.
  
  – Maheer Ali
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From where send property come. And sourceamount which is expected output and 4000 should be "4,000"
  
  – Maheer Ali
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MaheerAli Come from the OP example code. And thanks for "4,000"
  
  – R3tep
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I mistyped sourceamount there was send property in old code. But now its fine so +1
  
  – Maheer Ali
  18 hours ago
  
  

  
  
  
  

add a comment | 

7

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited 17 hours ago

answered 19 hours ago

Zakaria AcharkiZakaria Acharki

56.4k134471

add a comment | 

3

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited 18 hours ago

answered 18 hours ago

Francis LeighFrancis Leigh

821313

add a comment | 

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3

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited 18 hours ago

answered 19 hours ago

R3tepR3tep

8,10882962

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  doesnot match the expected output..
  
  – Maheer Ali
  19 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Still doesnot match expected output.
  
  – Maheer Ali
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From where send property come. And sourceamount which is expected output and 4000 should be "4,000"
  
  – Maheer Ali
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MaheerAli Come from the OP example code. And thanks for "4,000"
  
  – R3tep
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I mistyped sourceamount there was send property in old code. But now its fine so +1
  
  – Maheer Ali
  18 hours ago
  
  

  
  
  
  

add a comment | 

3

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited 18 hours ago

answered 19 hours ago

R3tepR3tep

8,10882962

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  doesnot match the expected output..
  
  – Maheer Ali
  19 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Still doesnot match expected output.
  
  – Maheer Ali
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From where send property come. And sourceamount which is expected output and 4000 should be "4,000"
  
  – Maheer Ali
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MaheerAli Come from the OP example code. And thanks for "4,000"
  
  – R3tep
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I mistyped sourceamount there was send property in old code. But now its fine so +1
  
  – Maheer Ali
  18 hours ago
  
  

  
  
  
  

add a comment | 

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited 18 hours ago

answered 19 hours ago

R3tepR3tep

8,10882962

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited 18 hours ago

answered 19 hours ago

R3tepR3tep

8,10882962

answered 19 hours ago

R3tepR3tep

8,10882962

answered 19 hours ago

R3tepR3tep

8,10882962

7

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited 17 hours ago

answered 19 hours ago

Zakaria AcharkiZakaria Acharki

56.4k134471

add a comment | 

7

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited 17 hours ago

answered 19 hours ago

Zakaria AcharkiZakaria Acharki

56.4k134471

add a comment | 

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited 17 hours ago

answered 19 hours ago

Zakaria AcharkiZakaria Acharki

56.4k134471

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited 17 hours ago

answered 19 hours ago

Zakaria AcharkiZakaria Acharki

56.4k134471

answered 19 hours ago

Zakaria AcharkiZakaria Acharki

56.4k134471

answered 19 hours ago

Zakaria AcharkiZakaria Acharki

56.4k134471

3

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited 18 hours ago

answered 18 hours ago

Francis LeighFrancis Leigh

821313

add a comment | 

3

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited 18 hours ago

answered 18 hours ago

Francis LeighFrancis Leigh

821313

add a comment | 

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited 18 hours ago

answered 18 hours ago

Francis LeighFrancis Leigh

821313

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited 18 hours ago

answered 18 hours ago

Francis LeighFrancis Leigh

821313

answered 18 hours ago

Francis LeighFrancis Leigh

821313

answered 18 hours ago

Francis LeighFrancis Leigh

821313