Unlock My Phone! February 2018Unlock My Phone! January 2018The summer term exams must go onIn standard isolated labWe have an important mission for youARG - morse/wordplay puzzle?A Puzzling Cipher: ReduxI can't unlock my phone!Enigmatic AnimalsAn important club and two competing applicantsThe “Three Diamond” Distilling CompanyUnlock My Phone! January 2018
Why not use SQL instead of GraphQL?
Can I make popcorn with any corn?
Fencing style for blades that can attack from a distance
In a 5 years PhD, is it possible to get a postdoc position with one publication? I can really use some advice
Languages that we cannot (dis)prove to be Context-Free
How to format long polynomial?
Finding the repeating unit of polymerisation given two constituent molecules
How to add double frame in tcolorbox?
Can an x86 CPU running in real mode be considered to be basically an 8086 CPU?
What's the output of a record cartridge playing an out-of-speed record
What typically incentivizes a professor to change jobs to a lower ranking university?
What does it mean to describe someone as a butt steak?
How do we improve the relationship with a client software team that performs poorly and is becoming less collaborative?
Why doesn't H₄O²⁺ exist?
1 as a common root of a quadratic equation
Have astronauts in space suits ever taken selfies? If so, how?
The Clique vs. Independent Set Problem
Why is consensus so controversial in Britain?
Fully-Firstable Anagram Sets
Why is Minecraft giving an OpenGL error?
Why "Having chlorophyll without photosynthesis is actually very dangerous" and "like living with a bomb"?
Does Unearthed Arcana render Favored Souls redundant?
How is it possible to have an ability score that is less than 3?
Mage Armor with Defense fighting style (for Adventurers League bladeslinger)
Unlock My Phone! February 2018
Unlock My Phone! January 2018The summer term exams must go onIn standard isolated labWe have an important mission for youARG - morse/wordplay puzzle?A Puzzling Cipher: ReduxI can't unlock my phone!Enigmatic AnimalsAn important club and two competing applicantsThe “Three Diamond” Distilling CompanyUnlock My Phone! January 2018
$begingroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?
Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?
Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
add a comment |
$begingroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?
Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?
Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
knowledge visual
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Apr 3 at 0:26
Tyler22Alex
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
316212
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
316212
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
add a comment |
1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
1
1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
add a comment |
8 Answers
8
active
oldest
votes
$begingroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
33626
New contributor
RedBaron is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
$endgroup$
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,59821073
$endgroup$
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
$endgroup$
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
1,65222
$endgroup$
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
$endgroup$
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
$begingroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "559"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81316%2funlock-my-phone-february-2018%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
33626
New contributor
RedBaron is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
$begingroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
33626
New contributor
RedBaron is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
$begingroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
33626
New contributor
RedBaron is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
33626
New contributor
RedBaron is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Apr 3 at 8:08
answered Apr 3 at 7:40
RedBaronRedBaron
33626
New contributor
RedBaron is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Apr 3 at 7:40
RedBaronRedBaron
33626
answered Apr 3 at 7:40
RedBaronRedBaron
33626
33626
New contributor
RedBaron is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
RedBaron is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
RedBaron is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
5
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
$endgroup$
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
$endgroup$
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
$endgroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
answered Apr 2 at 19:49
AProughAPrough
5,9061245
answered Apr 2 at 19:49
AProughAPrough
5,9061245
answered Apr 2 at 19:49
AProughAPrough
5,9061245
5,9061245
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
1
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,59821073
$endgroup$
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,59821073
$endgroup$
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,59821073
$endgroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,59821073
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,59821073
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,59821073
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,59821073
6,59821073
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
7
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
$endgroup$
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
$endgroup$
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
$endgroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
answered Apr 2 at 21:21
user1812user1812
912
answered Apr 2 at 21:21
user1812user1812
912
answered Apr 2 at 21:21
user1812user1812
912
912
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
1
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
1,65222
$endgroup$
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
1,65222
$endgroup$
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
1,65222
$endgroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
1,65222
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
1,65222
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
1,65222
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
1,65222
1,65222
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
1
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
$endgroup$
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
$endgroup$
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
$endgroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
30.5k567188
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
1
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Apr 2 at 21:05
tuvokkituvokki
1312
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Apr 2 at 21:05
tuvokkituvokki
1312
answered Apr 2 at 21:05
tuvokkituvokki
1312
1312
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
1
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
$begingroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
$endgroup$
add a comment |
$begingroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
$endgroup$
add a comment |
$begingroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
$endgroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
answered Apr 3 at 12:52
PeterPeter
2006
answered Apr 3 at 12:52
PeterPeter
2006
answered Apr 3 at 12:52
PeterPeter
2006
2006
add a comment |
add a comment |
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81316%2funlock-my-phone-february-2018%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32