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2

0

I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.

Currently the relevant part of the function looks like this:

print_music()
 awk 'gsub("position ", "");print'`
 duration=`cmus-remote -Q 

bash awk

share|improve this question

edited Apr 2 at 20:05

αғsнιη

17.1k103069

asked Apr 2 at 19:09

JoeJoe

223

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Is this stackoverflow.com/q/13422743/4023950 what you need?
  
  – αғsнιη
  Apr 2 at 20:02
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.
  
  – bu5hman
  Apr 2 at 20:18
  
  

  
  
  
  

add a comment | 

2

0

I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.

Currently the relevant part of the function looks like this:

print_music()
 awk 'gsub("position ", "");print'`
 duration=`cmus-remote -Q 

bash awk

share|improve this question

edited Apr 2 at 20:05

αғsнιη

17.1k103069

asked Apr 2 at 19:09

JoeJoe

223

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Is this stackoverflow.com/q/13422743/4023950 what you need?
  
  – αғsнιη
  Apr 2 at 20:02
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.
  
  – bu5hman
  Apr 2 at 20:18
  
  

  
  
  
  

add a comment | 

I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.

Currently the relevant part of the function looks like this:

print_music()
 awk 'gsub("position ", "");print'`
 duration=`cmus-remote -Q 

bash awk

share|improve this question

edited Apr 2 at 20:05

αғsнιη

17.1k103069

asked Apr 2 at 19:09

JoeJoe

223

print_music()
 awk 'gsub("position ", "");print'`
 duration=`cmus-remote -Q 

share|improve this question

edited Apr 2 at 20:05

αғsнιη

17.1k103069

asked Apr 2 at 19:09

JoeJoe

223

share|improve this question

edited Apr 2 at 20:05

αғsнιη

17.1k103069

asked Apr 2 at 19:09

JoeJoe

223

edited Apr 2 at 20:05

αғsнιη

17.1k103069

edited Apr 2 at 20:05

αғsнιη

17.1k103069

asked Apr 2 at 19:09

JoeJoe

223

asked Apr 2 at 19:09

JoeJoe

223

1 Answer
1

active

oldest

votes

6

This will help you:

sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 

$ sec2min 500
8:20
$ sec2min 1
0:01

share|improve this answer

answered Apr 2 at 20:02

glenn jackmanglenn jackman

53k573114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! That's working perfectly :)
  
  – Joe
  Apr 2 at 22:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
  
  – RubberStamp
  Apr 3 at 0:41
  

  
  
  
  

add a comment | 

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6

This will help you:

sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 

$ sec2min 500
8:20
$ sec2min 1
0:01

share|improve this answer

answered Apr 2 at 20:02

glenn jackmanglenn jackman

53k573114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! That's working perfectly :)
  
  – Joe
  Apr 2 at 22:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
  
  – RubberStamp
  Apr 3 at 0:41
  

  
  
  
  

add a comment | 

6

This will help you:

sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 

$ sec2min 500
8:20
$ sec2min 1
0:01

share|improve this answer

answered Apr 2 at 20:02

glenn jackmanglenn jackman

53k573114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! That's working perfectly :)
  
  – Joe
  Apr 2 at 22:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
  
  – RubberStamp
  Apr 3 at 0:41
  

  
  
  
  

add a comment | 

This will help you:

sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 

$ sec2min 500
8:20
$ sec2min 1
0:01

share|improve this answer

answered Apr 2 at 20:02

glenn jackmanglenn jackman

53k573114

sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 

$ sec2min 500
8:20
$ sec2min 1
0:01

share|improve this answer

answered Apr 2 at 20:02

glenn jackmanglenn jackman

53k573114

answered Apr 2 at 20:02

glenn jackmanglenn jackman

53k573114

answered Apr 2 at 20:02

glenn jackmanglenn jackman

53k573114