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Is it possible to search for a directory/file combination?
The Next CEO of Stack OverflowFind path that has specific sub directoryksh:Linux - Command to find a particular directory/fileIs there a way to find a file in an inverse recursive search?Find images by size: find / file / awkExclude directory in findHow do I search all subdirectories to find one with a certain name?Efficiently finding a file/directory based on keywordIdentify sub-directories that do not contain a specific string in a specific fileHow to use the results of “file” (Name of Creating Application: Microsoft Word) to search for a specific string?Search for files within a directoryfind a file through particular search in while loopCreating text files in every sub-directory
I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:
cd /
find . -name "ABC_MPSC/ABC.jpg"
But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could have helped me not have to search manually?
find
New contributor
add a comment |
I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:
cd /
find . -name "ABC_MPSC/ABC.jpg"
But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could have helped me not have to search manually?
find
New contributor
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
2 days ago
2
You can also find it usinglocate
, which should be significantly faster, but only works if the file already existed whenupdatedb
was last run.
– Simon Richter
2 days ago
add a comment |
I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:
cd /
find . -name "ABC_MPSC/ABC.jpg"
But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could have helped me not have to search manually?
find
New contributor
I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:
cd /
find . -name "ABC_MPSC/ABC.jpg"
But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could have helped me not have to search manually?
find
find
New contributor
New contributor
New contributor
asked 2 days ago
PascLeRascPascLeRasc
1534
1534
New contributor
New contributor
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
2 days ago
2
You can also find it usinglocate
, which should be significantly faster, but only works if the file already existed whenupdatedb
was last run.
– Simon Richter
2 days ago
add a comment |
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
2 days ago
2
You can also find it usinglocate
, which should be significantly faster, but only works if the file already existed whenupdatedb
was last run.
– Simon Richter
2 days ago
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
2 days ago
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
2 days ago
2
2
You can also find it using
locate
, which should be significantly faster, but only works if the file already existed when updatedb
was last run.– Simon Richter
2 days ago
You can also find it using
locate
, which should be significantly faster, but only works if the file already existed when updatedb
was last run.– Simon Richter
2 days ago
add a comment |
2 Answers
2
active
oldest
votes
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
add a comment |
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f /ABC.jpg ; -print
This relies on the
find
implementation to expandto the current pathname of the found directory, even though it's concatenated with
/ABC.jpg
(it's not required to do that). It could also be written asfind / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh ; -printLook for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
add a comment |
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
add a comment |
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
edited 2 days ago
answered 2 days ago
Jeff Schaller♦Jeff Schaller
44.4k1162143
44.4k1162143
add a comment |
add a comment |
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f /ABC.jpg ; -print
This relies on the
find
implementation to expandto the current pathname of the found directory, even though it's concatenated with
/ABC.jpg
(it's not required to do that). It could also be written asfind / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh ; -printLook for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
add a comment |
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f /ABC.jpg ; -print
This relies on the
find
implementation to expandto the current pathname of the found directory, even though it's concatenated with
/ABC.jpg
(it's not required to do that). It could also be written asfind / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh ; -printLook for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
add a comment |
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f /ABC.jpg ; -print
This relies on the
find
implementation to expandto the current pathname of the found directory, even though it's concatenated with
/ABC.jpg
(it's not required to do that). It could also be written asfind / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh ; -printLook for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f /ABC.jpg ; -print
This relies on the
find
implementation to expandto the current pathname of the found directory, even though it's concatenated with
/ABC.jpg
(it's not required to do that). It could also be written asfind / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh ; -printLook for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
edited 2 days ago
answered 2 days ago
Kusalananda♦Kusalananda
139k17259429
139k17259429
add a comment |
add a comment |
PascLeRasc is a new contributor. Be nice, and check out our Code of Conduct.
PascLeRasc is a new contributor. Be nice, and check out our Code of Conduct.
PascLeRasc is a new contributor. Be nice, and check out our Code of Conduct.
PascLeRasc is a new contributor. Be nice, and check out our Code of Conduct.
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Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
2 days ago
2
You can also find it using
locate
, which should be significantly faster, but only works if the file already existed whenupdatedb
was last run.– Simon Richter
2 days ago