Parametric curve length - calculus [on hold] The Next CEO of Stack OverflowDetect “cusp” in parametric curveFind the length of the parametric curve (Difficult)Parametric curve parametriced by lengthCompute the length of a parametric curve.Arc Length parametric curveSampling a curve (parametric)Arc Length with Parametric EquationsFind the length of the parametric curveDetermine the length of the Parametric Curve given by the set of parametric equations.Length of a parametric curve formula: What does the integral represent?
Raspberry pi 3 B with Ubuntu 18.04 server arm64: what chip
Small nick on power cord from an electric alarm clock, and copper wiring exposed but intact
Is it correct to say moon starry nights?
IC has pull-down resistors on SMBus lines?
Physiological effects of huge anime eyes
How to use ReplaceAll on an expression that contains a rule
Airplane gently rocking its wings during whole flight
Is it convenient to ask the journal's editor for two additional days to complete a review?
Getting Stale Gas Out of a Gas Tank w/out Dropping the Tank
How do I fit a non linear curve?
Film where the government was corrupt with aliens, people sent to kill aliens are given rigged visors not showing the right aliens
Is it ever safe to open a suspicious HTML file (e.g. email attachment)?
What does "shotgun unity" refer to here in this sentence?
Is there a reasonable and studied concept of reduction between regular languages?
Is Nisuin Biblical or Rabbinic?
Is fine stranded wire ok for main supply line?
It is correct to match light sources with the same color temperature?
Yu-Gi-Oh cards in Python 3
Towers in the ocean; How deep can they be built?
What is the process for purifying your home if you believe it may have been previously used for pagan worship?
In the "Harry Potter and the Order of the Phoenix" video game, what potion is used to sabotage Umbridge's speakers?
Plausibility of squid whales
If Nick Fury and Coulson already knew about aliens (Kree and Skrull) why did they wait until Thor's appearance to start making weapons?
What was Carter Burke's job for "the company" in Aliens?
Parametric curve length - calculus [on hold]
The Next CEO of Stack OverflowDetect “cusp” in parametric curveFind the length of the parametric curve (Difficult)Parametric curve parametriced by lengthCompute the length of a parametric curve.Arc Length parametric curveSampling a curve (parametric)Arc Length with Parametric EquationsFind the length of the parametric curveDetermine the length of the Parametric Curve given by the set of parametric equations.Length of a parametric curve formula: What does the integral represent?
$begingroup$
Find the length of the following parametric curve.
$x = 5 + frac92 t^3$, $y = 4 + 3 t^frac92$, $0 leq t leq 2$.
I used integration and after some point I got lost :( What are the steps?
calculus parametric
edited 2 days ago
Peter Mortensen
565310
asked 2 days ago
McAMcA
264
$endgroup$
put on hold as off-topic by Travis, Jyrki Lahtonen, Leucippus, Eevee Trainer, José Carlos Santos yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Travis, Jyrki Lahtonen, Leucippus, Eevee Trainer, José Carlos Santos
add a comment |
$begingroup$
Find the length of the following parametric curve.
$x = 5 + frac92 t^3$, $y = 4 + 3 t^frac92$, $0 leq t leq 2$.
I used integration and after some point I got lost :( What are the steps?
calculus parametric
edited 2 days ago
Peter Mortensen
565310
asked 2 days ago
McAMcA
264
$endgroup$
put on hold as off-topic by Travis, Jyrki Lahtonen, Leucippus, Eevee Trainer, José Carlos Santos yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Travis, Jyrki Lahtonen, Leucippus, Eevee Trainer, José Carlos Santos
$begingroup$
Is this $$x=5+frac92t^3,y=4+3t^9/2$$?
$endgroup$
– Dr. Sonnhard Graubner
2 days ago
add a comment |
$begingroup$
Find the length of the following parametric curve.
$x = 5 + frac92 t^3$, $y = 4 + 3 t^frac92$, $0 leq t leq 2$.
I used integration and after some point I got lost :( What are the steps?
calculus parametric
edited 2 days ago
Peter Mortensen
565310
asked 2 days ago
McAMcA
264
$endgroup$
Find the length of the following parametric curve.
$x = 5 + frac92 t^3$, $y = 4 + 3 t^frac92$, $0 leq t leq 2$.
I used integration and after some point I got lost :( What are the steps?
calculus parametric
calculus parametric
edited 2 days ago
Peter Mortensen
565310
asked 2 days ago
McAMcA
264
edited 2 days ago
Peter Mortensen
565310
asked 2 days ago
McAMcA
264
edited 2 days ago
Peter Mortensen
565310
edited 2 days ago
Peter Mortensen
565310
edited 2 days ago
Peter Mortensen
565310
565310
asked 2 days ago
McAMcA
264
asked 2 days ago
McAMcA
264
asked 2 days ago
McAMcA
264
264
put on hold as off-topic by Travis, Jyrki Lahtonen, Leucippus, Eevee Trainer, José Carlos Santos yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Travis, Jyrki Lahtonen, Leucippus, Eevee Trainer, José Carlos Santos
put on hold as off-topic by Travis, Jyrki Lahtonen, Leucippus, Eevee Trainer, José Carlos Santos yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Travis, Jyrki Lahtonen, Leucippus, Eevee Trainer, José Carlos Santos
$begingroup$
Is this $$x=5+frac92t^3,y=4+3t^9/2$$?
$endgroup$
– Dr. Sonnhard Graubner
2 days ago
add a comment |
$begingroup$
Is this $$x=5+frac92t^3,y=4+3t^9/2$$?
$endgroup$
– Dr. Sonnhard Graubner
2 days ago
$begingroup$
Is this $$x=5+frac92t^3,y=4+3t^9/2$$?
$endgroup$
– Dr. Sonnhard Graubner
2 days ago
$begingroup$
Is this $$x=5+frac92t^3,y=4+3t^9/2$$?
$endgroup$
– Dr. Sonnhard Graubner
2 days ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
You must use the formula $$int_0^2sqrtleft(fracdxdtright)^2+left(fracdydtright)^2dt$$
$$dx=frac923t^2dt$$ and $$dy=3cdot frac92t^7/2dt$$
answered 2 days ago
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
78.4k42867
$endgroup$
add a comment |
$begingroup$
Apply the formula for arc length, we get
$$
int_0^2 frac27t^2,sqrtt^3+12 dt
$$
Then we make the change of variable $v=t^3+1$ to get
$$
int_1^9 frac 9 2 sqrtv dv = 78.
$$
answered 2 days ago
EagleToLearnEagleToLearn
534
New contributor
EagleToLearn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
beginalignedL&=int_0^2 sqrtfrac7294t^4+frac7294t^7dt\&=int_0^2sqrtfrac7294t^4(1+t^3)dt\&=frac272int_0^2t^2(1+t^3)^frac12dt\&=3(1+t^3)^frac32big]_0^2endaligned
Made the leap from the third line to the fourth line by recognizing that $F(t)=3(1+t^3)^frac32$ is an antiderivative of $f(t)=frac272t^2(1+t^3)^frac12$.
answered 2 days ago
Matt A PeltoMatt A Pelto
2,667621
$endgroup$
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You must use the formula $$int_0^2sqrtleft(fracdxdtright)^2+left(fracdydtright)^2dt$$
$$dx=frac923t^2dt$$ and $$dy=3cdot frac92t^7/2dt$$
answered 2 days ago
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
78.4k42867
$endgroup$
add a comment |
$begingroup$
You must use the formula $$int_0^2sqrtleft(fracdxdtright)^2+left(fracdydtright)^2dt$$
$$dx=frac923t^2dt$$ and $$dy=3cdot frac92t^7/2dt$$
answered 2 days ago
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
78.4k42867
$endgroup$
add a comment |
$begingroup$
You must use the formula $$int_0^2sqrtleft(fracdxdtright)^2+left(fracdydtright)^2dt$$
$$dx=frac923t^2dt$$ and $$dy=3cdot frac92t^7/2dt$$
answered 2 days ago
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
78.4k42867
$endgroup$
You must use the formula $$int_0^2sqrtleft(fracdxdtright)^2+left(fracdydtright)^2dt$$
$$dx=frac923t^2dt$$ and $$dy=3cdot frac92t^7/2dt$$
answered 2 days ago
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
78.4k42867
answered 2 days ago
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
78.4k42867
answered 2 days ago
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
78.4k42867
answered 2 days ago
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
78.4k42867
78.4k42867
add a comment |
add a comment |
$begingroup$
Apply the formula for arc length, we get
$$
int_0^2 frac27t^2,sqrtt^3+12 dt
$$
Then we make the change of variable $v=t^3+1$ to get
$$
int_1^9 frac 9 2 sqrtv dv = 78.
$$
answered 2 days ago
EagleToLearnEagleToLearn
534
New contributor
EagleToLearn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Apply the formula for arc length, we get
$$
int_0^2 frac27t^2,sqrtt^3+12 dt
$$
Then we make the change of variable $v=t^3+1$ to get
$$
int_1^9 frac 9 2 sqrtv dv = 78.
$$
answered 2 days ago
EagleToLearnEagleToLearn
534
New contributor
EagleToLearn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Apply the formula for arc length, we get
$$
int_0^2 frac27t^2,sqrtt^3+12 dt
$$
Then we make the change of variable $v=t^3+1$ to get
$$
int_1^9 frac 9 2 sqrtv dv = 78.
$$
answered 2 days ago
EagleToLearnEagleToLearn
534
New contributor
EagleToLearn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Apply the formula for arc length, we get
$$
int_0^2 frac27t^2,sqrtt^3+12 dt
$$
Then we make the change of variable $v=t^3+1$ to get
$$
int_1^9 frac 9 2 sqrtv dv = 78.
$$
answered 2 days ago
EagleToLearnEagleToLearn
534
New contributor
EagleToLearn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
EagleToLearnEagleToLearn
534
New contributor
EagleToLearn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
EagleToLearnEagleToLearn
534
answered 2 days ago
EagleToLearnEagleToLearn
534
534
New contributor
EagleToLearn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
EagleToLearn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
EagleToLearn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
$begingroup$
beginalignedL&=int_0^2 sqrtfrac7294t^4+frac7294t^7dt\&=int_0^2sqrtfrac7294t^4(1+t^3)dt\&=frac272int_0^2t^2(1+t^3)^frac12dt\&=3(1+t^3)^frac32big]_0^2endaligned
Made the leap from the third line to the fourth line by recognizing that $F(t)=3(1+t^3)^frac32$ is an antiderivative of $f(t)=frac272t^2(1+t^3)^frac12$.
answered 2 days ago
Matt A PeltoMatt A Pelto
2,667621
$endgroup$
add a comment |
$begingroup$
beginalignedL&=int_0^2 sqrtfrac7294t^4+frac7294t^7dt\&=int_0^2sqrtfrac7294t^4(1+t^3)dt\&=frac272int_0^2t^2(1+t^3)^frac12dt\&=3(1+t^3)^frac32big]_0^2endaligned
Made the leap from the third line to the fourth line by recognizing that $F(t)=3(1+t^3)^frac32$ is an antiderivative of $f(t)=frac272t^2(1+t^3)^frac12$.
answered 2 days ago
Matt A PeltoMatt A Pelto
2,667621
$endgroup$
add a comment |
$begingroup$
beginalignedL&=int_0^2 sqrtfrac7294t^4+frac7294t^7dt\&=int_0^2sqrtfrac7294t^4(1+t^3)dt\&=frac272int_0^2t^2(1+t^3)^frac12dt\&=3(1+t^3)^frac32big]_0^2endaligned
Made the leap from the third line to the fourth line by recognizing that $F(t)=3(1+t^3)^frac32$ is an antiderivative of $f(t)=frac272t^2(1+t^3)^frac12$.
answered 2 days ago
Matt A PeltoMatt A Pelto
2,667621
$endgroup$
beginalignedL&=int_0^2 sqrtfrac7294t^4+frac7294t^7dt\&=int_0^2sqrtfrac7294t^4(1+t^3)dt\&=frac272int_0^2t^2(1+t^3)^frac12dt\&=3(1+t^3)^frac32big]_0^2endaligned
Made the leap from the third line to the fourth line by recognizing that $F(t)=3(1+t^3)^frac32$ is an antiderivative of $f(t)=frac272t^2(1+t^3)^frac12$.
answered 2 days ago
Matt A PeltoMatt A Pelto
2,667621
edited 2 days ago
answered 2 days ago
Matt A PeltoMatt A Pelto
2,667621
answered 2 days ago
Matt A PeltoMatt A Pelto
2,667621
answered 2 days ago
Matt A PeltoMatt A Pelto
2,667621
2,667621
add a comment |
add a comment |
$begingroup$
Is this $$x=5+frac92t^3,y=4+3t^9/2$$?
$endgroup$
– Dr. Sonnhard Graubner
2 days ago