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How to draw the diamond structure using `chains`?


Reducing size of a block diagramTikz: labels above the arrows using chains library?Rotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ: Drawing an arc from an intersection to an intersectionUsing loops with chains?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themWith continue chain, how to achieve absolute node positioning?TikZ: How to draw a flow chart using library chains and matrix of nodes?













2















I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
2nd-iso-wiki



The code and the resulting figure is shown as follows.



How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



2nd-iso



documentclass[tikz]standalone
usetikzlibrarychains, scopes

begindocument
begintikzpicture[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]

[start chain = G going below] % G chain
node (g) [on chain] $G$;
node (hn) [on chain, below = 0.50cm of g] $HN$;
[start branch = H going below left] % H branch
node (h) [on chain] $H$;

[start branch = N going below right] % N branch
node [on chain] $N$;

node [on chain] ; % dummy node % continue G chain
node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] $H cap N$;
node (e) [on chain, below = 0.50cm of hcapn] $ e $;

endtikzpicture
enddocument









share|improve this question


























    2















    I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
    2nd-iso-wiki



    The code and the resulting figure is shown as follows.



    How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



    2nd-iso



    documentclass[tikz]standalone
    usetikzlibrarychains, scopes

    begindocument
    begintikzpicture[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]

    [start chain = G going below] % G chain
    node (g) [on chain] $G$;
    node (hn) [on chain, below = 0.50cm of g] $HN$;
    [start branch = H going below left] % H branch
    node (h) [on chain] $H$;

    [start branch = N going below right] % N branch
    node [on chain] $N$;

    node [on chain] ; % dummy node % continue G chain
    node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] $H cap N$;
    node (e) [on chain, below = 0.50cm of hcapn] $ e $;

    endtikzpicture
    enddocument









    share|improve this question
























      2












      2








      2








      I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
      2nd-iso-wiki



      The code and the resulting figure is shown as follows.



      How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



      2nd-iso



      documentclass[tikz]standalone
      usetikzlibrarychains, scopes

      begindocument
      begintikzpicture[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]

      [start chain = G going below] % G chain
      node (g) [on chain] $G$;
      node (hn) [on chain, below = 0.50cm of g] $HN$;
      [start branch = H going below left] % H branch
      node (h) [on chain] $H$;

      [start branch = N going below right] % N branch
      node [on chain] $N$;

      node [on chain] ; % dummy node % continue G chain
      node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] $H cap N$;
      node (e) [on chain, below = 0.50cm of hcapn] $ e $;

      endtikzpicture
      enddocument









      share|improve this question














      I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
      2nd-iso-wiki



      The code and the resulting figure is shown as follows.



      How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



      2nd-iso



      documentclass[tikz]standalone
      usetikzlibrarychains, scopes

      begindocument
      begintikzpicture[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]

      [start chain = G going below] % G chain
      node (g) [on chain] $G$;
      node (hn) [on chain, below = 0.50cm of g] $HN$;
      [start branch = H going below left] % H branch
      node (h) [on chain] $H$;

      [start branch = N going below right] % N branch
      node [on chain] $N$;

      node [on chain] ; % dummy node % continue G chain
      node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] $H cap N$;
      node (e) [on chain, below = 0.50cm of hcapn] $ e $;

      endtikzpicture
      enddocument






      tikz-pgf tikz-chains






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 2 days ago









      hengxinhengxin

      1,0282926




      1,0282926




















          2 Answers
          2






          active

          oldest

          votes


















          3














          with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



          documentclass[tikz, margin=3mm]standalone
          usetikzlibrarychains, positioning, shapes.geometric
          makeatletter
          tikzsetsuspend join/.code=deftikz@after@path
          makeatother

          begindocument
          begintikzpicture[
          node distance = 8mm and 10 mm,
          start chain = going below,
          N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
          node (g) [N] $G$;
          node (hn) [N] $HN$;
          node (h) [N, below left=of hn] $H$;
          node (hcapn) [N, below=of h -| hn] $H cap N$;
          node (e) [N] $ e $;
          %
          node (n) [N,suspend join,
          below right=of hn] $N$;
          node [below=of hn] $cong$;
          draw (hn) -- (n) (n) -- (hcapn);
          endtikzpicture
          enddocument


          enter image description here






          share|improve this answer

























          • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

            – marmot
            2 days ago












          • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

            – Zarko
            2 days ago











          • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

            – marmot
            yesterday











          • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

            – Zarko
            yesterday


















          5














          If you want to replicate the linked picture, I propose this



          documentclass[tikz]standalone
          usetikzlibraryshapes,fit
          usepackagemathptmx
          begindocument
          begintikzpicture[x=1.75cm,y=1.75cm]
          beginscope[every node/.style=draw,circle,minimum size=1cm]
          node (g) at (0,2) $G$;
          node (sn) at (0,1) $SN$;
          node (n) at (-1,0) $N$;
          node (s) at (1,0) $S$;
          node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
          node (e) at (0,-2) $e$;
          endscope
          draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
          node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
          node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
          node $cong$;
          endtikzpicture
          enddocument


          enter image description here






          share|improve this answer























            Your Answer








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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]standalone
            usetikzlibrarychains, positioning, shapes.geometric
            makeatletter
            tikzsetsuspend join/.code=deftikz@after@path
            makeatother

            begindocument
            begintikzpicture[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
            node (g) [N] $G$;
            node (hn) [N] $HN$;
            node (h) [N, below left=of hn] $H$;
            node (hcapn) [N, below=of h -| hn] $H cap N$;
            node (e) [N] $ e $;
            %
            node (n) [N,suspend join,
            below right=of hn] $N$;
            node [below=of hn] $cong$;
            draw (hn) -- (n) (n) -- (hcapn);
            endtikzpicture
            enddocument


            enter image description here






            share|improve this answer

























            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              2 days ago












            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              2 days ago











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              yesterday











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              yesterday















            3














            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]standalone
            usetikzlibrarychains, positioning, shapes.geometric
            makeatletter
            tikzsetsuspend join/.code=deftikz@after@path
            makeatother

            begindocument
            begintikzpicture[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
            node (g) [N] $G$;
            node (hn) [N] $HN$;
            node (h) [N, below left=of hn] $H$;
            node (hcapn) [N, below=of h -| hn] $H cap N$;
            node (e) [N] $ e $;
            %
            node (n) [N,suspend join,
            below right=of hn] $N$;
            node [below=of hn] $cong$;
            draw (hn) -- (n) (n) -- (hcapn);
            endtikzpicture
            enddocument


            enter image description here






            share|improve this answer

























            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              2 days ago












            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              2 days ago











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              yesterday











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              yesterday













            3












            3








            3







            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]standalone
            usetikzlibrarychains, positioning, shapes.geometric
            makeatletter
            tikzsetsuspend join/.code=deftikz@after@path
            makeatother

            begindocument
            begintikzpicture[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
            node (g) [N] $G$;
            node (hn) [N] $HN$;
            node (h) [N, below left=of hn] $H$;
            node (hcapn) [N, below=of h -| hn] $H cap N$;
            node (e) [N] $ e $;
            %
            node (n) [N,suspend join,
            below right=of hn] $N$;
            node [below=of hn] $cong$;
            draw (hn) -- (n) (n) -- (hcapn);
            endtikzpicture
            enddocument


            enter image description here






            share|improve this answer















            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]standalone
            usetikzlibrarychains, positioning, shapes.geometric
            makeatletter
            tikzsetsuspend join/.code=deftikz@after@path
            makeatother

            begindocument
            begintikzpicture[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
            node (g) [N] $G$;
            node (hn) [N] $HN$;
            node (h) [N, below left=of hn] $H$;
            node (hcapn) [N, below=of h -| hn] $H cap N$;
            node (e) [N] $ e $;
            %
            node (n) [N,suspend join,
            below right=of hn] $N$;
            node [below=of hn] $cong$;
            draw (hn) -- (n) (n) -- (hcapn);
            endtikzpicture
            enddocument


            enter image description here







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 2 days ago

























            answered 2 days ago









            ZarkoZarko

            129k868169




            129k868169












            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              2 days ago












            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              2 days ago











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              yesterday











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              yesterday

















            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              2 days ago












            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              2 days ago











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              yesterday











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              yesterday
















            Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

            – marmot
            2 days ago






            Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

            – marmot
            2 days ago














            i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

            – Zarko
            2 days ago





            i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

            – Zarko
            2 days ago













            What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

            – marmot
            yesterday





            What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

            – marmot
            yesterday













            @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

            – Zarko
            yesterday





            @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

            – Zarko
            yesterday











            5














            If you want to replicate the linked picture, I propose this



            documentclass[tikz]standalone
            usetikzlibraryshapes,fit
            usepackagemathptmx
            begindocument
            begintikzpicture[x=1.75cm,y=1.75cm]
            beginscope[every node/.style=draw,circle,minimum size=1cm]
            node (g) at (0,2) $G$;
            node (sn) at (0,1) $SN$;
            node (n) at (-1,0) $N$;
            node (s) at (1,0) $S$;
            node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
            node (e) at (0,-2) $e$;
            endscope
            draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
            node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
            node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
            node $cong$;
            endtikzpicture
            enddocument


            enter image description here






            share|improve this answer



























              5














              If you want to replicate the linked picture, I propose this



              documentclass[tikz]standalone
              usetikzlibraryshapes,fit
              usepackagemathptmx
              begindocument
              begintikzpicture[x=1.75cm,y=1.75cm]
              beginscope[every node/.style=draw,circle,minimum size=1cm]
              node (g) at (0,2) $G$;
              node (sn) at (0,1) $SN$;
              node (n) at (-1,0) $N$;
              node (s) at (1,0) $S$;
              node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
              node (e) at (0,-2) $e$;
              endscope
              draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
              node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
              node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
              node $cong$;
              endtikzpicture
              enddocument


              enter image description here






              share|improve this answer

























                5












                5








                5







                If you want to replicate the linked picture, I propose this



                documentclass[tikz]standalone
                usetikzlibraryshapes,fit
                usepackagemathptmx
                begindocument
                begintikzpicture[x=1.75cm,y=1.75cm]
                beginscope[every node/.style=draw,circle,minimum size=1cm]
                node (g) at (0,2) $G$;
                node (sn) at (0,1) $SN$;
                node (n) at (-1,0) $N$;
                node (s) at (1,0) $S$;
                node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
                node (e) at (0,-2) $e$;
                endscope
                draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
                node $cong$;
                endtikzpicture
                enddocument


                enter image description here






                share|improve this answer













                If you want to replicate the linked picture, I propose this



                documentclass[tikz]standalone
                usetikzlibraryshapes,fit
                usepackagemathptmx
                begindocument
                begintikzpicture[x=1.75cm,y=1.75cm]
                beginscope[every node/.style=draw,circle,minimum size=1cm]
                node (g) at (0,2) $G$;
                node (sn) at (0,1) $SN$;
                node (n) at (-1,0) $N$;
                node (s) at (1,0) $S$;
                node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
                node (e) at (0,-2) $e$;
                endscope
                draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
                node $cong$;
                endtikzpicture
                enddocument


                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 2 days ago









                JouleVJouleV

                9,91322558




                9,91322558



























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