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How to draw the diamond structure using `chains`?
Reducing size of a block diagramTikz: labels above the arrows using chains library?Rotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ: Drawing an arc from an intersection to an intersectionUsing loops with chains?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themWith continue chain, how to achieve absolute node positioning?TikZ: How to draw a flow chart using library chains and matrix of nodes?
I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
The code and the resulting figure is shown as follows.
How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?

documentclass[tikz]standalone
usetikzlibrarychains, scopes
begindocument
begintikzpicture[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
[start chain = G going below] % G chain
node (g) [on chain] $G$;
node (hn) [on chain, below = 0.50cm of g] $HN$;
[start branch = H going below left] % H branch
node (h) [on chain] $H$;
[start branch = N going below right] % N branch
node [on chain] $N$;
node [on chain] ; % dummy node % continue G chain
node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] $H cap N$;
node (e) [on chain, below = 0.50cm of hcapn] $ e $;
endtikzpicture
enddocument
tikz-pgf tikz-chains
add a comment |
I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
The code and the resulting figure is shown as follows.
How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?

documentclass[tikz]standalone
usetikzlibrarychains, scopes
begindocument
begintikzpicture[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
[start chain = G going below] % G chain
node (g) [on chain] $G$;
node (hn) [on chain, below = 0.50cm of g] $HN$;
[start branch = H going below left] % H branch
node (h) [on chain] $H$;
[start branch = N going below right] % N branch
node [on chain] $N$;
node [on chain] ; % dummy node % continue G chain
node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] $H cap N$;
node (e) [on chain, below = 0.50cm of hcapn] $ e $;
endtikzpicture
enddocument
tikz-pgf tikz-chains
add a comment |
I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
The code and the resulting figure is shown as follows.
How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?

documentclass[tikz]standalone
usetikzlibrarychains, scopes
begindocument
begintikzpicture[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
[start chain = G going below] % G chain
node (g) [on chain] $G$;
node (hn) [on chain, below = 0.50cm of g] $HN$;
[start branch = H going below left] % H branch
node (h) [on chain] $H$;
[start branch = N going below right] % N branch
node [on chain] $N$;
node [on chain] ; % dummy node % continue G chain
node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] $H cap N$;
node (e) [on chain, below = 0.50cm of hcapn] $ e $;
endtikzpicture
enddocument
tikz-pgf tikz-chains
I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
The code and the resulting figure is shown as follows.
How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?

documentclass[tikz]standalone
usetikzlibrarychains, scopes
begindocument
begintikzpicture[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
[start chain = G going below] % G chain
node (g) [on chain] $G$;
node (hn) [on chain, below = 0.50cm of g] $HN$;
[start branch = H going below left] % H branch
node (h) [on chain] $H$;
[start branch = N going below right] % N branch
node [on chain] $N$;
node [on chain] ; % dummy node % continue G chain
node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] $H cap N$;
node (e) [on chain, below = 0.50cm of hcapn] $ e $;
endtikzpicture
enddocument
tikz-pgf tikz-chains
tikz-pgf tikz-chains
asked 2 days ago
hengxinhengxin
1,0282926
1,0282926
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:
documentclass[tikz, margin=3mm]standalone
usetikzlibrarychains, positioning, shapes.geometric
makeatletter
tikzsetsuspend join/.code=deftikz@after@path
makeatother
begindocument
begintikzpicture[
node distance = 8mm and 10 mm,
start chain = going below,
N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
node (g) [N] $G$;
node (hn) [N] $HN$;
node (h) [N, below left=of hn] $H$;
node (hcapn) [N, below=of h -| hn] $H cap N$;
node (e) [N] $ e $;
%
node (n) [N,suspend join,
below right=of hn] $N$;
node [below=of hn] $cong$;
draw (hn) -- (n) (n) -- (hcapn);
endtikzpicture
enddocument

Why is it that an identical definition ofsuspend joincan be found e.g. in Heiko Oberdiek's answer?
– marmot
2 days ago
i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?
– Zarko
2 days ago
What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?
– marmot
yesterday
@marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!
– Zarko
yesterday
add a comment |
If you want to replicate the linked picture, I propose this
documentclass[tikz]standalone
usetikzlibraryshapes,fit
usepackagemathptmx
begindocument
begintikzpicture[x=1.75cm,y=1.75cm]
beginscope[every node/.style=draw,circle,minimum size=1cm]
node (g) at (0,2) $G$;
node (sn) at (0,1) $SN$;
node (n) at (-1,0) $N$;
node (s) at (1,0) $S$;
node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
node (e) at (0,-2) $e$;
endscope
draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
node $cong$;
endtikzpicture
enddocument

add a comment |
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2 Answers
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with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:
documentclass[tikz, margin=3mm]standalone
usetikzlibrarychains, positioning, shapes.geometric
makeatletter
tikzsetsuspend join/.code=deftikz@after@path
makeatother
begindocument
begintikzpicture[
node distance = 8mm and 10 mm,
start chain = going below,
N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
node (g) [N] $G$;
node (hn) [N] $HN$;
node (h) [N, below left=of hn] $H$;
node (hcapn) [N, below=of h -| hn] $H cap N$;
node (e) [N] $ e $;
%
node (n) [N,suspend join,
below right=of hn] $N$;
node [below=of hn] $cong$;
draw (hn) -- (n) (n) -- (hcapn);
endtikzpicture
enddocument

Why is it that an identical definition ofsuspend joincan be found e.g. in Heiko Oberdiek's answer?
– marmot
2 days ago
i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?
– Zarko
2 days ago
What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?
– marmot
yesterday
@marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!
– Zarko
yesterday
add a comment |
with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:
documentclass[tikz, margin=3mm]standalone
usetikzlibrarychains, positioning, shapes.geometric
makeatletter
tikzsetsuspend join/.code=deftikz@after@path
makeatother
begindocument
begintikzpicture[
node distance = 8mm and 10 mm,
start chain = going below,
N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
node (g) [N] $G$;
node (hn) [N] $HN$;
node (h) [N, below left=of hn] $H$;
node (hcapn) [N, below=of h -| hn] $H cap N$;
node (e) [N] $ e $;
%
node (n) [N,suspend join,
below right=of hn] $N$;
node [below=of hn] $cong$;
draw (hn) -- (n) (n) -- (hcapn);
endtikzpicture
enddocument

Why is it that an identical definition ofsuspend joincan be found e.g. in Heiko Oberdiek's answer?
– marmot
2 days ago
i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?
– Zarko
2 days ago
What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?
– marmot
yesterday
@marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!
– Zarko
yesterday
add a comment |
with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:
documentclass[tikz, margin=3mm]standalone
usetikzlibrarychains, positioning, shapes.geometric
makeatletter
tikzsetsuspend join/.code=deftikz@after@path
makeatother
begindocument
begintikzpicture[
node distance = 8mm and 10 mm,
start chain = going below,
N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
node (g) [N] $G$;
node (hn) [N] $HN$;
node (h) [N, below left=of hn] $H$;
node (hcapn) [N, below=of h -| hn] $H cap N$;
node (e) [N] $ e $;
%
node (n) [N,suspend join,
below right=of hn] $N$;
node [below=of hn] $cong$;
draw (hn) -- (n) (n) -- (hcapn);
endtikzpicture
enddocument

with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:
documentclass[tikz, margin=3mm]standalone
usetikzlibrarychains, positioning, shapes.geometric
makeatletter
tikzsetsuspend join/.code=deftikz@after@path
makeatother
begindocument
begintikzpicture[
node distance = 8mm and 10 mm,
start chain = going below,
N/.style = ellipse, draw, inner sep=2pt, on chain, join=by -]
node (g) [N] $G$;
node (hn) [N] $HN$;
node (h) [N, below left=of hn] $H$;
node (hcapn) [N, below=of h -| hn] $H cap N$;
node (e) [N] $ e $;
%
node (n) [N,suspend join,
below right=of hn] $N$;
node [below=of hn] $cong$;
draw (hn) -- (n) (n) -- (hcapn);
endtikzpicture
enddocument

edited 2 days ago
answered 2 days ago
ZarkoZarko
129k868169
129k868169
Why is it that an identical definition ofsuspend joincan be found e.g. in Heiko Oberdiek's answer?
– marmot
2 days ago
i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?
– Zarko
2 days ago
What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?
– marmot
yesterday
@marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!
– Zarko
yesterday
add a comment |
Why is it that an identical definition ofsuspend joincan be found e.g. in Heiko Oberdiek's answer?
– marmot
2 days ago
i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?
– Zarko
2 days ago
What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?
– marmot
yesterday
@marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!
– Zarko
yesterday
Why is it that an identical definition of
suspend join can be found e.g. in Heiko Oberdiek's answer?– marmot
2 days ago
Why is it that an identical definition of
suspend join can be found e.g. in Heiko Oberdiek's answer?– marmot
2 days ago
i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?
– Zarko
2 days ago
i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?
– Zarko
2 days ago
What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?
– marmot
yesterday
What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?
– marmot
yesterday
@marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!
– Zarko
yesterday
@marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!
– Zarko
yesterday
add a comment |
If you want to replicate the linked picture, I propose this
documentclass[tikz]standalone
usetikzlibraryshapes,fit
usepackagemathptmx
begindocument
begintikzpicture[x=1.75cm,y=1.75cm]
beginscope[every node/.style=draw,circle,minimum size=1cm]
node (g) at (0,2) $G$;
node (sn) at (0,1) $SN$;
node (n) at (-1,0) $N$;
node (s) at (1,0) $S$;
node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
node (e) at (0,-2) $e$;
endscope
draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
node $cong$;
endtikzpicture
enddocument

add a comment |
If you want to replicate the linked picture, I propose this
documentclass[tikz]standalone
usetikzlibraryshapes,fit
usepackagemathptmx
begindocument
begintikzpicture[x=1.75cm,y=1.75cm]
beginscope[every node/.style=draw,circle,minimum size=1cm]
node (g) at (0,2) $G$;
node (sn) at (0,1) $SN$;
node (n) at (-1,0) $N$;
node (s) at (1,0) $S$;
node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
node (e) at (0,-2) $e$;
endscope
draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
node $cong$;
endtikzpicture
enddocument

add a comment |
If you want to replicate the linked picture, I propose this
documentclass[tikz]standalone
usetikzlibraryshapes,fit
usepackagemathptmx
begindocument
begintikzpicture[x=1.75cm,y=1.75cm]
beginscope[every node/.style=draw,circle,minimum size=1cm]
node (g) at (0,2) $G$;
node (sn) at (0,1) $SN$;
node (n) at (-1,0) $N$;
node (s) at (1,0) $S$;
node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
node (e) at (0,-2) $e$;
endscope
draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
node $cong$;
endtikzpicture
enddocument

If you want to replicate the linked picture, I propose this
documentclass[tikz]standalone
usetikzlibraryshapes,fit
usepackagemathptmx
begindocument
begintikzpicture[x=1.75cm,y=1.75cm]
beginscope[every node/.style=draw,circle,minimum size=1cm]
node (g) at (0,2) $G$;
node (sn) at (0,1) $SN$;
node (n) at (-1,0) $N$;
node (s) at (1,0) $S$;
node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) $Scap N$;
node (e) at (0,-2) $e$;
endscope
draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] ;
node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] ;
node $cong$;
endtikzpicture
enddocument

answered 2 days ago
JouleVJouleV
9,91322558
9,91322558
add a comment |
add a comment |
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Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown