Sulfuric acid symmetry point groupAre all cubic point groups encountered?Why does benzene have a D6h point group?Does an axis of symmetry determine chiralty?Identifying the C3, C4, S4, and S6 symmetry operations in the Oh point groupSymmetry and SALC: choosing coordinate basisWhat is the symmetry of the cuboctahedron (FCC metal)?High Degrees of Symmetry in MoleculesIs there a possible distortion of XeF6 from Oh point group to reduced symmetry?What is the Crystal System of MoS2?Relationship between the symmetry number of a molecule as used in rotational spectroscopy and point group
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Sulfuric acid symmetry point group
Are all cubic point groups encountered?Why does benzene have a D6h point group?Does an axis of symmetry determine chiralty?Identifying the C3, C4, S4, and S6 symmetry operations in the Oh point groupSymmetry and SALC: choosing coordinate basisWhat is the symmetry of the cuboctahedron (FCC metal)?High Degrees of Symmetry in MoleculesIs there a possible distortion of XeF6 from Oh point group to reduced symmetry?What is the Crystal System of MoS2?Relationship between the symmetry number of a molecule as used in rotational spectroscopy and point group
$begingroup$
On the following page: https://cccbdb.nist.gov/pglist.asp It appears that the point symmetry group of sulphuric acid is $C_2$. I know that $C_2$ means that there is an axis of symmetry of order 2 (180 degree rotation).
But, I am not able to visualize it in the molecule.
crystal-structure symmetry crystallography
edited 2 days ago
andselisk
18.9k660125
asked 2 days ago
aprendiendo-a-programaraprendiendo-a-programar
364
$endgroup$
add a comment |
$begingroup$
On the following page: https://cccbdb.nist.gov/pglist.asp It appears that the point symmetry group of sulphuric acid is $C_2$. I know that $C_2$ means that there is an axis of symmetry of order 2 (180 degree rotation).
But, I am not able to visualize it in the molecule.
crystal-structure symmetry crystallography
edited 2 days ago
andselisk
18.9k660125
asked 2 days ago
aprendiendo-a-programaraprendiendo-a-programar
364
$endgroup$
add a comment |
$begingroup$
On the following page: https://cccbdb.nist.gov/pglist.asp It appears that the point symmetry group of sulphuric acid is $C_2$. I know that $C_2$ means that there is an axis of symmetry of order 2 (180 degree rotation).
But, I am not able to visualize it in the molecule.
crystal-structure symmetry crystallography
edited 2 days ago
andselisk
18.9k660125
asked 2 days ago
aprendiendo-a-programaraprendiendo-a-programar
364
$endgroup$
On the following page: https://cccbdb.nist.gov/pglist.asp It appears that the point symmetry group of sulphuric acid is $C_2$. I know that $C_2$ means that there is an axis of symmetry of order 2 (180 degree rotation).
But, I am not able to visualize it in the molecule.
crystal-structure symmetry crystallography
crystal-structure symmetry crystallography
edited 2 days ago
andselisk
18.9k660125
asked 2 days ago
aprendiendo-a-programaraprendiendo-a-programar
364
edited 2 days ago
andselisk
18.9k660125
asked 2 days ago
aprendiendo-a-programaraprendiendo-a-programar
364
edited 2 days ago
andselisk
18.9k660125
edited 2 days ago
andselisk
18.9k660125
edited 2 days ago
andselisk
18.9k660125
18.9k660125
asked 2 days ago
aprendiendo-a-programaraprendiendo-a-programar
364
asked 2 days ago
aprendiendo-a-programaraprendiendo-a-programar
364
asked 2 days ago
aprendiendo-a-programaraprendiendo-a-programar
364
364
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
In fact, you can see $C_2$ and other symmetry elements for yourself in 3D by opening the CIF [1, COD-2005680] with Mercury (free, available for Windows, Linux, MacOS):
Figure 1.
Unit cell of crystalline sulfuric acid $ceH2SO4$.
Green lines parallel to crystallographic axis $b$ depict $C_2$ rotation axes.
This can be achieved by drawing the unit cell content with Calculate → Packing/Slicing… and adding symmetry elements of interest via Display → Symmetry Elements….
Figure 2.
Single molecular unit $ceH2SO4$ in two projections with the $C_2$ placed in drawing plane (left) and perpendicular to drawing plane (right).
References
- Kemnitz, E.; Werner, C.; Trojanov, S. Reinvestigation of Crystalline Sulfuric Acid and Oxonium Hydrogensulfate. Acta Crystallographica Section C Crystal Structure Communications 1996, 52 (11), 2665–2668. https://doi.org/10.1107/S0108270196006749.
answered 2 days ago
andseliskandselisk
18.9k660125
$endgroup$
$begingroup$
How I can a draw the molecule on Mercury? @andseliskç
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar I updated the answer with the link to CIF, which you can open with Mercury. This is an experimentally determined structure which you are not supposed to "draw" yourself.
$endgroup$
– andselisk
2 days ago
$begingroup$
I do everything you tell me and I don't get what you get.
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar What exactly you are experiencing problems with?
$endgroup$
– andselisk
2 days ago
$begingroup$
First of all, it is still not clear to me where I can find more molecules (such as water, benzene, ammonia,...). Also, once I open the sulphuric acid file in Mercury and pulse the "Packing/..." command I don't get the same thing that you hung in your answer. And, if I add the symmetry, numerous planes and lines appear, nothing to do with what you put.
$endgroup$
– aprendiendo-a-programar
2 days ago
|
show 7 more comments
$begingroup$
In the structure as drawn here, the axis is perpenducular to the plane of the paper passing through the sulfur atom.
answered 2 days ago
Oscar LanziOscar Lanzi
15.9k12648
$endgroup$
$begingroup$
But, if I turn around that axis, every 180 degrees the molecule would not be as it was initially. @Oscar Lanzi
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
Which atoms would be out of place? Look again... .
$endgroup$
– Oscar Lanzi
2 days ago
add a comment |
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2 Answers
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2 Answers
2
active
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votes
$begingroup$
In fact, you can see $C_2$ and other symmetry elements for yourself in 3D by opening the CIF [1, COD-2005680] with Mercury (free, available for Windows, Linux, MacOS):
Figure 1.
Unit cell of crystalline sulfuric acid $ceH2SO4$.
Green lines parallel to crystallographic axis $b$ depict $C_2$ rotation axes.
This can be achieved by drawing the unit cell content with Calculate → Packing/Slicing… and adding symmetry elements of interest via Display → Symmetry Elements….
Figure 2.
Single molecular unit $ceH2SO4$ in two projections with the $C_2$ placed in drawing plane (left) and perpendicular to drawing plane (right).
References
- Kemnitz, E.; Werner, C.; Trojanov, S. Reinvestigation of Crystalline Sulfuric Acid and Oxonium Hydrogensulfate. Acta Crystallographica Section C Crystal Structure Communications 1996, 52 (11), 2665–2668. https://doi.org/10.1107/S0108270196006749.
answered 2 days ago
andseliskandselisk
18.9k660125
$endgroup$
$begingroup$
How I can a draw the molecule on Mercury? @andseliskç
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar I updated the answer with the link to CIF, which you can open with Mercury. This is an experimentally determined structure which you are not supposed to "draw" yourself.
$endgroup$
– andselisk
2 days ago
$begingroup$
I do everything you tell me and I don't get what you get.
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar What exactly you are experiencing problems with?
$endgroup$
– andselisk
2 days ago
$begingroup$
First of all, it is still not clear to me where I can find more molecules (such as water, benzene, ammonia,...). Also, once I open the sulphuric acid file in Mercury and pulse the "Packing/..." command I don't get the same thing that you hung in your answer. And, if I add the symmetry, numerous planes and lines appear, nothing to do with what you put.
$endgroup$
– aprendiendo-a-programar
2 days ago
|
show 7 more comments
$begingroup$
In fact, you can see $C_2$ and other symmetry elements for yourself in 3D by opening the CIF [1, COD-2005680] with Mercury (free, available for Windows, Linux, MacOS):
Figure 1.
Unit cell of crystalline sulfuric acid $ceH2SO4$.
Green lines parallel to crystallographic axis $b$ depict $C_2$ rotation axes.
This can be achieved by drawing the unit cell content with Calculate → Packing/Slicing… and adding symmetry elements of interest via Display → Symmetry Elements….
Figure 2.
Single molecular unit $ceH2SO4$ in two projections with the $C_2$ placed in drawing plane (left) and perpendicular to drawing plane (right).
References
- Kemnitz, E.; Werner, C.; Trojanov, S. Reinvestigation of Crystalline Sulfuric Acid and Oxonium Hydrogensulfate. Acta Crystallographica Section C Crystal Structure Communications 1996, 52 (11), 2665–2668. https://doi.org/10.1107/S0108270196006749.
answered 2 days ago
andseliskandselisk
18.9k660125
$endgroup$
$begingroup$
How I can a draw the molecule on Mercury? @andseliskç
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar I updated the answer with the link to CIF, which you can open with Mercury. This is an experimentally determined structure which you are not supposed to "draw" yourself.
$endgroup$
– andselisk
2 days ago
$begingroup$
I do everything you tell me and I don't get what you get.
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar What exactly you are experiencing problems with?
$endgroup$
– andselisk
2 days ago
$begingroup$
First of all, it is still not clear to me where I can find more molecules (such as water, benzene, ammonia,...). Also, once I open the sulphuric acid file in Mercury and pulse the "Packing/..." command I don't get the same thing that you hung in your answer. And, if I add the symmetry, numerous planes and lines appear, nothing to do with what you put.
$endgroup$
– aprendiendo-a-programar
2 days ago
|
show 7 more comments
$begingroup$
In fact, you can see $C_2$ and other symmetry elements for yourself in 3D by opening the CIF [1, COD-2005680] with Mercury (free, available for Windows, Linux, MacOS):
Figure 1.
Unit cell of crystalline sulfuric acid $ceH2SO4$.
Green lines parallel to crystallographic axis $b$ depict $C_2$ rotation axes.
This can be achieved by drawing the unit cell content with Calculate → Packing/Slicing… and adding symmetry elements of interest via Display → Symmetry Elements….
Figure 2.
Single molecular unit $ceH2SO4$ in two projections with the $C_2$ placed in drawing plane (left) and perpendicular to drawing plane (right).
References
- Kemnitz, E.; Werner, C.; Trojanov, S. Reinvestigation of Crystalline Sulfuric Acid and Oxonium Hydrogensulfate. Acta Crystallographica Section C Crystal Structure Communications 1996, 52 (11), 2665–2668. https://doi.org/10.1107/S0108270196006749.
answered 2 days ago
andseliskandselisk
18.9k660125
$endgroup$
In fact, you can see $C_2$ and other symmetry elements for yourself in 3D by opening the CIF [1, COD-2005680] with Mercury (free, available for Windows, Linux, MacOS):
Figure 1.
Unit cell of crystalline sulfuric acid $ceH2SO4$.
Green lines parallel to crystallographic axis $b$ depict $C_2$ rotation axes.
This can be achieved by drawing the unit cell content with Calculate → Packing/Slicing… and adding symmetry elements of interest via Display → Symmetry Elements….
Figure 2.
Single molecular unit $ceH2SO4$ in two projections with the $C_2$ placed in drawing plane (left) and perpendicular to drawing plane (right).
References
- Kemnitz, E.; Werner, C.; Trojanov, S. Reinvestigation of Crystalline Sulfuric Acid and Oxonium Hydrogensulfate. Acta Crystallographica Section C Crystal Structure Communications 1996, 52 (11), 2665–2668. https://doi.org/10.1107/S0108270196006749.
answered 2 days ago
andseliskandselisk
18.9k660125
edited 2 days ago
answered 2 days ago
andseliskandselisk
18.9k660125
answered 2 days ago
andseliskandselisk
18.9k660125
answered 2 days ago
andseliskandselisk
18.9k660125
18.9k660125
$begingroup$
How I can a draw the molecule on Mercury? @andseliskç
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar I updated the answer with the link to CIF, which you can open with Mercury. This is an experimentally determined structure which you are not supposed to "draw" yourself.
$endgroup$
– andselisk
2 days ago
$begingroup$
I do everything you tell me and I don't get what you get.
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar What exactly you are experiencing problems with?
$endgroup$
– andselisk
2 days ago
$begingroup$
First of all, it is still not clear to me where I can find more molecules (such as water, benzene, ammonia,...). Also, once I open the sulphuric acid file in Mercury and pulse the "Packing/..." command I don't get the same thing that you hung in your answer. And, if I add the symmetry, numerous planes and lines appear, nothing to do with what you put.
$endgroup$
– aprendiendo-a-programar
2 days ago
|
show 7 more comments
$begingroup$
How I can a draw the molecule on Mercury? @andseliskç
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar I updated the answer with the link to CIF, which you can open with Mercury. This is an experimentally determined structure which you are not supposed to "draw" yourself.
$endgroup$
– andselisk
2 days ago
$begingroup$
I do everything you tell me and I don't get what you get.
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar What exactly you are experiencing problems with?
$endgroup$
– andselisk
2 days ago
$begingroup$
First of all, it is still not clear to me where I can find more molecules (such as water, benzene, ammonia,...). Also, once I open the sulphuric acid file in Mercury and pulse the "Packing/..." command I don't get the same thing that you hung in your answer. And, if I add the symmetry, numerous planes and lines appear, nothing to do with what you put.
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
How I can a draw the molecule on Mercury? @andseliskç
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
How I can a draw the molecule on Mercury? @andseliskç
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar I updated the answer with the link to CIF, which you can open with Mercury. This is an experimentally determined structure which you are not supposed to "draw" yourself.
$endgroup$
– andselisk
2 days ago
$begingroup$
@aprendiendo-a-programar I updated the answer with the link to CIF, which you can open with Mercury. This is an experimentally determined structure which you are not supposed to "draw" yourself.
$endgroup$
– andselisk
2 days ago
$begingroup$
I do everything you tell me and I don't get what you get.
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
I do everything you tell me and I don't get what you get.
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
@aprendiendo-a-programar What exactly you are experiencing problems with?
$endgroup$
– andselisk
2 days ago
$begingroup$
@aprendiendo-a-programar What exactly you are experiencing problems with?
$endgroup$
– andselisk
2 days ago
$begingroup$
First of all, it is still not clear to me where I can find more molecules (such as water, benzene, ammonia,...). Also, once I open the sulphuric acid file in Mercury and pulse the "Packing/..." command I don't get the same thing that you hung in your answer. And, if I add the symmetry, numerous planes and lines appear, nothing to do with what you put.
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
First of all, it is still not clear to me where I can find more molecules (such as water, benzene, ammonia,...). Also, once I open the sulphuric acid file in Mercury and pulse the "Packing/..." command I don't get the same thing that you hung in your answer. And, if I add the symmetry, numerous planes and lines appear, nothing to do with what you put.
$endgroup$
– aprendiendo-a-programar
2 days ago
|
show 7 more comments
$begingroup$
In the structure as drawn here, the axis is perpenducular to the plane of the paper passing through the sulfur atom.
answered 2 days ago
Oscar LanziOscar Lanzi
15.9k12648
$endgroup$
$begingroup$
But, if I turn around that axis, every 180 degrees the molecule would not be as it was initially. @Oscar Lanzi
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
Which atoms would be out of place? Look again... .
$endgroup$
– Oscar Lanzi
2 days ago
add a comment |
$begingroup$
In the structure as drawn here, the axis is perpenducular to the plane of the paper passing through the sulfur atom.
answered 2 days ago
Oscar LanziOscar Lanzi
15.9k12648
$endgroup$
$begingroup$
But, if I turn around that axis, every 180 degrees the molecule would not be as it was initially. @Oscar Lanzi
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
Which atoms would be out of place? Look again... .
$endgroup$
– Oscar Lanzi
2 days ago
add a comment |
$begingroup$
In the structure as drawn here, the axis is perpenducular to the plane of the paper passing through the sulfur atom.
answered 2 days ago
Oscar LanziOscar Lanzi
15.9k12648
$endgroup$
In the structure as drawn here, the axis is perpenducular to the plane of the paper passing through the sulfur atom.
answered 2 days ago
Oscar LanziOscar Lanzi
15.9k12648
answered 2 days ago
Oscar LanziOscar Lanzi
15.9k12648
answered 2 days ago
Oscar LanziOscar Lanzi
15.9k12648
answered 2 days ago
Oscar LanziOscar Lanzi
15.9k12648
15.9k12648
$begingroup$
But, if I turn around that axis, every 180 degrees the molecule would not be as it was initially. @Oscar Lanzi
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
Which atoms would be out of place? Look again... .
$endgroup$
– Oscar Lanzi
2 days ago
add a comment |
$begingroup$
But, if I turn around that axis, every 180 degrees the molecule would not be as it was initially. @Oscar Lanzi
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
Which atoms would be out of place? Look again... .
$endgroup$
– Oscar Lanzi
2 days ago
$begingroup$
But, if I turn around that axis, every 180 degrees the molecule would not be as it was initially. @Oscar Lanzi
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
But, if I turn around that axis, every 180 degrees the molecule would not be as it was initially. @Oscar Lanzi
$endgroup$
– aprendiendo-a-programar
2 days ago
$begingroup$
Which atoms would be out of place? Look again... .
$endgroup$
– Oscar Lanzi
2 days ago
$begingroup$
Which atoms would be out of place? Look again... .
$endgroup$
– Oscar Lanzi
2 days ago
add a comment |
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