Update Cursor skipping last row? Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Create Python script to update field based on change in another field ArcGISUpdateCursor only takes last value of SearchCursorWhy is Update Cursor adding Object IDs incorrectly?Calculate Row if Row Value Equals Value in ListIdentify closed polylines in ArcGIS using PythonIteratively Updating Just Bottom Row in Table using ArcPy?Comparing value with value from the next rowArcPy rollback update / insert cursors if error occursUsing cursor.next() is resetting “row in cursor” causing it to skip every other rowSwitching from Nested Search Cursors to Dictionaries

Do you forfeit tax refunds/credits if you aren't required to and don't file by April 15?

Why don't the Weasley twins use magic outside of school if the Trace can only find the location of spells cast?

Bonus calculation: Am I making a mountain out of a molehill?

What causes the vertical darker bands in my photo?

How to motivate offshore teams and trust them to deliver?

What does the "x" in "x86" represent?

If a contract sometimes uses the wrong name, is it still valid?

How do I keep my slimes from escaping their pens?

Letter Boxed validator

How much radiation do nuclear physics experiments expose researchers to nowadays?

What is this single-engine low-wing propeller plane?

What would be the ideal power source for a cybernetic eye?

Stars Make Stars

What are the pros and cons of Aerospike nosecones?

Gastric acid as a weapon

Is there any avatar supposed to be born between the death of Krishna and the birth of Kalki?

Is a manifold-with-boundary with given interior and non-empty boundary essentially unique?

Proof involving the spectral radius and the Jordan canonical form

How do I stop a creek from eroding my steep embankment?

Why does Python start at index -1 when indexing a list from the end?

Is 1 ppb equal to 1 μg/kg?

When to stop saving and start investing?

How discoverable are IPv6 addresses and AAAA names by potential attackers?

Should I discuss the type of campaign with my players?



Update Cursor skipping last row?



Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Create Python script to update field based on change in another field ArcGISUpdateCursor only takes last value of SearchCursorWhy is Update Cursor adding Object IDs incorrectly?Calculate Row if Row Value Equals Value in ListIdentify closed polylines in ArcGIS using PythonIteratively Updating Just Bottom Row in Table using ArcPy?Comparing value with value from the next rowArcPy rollback update / insert cursors if error occursUsing cursor.next() is resetting “row in cursor” causing it to skip every other rowSwitching from Nested Search Cursors to Dictionaries



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








4















I have created a python function within field calculator to calculate the time difference between a timestamp (yyyy-MM-dd HH:mm:ss) in a row and the row after (the interval field in seconds). I have used a update cursor with field calculator to do this, however I am receiving null values for both the first and last row.



The first is correctly missed due to the function being reliant on having a value set by the previous row.



I am unsure as to why the last row is being skipped?



The first row of the attribute is formatted as:



First row



The last:



Last row



I have had this issue on several other update cursor functions including those on simple single row condition statements.



Am I missing a statement to close the update cursor loop?



My code is:



import arcpy, time, datetime
from time import strftime
from datetime import timedelta, datetime
from arcpy import da

def FindTime(table,date,interval):

firstRow = True

with arcpy.da.UpdateCursor(table, ["interval", "date"]) as cursor:

for row in cursor:
gap2 = row[1]

if firstRow == True:
gap1 = gap2
firstRow = False
continue
timedelta = gap2 - gap1
row[0] = timedelta.days * 24 * 3600 + timedelta.seconds
gap1 = gap2
cursor.updateRow(row)


*Updated from below comment's solution:



import arcpy
def FindTime(fc, datefield, daydiff_field):

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break









share|improve this question



















  • 1





    There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

    – BERA
    Apr 9 at 19:23












  • Edited pasting to SE typo!

    – Will
    Apr 10 at 9:42

















4















I have created a python function within field calculator to calculate the time difference between a timestamp (yyyy-MM-dd HH:mm:ss) in a row and the row after (the interval field in seconds). I have used a update cursor with field calculator to do this, however I am receiving null values for both the first and last row.



The first is correctly missed due to the function being reliant on having a value set by the previous row.



I am unsure as to why the last row is being skipped?



The first row of the attribute is formatted as:



First row



The last:



Last row



I have had this issue on several other update cursor functions including those on simple single row condition statements.



Am I missing a statement to close the update cursor loop?



My code is:



import arcpy, time, datetime
from time import strftime
from datetime import timedelta, datetime
from arcpy import da

def FindTime(table,date,interval):

firstRow = True

with arcpy.da.UpdateCursor(table, ["interval", "date"]) as cursor:

for row in cursor:
gap2 = row[1]

if firstRow == True:
gap1 = gap2
firstRow = False
continue
timedelta = gap2 - gap1
row[0] = timedelta.days * 24 * 3600 + timedelta.seconds
gap1 = gap2
cursor.updateRow(row)


*Updated from below comment's solution:



import arcpy
def FindTime(fc, datefield, daydiff_field):

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break









share|improve this question



















  • 1





    There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

    – BERA
    Apr 9 at 19:23












  • Edited pasting to SE typo!

    – Will
    Apr 10 at 9:42













4












4








4


0






I have created a python function within field calculator to calculate the time difference between a timestamp (yyyy-MM-dd HH:mm:ss) in a row and the row after (the interval field in seconds). I have used a update cursor with field calculator to do this, however I am receiving null values for both the first and last row.



The first is correctly missed due to the function being reliant on having a value set by the previous row.



I am unsure as to why the last row is being skipped?



The first row of the attribute is formatted as:



First row



The last:



Last row



I have had this issue on several other update cursor functions including those on simple single row condition statements.



Am I missing a statement to close the update cursor loop?



My code is:



import arcpy, time, datetime
from time import strftime
from datetime import timedelta, datetime
from arcpy import da

def FindTime(table,date,interval):

firstRow = True

with arcpy.da.UpdateCursor(table, ["interval", "date"]) as cursor:

for row in cursor:
gap2 = row[1]

if firstRow == True:
gap1 = gap2
firstRow = False
continue
timedelta = gap2 - gap1
row[0] = timedelta.days * 24 * 3600 + timedelta.seconds
gap1 = gap2
cursor.updateRow(row)


*Updated from below comment's solution:



import arcpy
def FindTime(fc, datefield, daydiff_field):

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break









share|improve this question
















I have created a python function within field calculator to calculate the time difference between a timestamp (yyyy-MM-dd HH:mm:ss) in a row and the row after (the interval field in seconds). I have used a update cursor with field calculator to do this, however I am receiving null values for both the first and last row.



The first is correctly missed due to the function being reliant on having a value set by the previous row.



I am unsure as to why the last row is being skipped?



The first row of the attribute is formatted as:



First row



The last:



Last row



I have had this issue on several other update cursor functions including those on simple single row condition statements.



Am I missing a statement to close the update cursor loop?



My code is:



import arcpy, time, datetime
from time import strftime
from datetime import timedelta, datetime
from arcpy import da

def FindTime(table,date,interval):

firstRow = True

with arcpy.da.UpdateCursor(table, ["interval", "date"]) as cursor:

for row in cursor:
gap2 = row[1]

if firstRow == True:
gap1 = gap2
firstRow = False
continue
timedelta = gap2 - gap1
row[0] = timedelta.days * 24 * 3600 + timedelta.seconds
gap1 = gap2
cursor.updateRow(row)


*Updated from below comment's solution:



import arcpy
def FindTime(fc, datefield, daydiff_field):

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break






arcpy modelbuilder field-calculator cursor python-parser






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 10 at 9:15







Will

















asked Apr 9 at 8:56









WillWill

695




695







  • 1





    There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

    – BERA
    Apr 9 at 19:23












  • Edited pasting to SE typo!

    – Will
    Apr 10 at 9:42












  • 1





    There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

    – BERA
    Apr 9 at 19:23












  • Edited pasting to SE typo!

    – Will
    Apr 10 at 9:42







1




1





There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

– BERA
Apr 9 at 19:23






There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

– BERA
Apr 9 at 19:23














Edited pasting to SE typo!

– Will
Apr 10 at 9:42





Edited pasting to SE typo!

– Will
Apr 10 at 9:42










1 Answer
1






active

oldest

votes


















4














If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here






share|improve this answer




















  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54











Your Answer








StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "79"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fgis.stackexchange.com%2fquestions%2f318213%2fupdate-cursor-skipping-last-row%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here






share|improve this answer




















  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54















4














If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here






share|improve this answer




















  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54













4












4








4







If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here






share|improve this answer















If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Apr 9 at 13:08

























answered Apr 9 at 9:34









BERABERA

17.2k62044




17.2k62044







  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54












  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54







3




3





This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

– Hornbydd
Apr 9 at 10:29





This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

– Hornbydd
Apr 9 at 10:29




3




3





Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

– BERA
Apr 9 at 10:31





Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

– BERA
Apr 9 at 10:31




2




2





If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

– Berend
Apr 9 at 12:52





If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

– Berend
Apr 9 at 12:52




1




1





Slower than what approach?

– BERA
Apr 9 at 12:54





Slower than what approach?

– BERA
Apr 9 at 12:54




1




1





Slower than using just an update cursor, as OP does

– Berend
Apr 9 at 12:54





Slower than using just an update cursor, as OP does

– Berend
Apr 9 at 12:54

















draft saved

draft discarded
















































Thanks for contributing an answer to Geographic Information Systems Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fgis.stackexchange.com%2fquestions%2f318213%2fupdate-cursor-skipping-last-row%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

រឿង រ៉ូមេអូ និង ហ្ស៊ុយលីយេ សង្ខេបរឿង តួអង្គ បញ្ជីណែនាំ

QGIS export composer to PDF scale the map [closed] Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Print Composer QGIS 2.6, how to export image?QGIS 2.8.1 print composer won't export all OpenCycleMap base layer tilesSave Print/Map QGIS composer view as PNG/PDF using Python (without changing anything in visible layout)?Export QGIS Print Composer PDF with searchable text labelsQGIS Print Composer does not change from landscape to portrait orientation?How can I avoid map size and scale changes in print composer?Fuzzy PDF export in QGIS running on macSierra OSExport the legend into its 100% size using Print ComposerScale-dependent rendering in QGIS PDF output

PDF-ში გადმოწერა სანავიგაციო მენიუproject page