Update Cursor skipping last row? Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Create Python script to update field based on change in another field ArcGISUpdateCursor only takes last value of SearchCursorWhy is Update Cursor adding Object IDs incorrectly?Calculate Row if Row Value Equals Value in ListIdentify closed polylines in ArcGIS using PythonIteratively Updating Just Bottom Row in Table using ArcPy?Comparing value with value from the next rowArcPy rollback update / insert cursors if error occursUsing cursor.next() is resetting “row in cursor” causing it to skip every other rowSwitching from Nested Search Cursors to Dictionaries

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Update Cursor skipping last row?



Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Create Python script to update field based on change in another field ArcGISUpdateCursor only takes last value of SearchCursorWhy is Update Cursor adding Object IDs incorrectly?Calculate Row if Row Value Equals Value in ListIdentify closed polylines in ArcGIS using PythonIteratively Updating Just Bottom Row in Table using ArcPy?Comparing value with value from the next rowArcPy rollback update / insert cursors if error occursUsing cursor.next() is resetting “row in cursor” causing it to skip every other rowSwitching from Nested Search Cursors to Dictionaries



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








4















I have created a python function within field calculator to calculate the time difference between a timestamp (yyyy-MM-dd HH:mm:ss) in a row and the row after (the interval field in seconds). I have used a update cursor with field calculator to do this, however I am receiving null values for both the first and last row.



The first is correctly missed due to the function being reliant on having a value set by the previous row.



I am unsure as to why the last row is being skipped?



The first row of the attribute is formatted as:



First row



The last:



Last row



I have had this issue on several other update cursor functions including those on simple single row condition statements.



Am I missing a statement to close the update cursor loop?



My code is:



import arcpy, time, datetime
from time import strftime
from datetime import timedelta, datetime
from arcpy import da

def FindTime(table,date,interval):

firstRow = True

with arcpy.da.UpdateCursor(table, ["interval", "date"]) as cursor:

for row in cursor:
gap2 = row[1]

if firstRow == True:
gap1 = gap2
firstRow = False
continue
timedelta = gap2 - gap1
row[0] = timedelta.days * 24 * 3600 + timedelta.seconds
gap1 = gap2
cursor.updateRow(row)


*Updated from below comment's solution:



import arcpy
def FindTime(fc, datefield, daydiff_field):

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break









share|improve this question



















  • 1





    There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

    – BERA
    Apr 9 at 19:23












  • Edited pasting to SE typo!

    – Will
    Apr 10 at 9:42

















4















I have created a python function within field calculator to calculate the time difference between a timestamp (yyyy-MM-dd HH:mm:ss) in a row and the row after (the interval field in seconds). I have used a update cursor with field calculator to do this, however I am receiving null values for both the first and last row.



The first is correctly missed due to the function being reliant on having a value set by the previous row.



I am unsure as to why the last row is being skipped?



The first row of the attribute is formatted as:



First row



The last:



Last row



I have had this issue on several other update cursor functions including those on simple single row condition statements.



Am I missing a statement to close the update cursor loop?



My code is:



import arcpy, time, datetime
from time import strftime
from datetime import timedelta, datetime
from arcpy import da

def FindTime(table,date,interval):

firstRow = True

with arcpy.da.UpdateCursor(table, ["interval", "date"]) as cursor:

for row in cursor:
gap2 = row[1]

if firstRow == True:
gap1 = gap2
firstRow = False
continue
timedelta = gap2 - gap1
row[0] = timedelta.days * 24 * 3600 + timedelta.seconds
gap1 = gap2
cursor.updateRow(row)


*Updated from below comment's solution:



import arcpy
def FindTime(fc, datefield, daydiff_field):

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break









share|improve this question



















  • 1





    There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

    – BERA
    Apr 9 at 19:23












  • Edited pasting to SE typo!

    – Will
    Apr 10 at 9:42













4












4








4


0






I have created a python function within field calculator to calculate the time difference between a timestamp (yyyy-MM-dd HH:mm:ss) in a row and the row after (the interval field in seconds). I have used a update cursor with field calculator to do this, however I am receiving null values for both the first and last row.



The first is correctly missed due to the function being reliant on having a value set by the previous row.



I am unsure as to why the last row is being skipped?



The first row of the attribute is formatted as:



First row



The last:



Last row



I have had this issue on several other update cursor functions including those on simple single row condition statements.



Am I missing a statement to close the update cursor loop?



My code is:



import arcpy, time, datetime
from time import strftime
from datetime import timedelta, datetime
from arcpy import da

def FindTime(table,date,interval):

firstRow = True

with arcpy.da.UpdateCursor(table, ["interval", "date"]) as cursor:

for row in cursor:
gap2 = row[1]

if firstRow == True:
gap1 = gap2
firstRow = False
continue
timedelta = gap2 - gap1
row[0] = timedelta.days * 24 * 3600 + timedelta.seconds
gap1 = gap2
cursor.updateRow(row)


*Updated from below comment's solution:



import arcpy
def FindTime(fc, datefield, daydiff_field):

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break









share|improve this question
















I have created a python function within field calculator to calculate the time difference between a timestamp (yyyy-MM-dd HH:mm:ss) in a row and the row after (the interval field in seconds). I have used a update cursor with field calculator to do this, however I am receiving null values for both the first and last row.



The first is correctly missed due to the function being reliant on having a value set by the previous row.



I am unsure as to why the last row is being skipped?



The first row of the attribute is formatted as:



First row



The last:



Last row



I have had this issue on several other update cursor functions including those on simple single row condition statements.



Am I missing a statement to close the update cursor loop?



My code is:



import arcpy, time, datetime
from time import strftime
from datetime import timedelta, datetime
from arcpy import da

def FindTime(table,date,interval):

firstRow = True

with arcpy.da.UpdateCursor(table, ["interval", "date"]) as cursor:

for row in cursor:
gap2 = row[1]

if firstRow == True:
gap1 = gap2
firstRow = False
continue
timedelta = gap2 - gap1
row[0] = timedelta.days * 24 * 3600 + timedelta.seconds
gap1 = gap2
cursor.updateRow(row)


*Updated from below comment's solution:



import arcpy
def FindTime(fc, datefield, daydiff_field):

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break






arcpy modelbuilder field-calculator cursor python-parser






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 10 at 9:15







Will

















asked Apr 9 at 8:56









WillWill

695




695







  • 1





    There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

    – BERA
    Apr 9 at 19:23












  • Edited pasting to SE typo!

    – Will
    Apr 10 at 9:42












  • 1





    There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

    – BERA
    Apr 9 at 19:23












  • Edited pasting to SE typo!

    – Will
    Apr 10 at 9:42







1




1





There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

– BERA
Apr 9 at 19:23






There is no row[2] in your first try, you only have two fields. Are you trying to fetch the value from next row? That is not possible

– BERA
Apr 9 at 19:23














Edited pasting to SE typo!

– Will
Apr 10 at 9:42





Edited pasting to SE typo!

– Will
Apr 10 at 9:42










1 Answer
1






active

oldest

votes


















4














If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here






share|improve this answer




















  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









4














If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here






share|improve this answer




















  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54















4














If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here






share|improve this answer




















  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54













4












4








4







If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here






share|improve this answer















If your field is type date, code below should work. Last line is not calculated since there is no row after. Or do you want to calculate for example second rows diff as second row-first row?



import arcpy

fc = 'somedates'
datefield = 'date123'
daydiff_field = 'seconddiff_long'

all_dates = [i[0] for i in arcpy.da.SearchCursor(fc,datefield)]

diff = [(d1-d0).seconds for d0,d1 in zip(all_dates, all_dates[1:])]
givediff = iter(diff)

with arcpy.da.UpdateCursor(fc, daydiff_field) as cursor:
#next(cursor) #uncomment this line if you want to calculate row2 diff as row2-row1, =first row no diff
for row in cursor:
try:
row[0] = next(givediff) #Fetch diffs until list is empty...
cursor.updateRow(row)
except StopIteration: #...then break the cursor
break


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Apr 9 at 13:08

























answered Apr 9 at 9:34









BERABERA

17.2k62044




17.2k62044







  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54












  • 3





    This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

    – Hornbydd
    Apr 9 at 10:29






  • 3





    Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

    – BERA
    Apr 9 at 10:31






  • 2





    If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

    – Berend
    Apr 9 at 12:52






  • 1





    Slower than what approach?

    – BERA
    Apr 9 at 12:54






  • 1





    Slower than using just an update cursor, as OP does

    – Berend
    Apr 9 at 12:54







3




3





This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

– Hornbydd
Apr 9 at 10:29





This is why I love using SE, I have never used the iter() function before, had to go away and look it up, like it! Is there a performance boost using that approach or was it for convenience?

– Hornbydd
Apr 9 at 10:29




3




3





Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

– BERA
Apr 9 at 10:31





Nice! Dont know if there is a performance boost. I use it because it is a simple way of fetching items in a list instead of trying to iterate over a cursor and list at the same time.

– BERA
Apr 9 at 10:31




2




2





If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

– Berend
Apr 9 at 12:52





If anything, it will actually be slower, because the table is traversed twice instead of once. But for small tables that may not be an issue.

– Berend
Apr 9 at 12:52




1




1





Slower than what approach?

– BERA
Apr 9 at 12:54





Slower than what approach?

– BERA
Apr 9 at 12:54




1




1





Slower than using just an update cursor, as OP does

– Berend
Apr 9 at 12:54





Slower than using just an update cursor, as OP does

– Berend
Apr 9 at 12:54

















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Romeo and Juliet ContentsCharactersSynopsisSourcesDate and textThemes and motifsCriticism and interpretationLegacyScene by sceneSee alsoNotes and referencesSourcesExternal linksNavigation menu"Consumer Price Index (estimate) 1800–"10.2307/28710160037-3222287101610.1093/res/II.5.31910.2307/45967845967810.2307/2869925286992510.1525/jams.1982.35.3.03a00050"Dada Masilo: South African dancer who breaks the rules"10.1093/res/os-XV.57.1610.2307/28680942868094"Sweet Sorrow: Mann-Korman's Romeo and Juliet Closes Sept. 5 at MN's Ordway"the original10.2307/45957745957710.1017/CCOL0521570476.009"Ram Leela box office collections hit massive Rs 100 crore, pulverises prediction"Archived"Broadway Revival of Romeo and Juliet, Starring Orlando Bloom and Condola Rashad, Will Close Dec. 8"Archived10.1075/jhp.7.1.04hon"Wherefore art thou, Romeo? To make us laugh at Navy Pier"the original10.1093/gmo/9781561592630.article.O006772"Ram-leela Review Roundup: Critics Hail Film as Best Adaptation of Romeo and Juliet"Archived10.2307/31946310047-77293194631"Romeo and Juliet get Twitter treatment""Juliet's Nurse by Lois Leveen""Romeo and Juliet: Orlando Bloom's Broadway Debut Released in Theaters for Valentine's Day"Archived"Romeo and Juliet Has No Balcony"10.1093/gmo/9781561592630.article.O00778110.2307/2867423286742310.1076/enst.82.2.115.959510.1080/00138380601042675"A plague o' both your houses: error in GCSE exam paper forces apology""Juliet of the Five O'Clock Shadow, and Other Wonders"10.2307/33912430027-4321339124310.2307/28487440038-7134284874410.2307/29123140149-661129123144728341M"Weekender Guide: Shakespeare on The Drive""balcony"UK public library membership"romeo"UK public library membership10.1017/CCOL9780521844291"Post-Zionist Critique on Israel and the Palestinians Part III: Popular Culture"10.2307/25379071533-86140377-919X2537907"Capulets and Montagues: UK exam board admit mixing names up in Romeo and Juliet paper"Istoria Novellamente Ritrovata di Due Nobili Amanti2027/mdp.390150822329610820-750X"GCSE exam error: Board accidentally rewrites Shakespeare"10.2307/29176390149-66112917639"Exam board apologises after error in English GCSE paper which confused characters in Shakespeare's Romeo and Juliet""From Mariotto and Ganozza to Romeo and Guilietta: Metamorphoses of a Renaissance Tale"10.2307/37323537323510.2307/2867455286745510.2307/28678912867891"10 Questions for Taylor Swift"10.2307/28680922868092"Haymarket Theatre""The Zeffirelli Way: Revealing Talk by Florentine Director""Michael Smuin: 1938-2007 / Prolific dance director had showy career"The Life and Art of Edwin BoothRomeo and JulietRomeo and JulietRomeo and JulietRomeo and JulietEasy Read Romeo and JulietRomeo and Julieteeecb12003684p(data)4099369-3n8211610759dbe00d-a9e2-41a3-b2c1-977dd692899302814385X313670221313670221