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Defining geometry type in QgsDataSourceUri
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Postgis - Converting 'geometry_dump' data type to a 'geometry' typePostgis geometry type = GeometryPostGIS change column type varchar => geometryCan QGIS import Multipatch geometry type?PostgreSQL geometry type invalidDefining features geometry in new created layer using PyQGIS?Debug QgsDataSourceUri as a QgsVectorLayerQGIS change geometry type in shapefileHow to backup QGIS (3.2.1) layer to independent PostGIS table?Invalid geometry vs. no geometry
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There is a PostgreSQL database containing some layers that have few types of geometry (multipolygons and linestrings). I need to distinguish these geometries in two separate layers.
My basic strings that make layer for QGIS are:
uri.setConnection('srs', '5432', 'db_name', 'postgres' , 'password')
for i, name in enumerate(sorted(list_of_layers)): # list containing elements like ['schema_name', 'layer_name']
if name[1] in ['layer_with_geometry_collection']:
uri.setDataSource(name[0], name[1], 'SP_GEOMETRY')
vlayer=QgsVectorLayer (uri.uri(), name[1], "postgres")
Where do I need to set the geometry type?
If I check vlayer.wkbType(), it throws me 0.
Manual set uri.setWkbType() hadn't helped yet.
qgis pyqgis geometry
add a comment |
There is a PostgreSQL database containing some layers that have few types of geometry (multipolygons and linestrings). I need to distinguish these geometries in two separate layers.
My basic strings that make layer for QGIS are:
uri.setConnection('srs', '5432', 'db_name', 'postgres' , 'password')
for i, name in enumerate(sorted(list_of_layers)): # list containing elements like ['schema_name', 'layer_name']
if name[1] in ['layer_with_geometry_collection']:
uri.setDataSource(name[0], name[1], 'SP_GEOMETRY')
vlayer=QgsVectorLayer (uri.uri(), name[1], "postgres")
Where do I need to set the geometry type?
If I check vlayer.wkbType(), it throws me 0.
Manual set uri.setWkbType() hadn't helped yet.
qgis pyqgis geometry
It is very dangerous to casually connect to an RDBMS as the administrative user. Doing so can often result in casual destruction of the database. Instead, create a login user to own your data, and another to manage read-only or read-mostly connections. Thepostgresuser should never own spatial data.
– Vince
Apr 10 at 12:22
@Vince you mean not to usepostgresas a username?
– Pavel Pereverzev
Apr 10 at 12:24
Yes. Only connect as postgres to create new login and group roles.
– Vince
Apr 10 at 12:49
add a comment |
There is a PostgreSQL database containing some layers that have few types of geometry (multipolygons and linestrings). I need to distinguish these geometries in two separate layers.
My basic strings that make layer for QGIS are:
uri.setConnection('srs', '5432', 'db_name', 'postgres' , 'password')
for i, name in enumerate(sorted(list_of_layers)): # list containing elements like ['schema_name', 'layer_name']
if name[1] in ['layer_with_geometry_collection']:
uri.setDataSource(name[0], name[1], 'SP_GEOMETRY')
vlayer=QgsVectorLayer (uri.uri(), name[1], "postgres")
Where do I need to set the geometry type?
If I check vlayer.wkbType(), it throws me 0.
Manual set uri.setWkbType() hadn't helped yet.
qgis pyqgis geometry
There is a PostgreSQL database containing some layers that have few types of geometry (multipolygons and linestrings). I need to distinguish these geometries in two separate layers.
My basic strings that make layer for QGIS are:
uri.setConnection('srs', '5432', 'db_name', 'postgres' , 'password')
for i, name in enumerate(sorted(list_of_layers)): # list containing elements like ['schema_name', 'layer_name']
if name[1] in ['layer_with_geometry_collection']:
uri.setDataSource(name[0], name[1], 'SP_GEOMETRY')
vlayer=QgsVectorLayer (uri.uri(), name[1], "postgres")
Where do I need to set the geometry type?
If I check vlayer.wkbType(), it throws me 0.
Manual set uri.setWkbType() hadn't helped yet.
qgis pyqgis geometry
qgis pyqgis geometry
edited Apr 10 at 10:56
Vince
14.8k32850
14.8k32850
asked Apr 10 at 9:32
Pavel PereverzevPavel Pereverzev
543211
543211
It is very dangerous to casually connect to an RDBMS as the administrative user. Doing so can often result in casual destruction of the database. Instead, create a login user to own your data, and another to manage read-only or read-mostly connections. Thepostgresuser should never own spatial data.
– Vince
Apr 10 at 12:22
@Vince you mean not to usepostgresas a username?
– Pavel Pereverzev
Apr 10 at 12:24
Yes. Only connect as postgres to create new login and group roles.
– Vince
Apr 10 at 12:49
add a comment |
It is very dangerous to casually connect to an RDBMS as the administrative user. Doing so can often result in casual destruction of the database. Instead, create a login user to own your data, and another to manage read-only or read-mostly connections. Thepostgresuser should never own spatial data.
– Vince
Apr 10 at 12:22
@Vince you mean not to usepostgresas a username?
– Pavel Pereverzev
Apr 10 at 12:24
Yes. Only connect as postgres to create new login and group roles.
– Vince
Apr 10 at 12:49
It is very dangerous to casually connect to an RDBMS as the administrative user. Doing so can often result in casual destruction of the database. Instead, create a login user to own your data, and another to manage read-only or read-mostly connections. The
postgres user should never own spatial data.– Vince
Apr 10 at 12:22
It is very dangerous to casually connect to an RDBMS as the administrative user. Doing so can often result in casual destruction of the database. Instead, create a login user to own your data, and another to manage read-only or read-mostly connections. The
postgres user should never own spatial data.– Vince
Apr 10 at 12:22
@Vince you mean not to use
postgres as a username?– Pavel Pereverzev
Apr 10 at 12:24
@Vince you mean not to use
postgres as a username?– Pavel Pereverzev
Apr 10 at 12:24
Yes. Only connect as postgres to create new login and group roles.
– Vince
Apr 10 at 12:49
Yes. Only connect as postgres to create new login and group roles.
– Vince
Apr 10 at 12:49
add a comment |
1 Answer
1
active
oldest
votes
Found an answer in PosGIS reference guide.
According to types of geometry that can be stored in PostGIS database, a filter should be written to get the specific geometry.
For example, I need to get only polygon features. The full code will be:
filter = """ST_GeometryType("") LIKE ''""".format('SP_GEOMETRY', 'ST_Polygon')
uri.setConnection('srs', '5432', 'db_name', 'postgres' , 'password')
for i, name in enumerate(sorted(list_of_layers)): # list containing elements like ['schema_name', 'layer_name']
if name[1] in ['layer_with_geometry_collection']:
uri.setDataSource(name[0], name[1], 'SP_GEOMETRY', filter) # filter added
vlayer=QgsVectorLayer (uri.uri(), name[1], "postgres")
You'd have to build a covering index to make this query performant, and doing do would conflict with use of a spatial index in the application.
– Vince
Apr 10 at 12:51
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
Found an answer in PosGIS reference guide.
According to types of geometry that can be stored in PostGIS database, a filter should be written to get the specific geometry.
For example, I need to get only polygon features. The full code will be:
filter = """ST_GeometryType("") LIKE ''""".format('SP_GEOMETRY', 'ST_Polygon')
uri.setConnection('srs', '5432', 'db_name', 'postgres' , 'password')
for i, name in enumerate(sorted(list_of_layers)): # list containing elements like ['schema_name', 'layer_name']
if name[1] in ['layer_with_geometry_collection']:
uri.setDataSource(name[0], name[1], 'SP_GEOMETRY', filter) # filter added
vlayer=QgsVectorLayer (uri.uri(), name[1], "postgres")
You'd have to build a covering index to make this query performant, and doing do would conflict with use of a spatial index in the application.
– Vince
Apr 10 at 12:51
add a comment |
Found an answer in PosGIS reference guide.
According to types of geometry that can be stored in PostGIS database, a filter should be written to get the specific geometry.
For example, I need to get only polygon features. The full code will be:
filter = """ST_GeometryType("") LIKE ''""".format('SP_GEOMETRY', 'ST_Polygon')
uri.setConnection('srs', '5432', 'db_name', 'postgres' , 'password')
for i, name in enumerate(sorted(list_of_layers)): # list containing elements like ['schema_name', 'layer_name']
if name[1] in ['layer_with_geometry_collection']:
uri.setDataSource(name[0], name[1], 'SP_GEOMETRY', filter) # filter added
vlayer=QgsVectorLayer (uri.uri(), name[1], "postgres")
You'd have to build a covering index to make this query performant, and doing do would conflict with use of a spatial index in the application.
– Vince
Apr 10 at 12:51
add a comment |
Found an answer in PosGIS reference guide.
According to types of geometry that can be stored in PostGIS database, a filter should be written to get the specific geometry.
For example, I need to get only polygon features. The full code will be:
filter = """ST_GeometryType("") LIKE ''""".format('SP_GEOMETRY', 'ST_Polygon')
uri.setConnection('srs', '5432', 'db_name', 'postgres' , 'password')
for i, name in enumerate(sorted(list_of_layers)): # list containing elements like ['schema_name', 'layer_name']
if name[1] in ['layer_with_geometry_collection']:
uri.setDataSource(name[0], name[1], 'SP_GEOMETRY', filter) # filter added
vlayer=QgsVectorLayer (uri.uri(), name[1], "postgres")
Found an answer in PosGIS reference guide.
According to types of geometry that can be stored in PostGIS database, a filter should be written to get the specific geometry.
For example, I need to get only polygon features. The full code will be:
filter = """ST_GeometryType("") LIKE ''""".format('SP_GEOMETRY', 'ST_Polygon')
uri.setConnection('srs', '5432', 'db_name', 'postgres' , 'password')
for i, name in enumerate(sorted(list_of_layers)): # list containing elements like ['schema_name', 'layer_name']
if name[1] in ['layer_with_geometry_collection']:
uri.setDataSource(name[0], name[1], 'SP_GEOMETRY', filter) # filter added
vlayer=QgsVectorLayer (uri.uri(), name[1], "postgres")
answered Apr 10 at 11:11
Pavel PereverzevPavel Pereverzev
543211
543211
You'd have to build a covering index to make this query performant, and doing do would conflict with use of a spatial index in the application.
– Vince
Apr 10 at 12:51
add a comment |
You'd have to build a covering index to make this query performant, and doing do would conflict with use of a spatial index in the application.
– Vince
Apr 10 at 12:51
You'd have to build a covering index to make this query performant, and doing do would conflict with use of a spatial index in the application.
– Vince
Apr 10 at 12:51
You'd have to build a covering index to make this query performant, and doing do would conflict with use of a spatial index in the application.
– Vince
Apr 10 at 12:51
add a comment |
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It is very dangerous to casually connect to an RDBMS as the administrative user. Doing so can often result in casual destruction of the database. Instead, create a login user to own your data, and another to manage read-only or read-mostly connections. The
postgresuser should never own spatial data.– Vince
Apr 10 at 12:22
@Vince you mean not to use
postgresas a username?– Pavel Pereverzev
Apr 10 at 12:24
Yes. Only connect as postgres to create new login and group roles.
– Vince
Apr 10 at 12:49