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Is it bad if a cable is higher current rating than a charger? [on hold]

8

$begingroup$

First time asking here, but

Is there any potential harm in using a charging cable with a higher current rating than a charger it is connected to? It's a tablet (Asus P027) and its charger is 5V/2A only.

I bought a 1-meter/3.3-foot USB-A to USB-C (3.1) cable rated for 3A, it has a 56K resistor according to the QA on the product's page (Belkin 1m USB-A to C cable should pull it on google) and this is all I know about it.

cables charger amperage

share|improve this question

edited yesterday

Transistor

87.6k785189

asked yesterday

Majora LunaMajora Luna

411

New contributor

Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

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put on hold as off-topic by Nick Alexeev♦ yesterday

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions on the use of electronic devices are off-topic as this site is intended specifically for questions on electronics design." – Nick Alexeev

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  No, it's good. The opposite is bad - in extreme cases the cable can melt and catch fire (happened to me, thankfully I noticed the smoke)
  $endgroup$
  – slebetman
  yesterday
  

  
  
  
  

add a comment | 

8

$begingroup$

First time asking here, but

Is there any potential harm in using a charging cable with a higher current rating than a charger it is connected to? It's a tablet (Asus P027) and its charger is 5V/2A only.

I bought a 1-meter/3.3-foot USB-A to USB-C (3.1) cable rated for 3A, it has a 56K resistor according to the QA on the product's page (Belkin 1m USB-A to C cable should pull it on google) and this is all I know about it.

cables charger amperage

share|improve this question

edited yesterday

Transistor

87.6k785189

asked yesterday

Majora LunaMajora Luna

411

New contributor

Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

put on hold as off-topic by Nick Alexeev♦ yesterday

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions on the use of electronic devices are off-topic as this site is intended specifically for questions on electronics design." – Nick Alexeev

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  No, it's good. The opposite is bad - in extreme cases the cable can melt and catch fire (happened to me, thankfully I noticed the smoke)
  $endgroup$
  – slebetman
  yesterday
  

  
  
  
  

add a comment | 

$begingroup$

First time asking here, but

Is there any potential harm in using a charging cable with a higher current rating than a charger it is connected to? It's a tablet (Asus P027) and its charger is 5V/2A only.

I bought a 1-meter/3.3-foot USB-A to USB-C (3.1) cable rated for 3A, it has a 56K resistor according to the QA on the product's page (Belkin 1m USB-A to C cable should pull it on google) and this is all I know about it.

cables charger amperage

share|improve this question

edited yesterday

Transistor

87.6k785189

asked yesterday

Majora LunaMajora Luna

411

New contributor

Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

share|improve this question

edited yesterday

Transistor

87.6k785189

asked yesterday

Majora LunaMajora Luna

411

New contributor

Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited yesterday

Transistor

87.6k785189

asked yesterday

Majora LunaMajora Luna

411

New contributor

Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited yesterday

Transistor

87.6k785189

edited yesterday

Transistor

87.6k785189

asked yesterday

Majora LunaMajora Luna

411

New contributor

Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked yesterday

Majora LunaMajora Luna

411

1 Answer
1

active

oldest

votes

11

$begingroup$

No, only the device should not draw more current than the adapter and the cable can handle.

So the device defines how much current will flow through the circuit (which consists of your adapter and cable).

If the device draws more current, the adapter or the cable may overheat (with a fire hazard).

Btw, it's better to be safe and not use exactly a 2A but at least more, so you are safe with a cable of 3A.

Remarks from others
Also, this yields for most (cheap) adapters. See the comment of Jarrod Christman for an exception.

For USB, there is a negotiation protocol. See the comment of Yakk below.

share|improve this answer

edited yesterday

answered yesterday

Michel KeijzersMichel Keijzers

6,87492971

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
  $endgroup$
  – Martin Bonner
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
  $endgroup$
  – Michel Keijzers
  yesterday
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
  $endgroup$
  – Jarrod Christman
  yesterday
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
  $endgroup$
  – Yakk
  yesterday
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  (note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
  $endgroup$
  – Yakk
  yesterday
  

  
  
  
  

 | 
show 9 more comments

11

$begingroup$

No, only the device should not draw more current than the adapter and the cable can handle.

So the device defines how much current will flow through the circuit (which consists of your adapter and cable).

If the device draws more current, the adapter or the cable may overheat (with a fire hazard).

Btw, it's better to be safe and not use exactly a 2A but at least more, so you are safe with a cable of 3A.

Remarks from others
Also, this yields for most (cheap) adapters. See the comment of Jarrod Christman for an exception.

For USB, there is a negotiation protocol. See the comment of Yakk below.

share|improve this answer

edited yesterday

answered yesterday

Michel KeijzersMichel Keijzers

6,87492971

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
  $endgroup$
  – Martin Bonner
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
  $endgroup$
  – Michel Keijzers
  yesterday
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
  $endgroup$
  – Jarrod Christman
  yesterday
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
  $endgroup$
  – Yakk
  yesterday
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  (note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
  $endgroup$
  – Yakk
  yesterday
  

  
  
  
  

 | 
show 9 more comments

11

$begingroup$

No, only the device should not draw more current than the adapter and the cable can handle.

So the device defines how much current will flow through the circuit (which consists of your adapter and cable).

If the device draws more current, the adapter or the cable may overheat (with a fire hazard).

Btw, it's better to be safe and not use exactly a 2A but at least more, so you are safe with a cable of 3A.

Remarks from others
Also, this yields for most (cheap) adapters. See the comment of Jarrod Christman for an exception.

For USB, there is a negotiation protocol. See the comment of Yakk below.

share|improve this answer

edited yesterday

answered yesterday

Michel KeijzersMichel Keijzers

6,87492971

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
  $endgroup$
  – Martin Bonner
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
  $endgroup$
  – Michel Keijzers
  yesterday
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
  $endgroup$
  – Jarrod Christman
  yesterday
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
  $endgroup$
  – Yakk
  yesterday
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  (note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
  $endgroup$
  – Yakk
  yesterday
  

  
  
  
  

 | 
show 9 more comments

$begingroup$

No, only the device should not draw more current than the adapter and the cable can handle.

So the device defines how much current will flow through the circuit (which consists of your adapter and cable).

If the device draws more current, the adapter or the cable may overheat (with a fire hazard).

Btw, it's better to be safe and not use exactly a 2A but at least more, so you are safe with a cable of 3A.

Remarks from others
Also, this yields for most (cheap) adapters. See the comment of Jarrod Christman for an exception.

For USB, there is a negotiation protocol. See the comment of Yakk below.

share|improve this answer

edited yesterday

answered yesterday

Michel KeijzersMichel Keijzers

6,87492971

$endgroup$

share|improve this answer

edited yesterday

answered yesterday

Michel KeijzersMichel Keijzers

6,87492971

answered yesterday

Michel KeijzersMichel Keijzers

6,87492971

answered yesterday

Michel KeijzersMichel Keijzers

6,87492971