Is it bad if a cable is higher current rating than a charger? [on hold] The Next CEO of Stack OverflowUSB Power - The basicsWhy ship a low power charger with an overkill thick cable?smartphone charger voltage ratingIs it safe to use the cable used in Portable Battery Charger and connect to the phone via the PC USB?Charging phone battery with a high current sourceMaximum current for a single-core cable?Why is the FLA current so much higher than the actual running current?cable size vs current ratingPower cable of a laptop chargerWhy USB wall chargers don't reach their amperage rating?Cordless vacumn charger rating calculation
How did people program for Consoles with multiple CPUs?
What is the purpose of the Evocation wizard's Potent Cantrip feature?
Does it take more energy to get to Venus or to Mars?
sp_blitzCache results Memory grants
Interfacing a button to MCU (and PC) with 50m long cable
Elegant way to replace substring in a regex with optional groups in Python?
WOW air has ceased operation, can I get my tickets refunded?
Can I run my washing machine drain line into a condensate pump so it drains better?
Is it professional to write unrelated content in an almost-empty email?
Rotate a column
Unreliable Magic - Is it worth it?
Why don't programming languages automatically manage the synchronous/asynchronous problem?
Should I tutor a student who I know has cheated on their homework?
Help understanding this unsettling image of Titan, Epimetheus, and Saturn's rings?
What is the result of assigning to std::vector<T>::begin()?
To not tell, not take, and not want
What exact does MIB represent in SNMP? How is it different from OID?
Anatomically Correct Strange Women In Ponds Distributing Swords
Is it ever safe to open a suspicious html file (e.g. email attachment)?
If a black hole is created from light, can this black hole then move at speed of light?
Can I equip Skullclamp on a creature I am sacrificing?
Are there any limitations on attacking while grappling?
Why do we use the plural of movies in this phrase "We went to the movies last night."?
Would a completely good Muggle be able to use a wand?
Is it bad if a cable is higher current rating than a charger? [on hold]
The Next CEO of Stack OverflowUSB Power - The basicsWhy ship a low power charger with an overkill thick cable?smartphone charger voltage ratingIs it safe to use the cable used in Portable Battery Charger and connect to the phone via the PC USB?Charging phone battery with a high current sourceMaximum current for a single-core cable?Why is the FLA current so much higher than the actual running current?cable size vs current ratingPower cable of a laptop chargerWhy USB wall chargers don't reach their amperage rating?Cordless vacumn charger rating calculation
$begingroup$
First time asking here, but
Is there any potential harm in using a charging cable with a higher current rating than a charger it is connected to? It's a tablet (Asus P027) and its charger is 5V/2A only.
I bought a 1-meter/3.3-foot USB-A to USB-C (3.1) cable rated for 3A, it has a 56K resistor according to the QA on the product's page (Belkin 1m USB-A to C cable should pull it on google) and this is all I know about it.
cables charger amperage
edited yesterday
Transistor
87.6k785189
asked yesterday
Majora LunaMajora Luna
411
New contributor
Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
put on hold as off-topic by Nick Alexeev♦ yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions on the use of electronic devices are off-topic as this site is intended specifically for questions on electronics design." – Nick Alexeev
add a comment |
$begingroup$
First time asking here, but
Is there any potential harm in using a charging cable with a higher current rating than a charger it is connected to? It's a tablet (Asus P027) and its charger is 5V/2A only.
I bought a 1-meter/3.3-foot USB-A to USB-C (3.1) cable rated for 3A, it has a 56K resistor according to the QA on the product's page (Belkin 1m USB-A to C cable should pull it on google) and this is all I know about it.
cables charger amperage
edited yesterday
Transistor
87.6k785189
asked yesterday
Majora LunaMajora Luna
411
New contributor
Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
put on hold as off-topic by Nick Alexeev♦ yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions on the use of electronic devices are off-topic as this site is intended specifically for questions on electronics design." – Nick Alexeev
$begingroup$
No, it's good. The opposite is bad - in extreme cases the cable can melt and catch fire (happened to me, thankfully I noticed the smoke)
$endgroup$
– slebetman
yesterday
add a comment |
$begingroup$
First time asking here, but
Is there any potential harm in using a charging cable with a higher current rating than a charger it is connected to? It's a tablet (Asus P027) and its charger is 5V/2A only.
I bought a 1-meter/3.3-foot USB-A to USB-C (3.1) cable rated for 3A, it has a 56K resistor according to the QA on the product's page (Belkin 1m USB-A to C cable should pull it on google) and this is all I know about it.
cables charger amperage
edited yesterday
Transistor
87.6k785189
asked yesterday
Majora LunaMajora Luna
411
New contributor
Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
First time asking here, but
Is there any potential harm in using a charging cable with a higher current rating than a charger it is connected to? It's a tablet (Asus P027) and its charger is 5V/2A only.
I bought a 1-meter/3.3-foot USB-A to USB-C (3.1) cable rated for 3A, it has a 56K resistor according to the QA on the product's page (Belkin 1m USB-A to C cable should pull it on google) and this is all I know about it.
cables charger amperage
cables charger amperage
edited yesterday
Transistor
87.6k785189
asked yesterday
Majora LunaMajora Luna
411
New contributor
Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited yesterday
Transistor
87.6k785189
asked yesterday
Majora LunaMajora Luna
411
New contributor
Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited yesterday
Transistor
87.6k785189
edited yesterday
Transistor
87.6k785189
edited yesterday
Transistor
87.6k785189
87.6k785189
asked yesterday
Majora LunaMajora Luna
411
New contributor
Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
Majora LunaMajora Luna
411
asked yesterday
Majora LunaMajora Luna
411
411
New contributor
Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Majora Luna is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Nick Alexeev♦ yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions on the use of electronic devices are off-topic as this site is intended specifically for questions on electronics design." – Nick Alexeev
put on hold as off-topic by Nick Alexeev♦ yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions on the use of electronic devices are off-topic as this site is intended specifically for questions on electronics design." – Nick Alexeev
$begingroup$
No, it's good. The opposite is bad - in extreme cases the cable can melt and catch fire (happened to me, thankfully I noticed the smoke)
$endgroup$
– slebetman
yesterday
add a comment |
$begingroup$
No, it's good. The opposite is bad - in extreme cases the cable can melt and catch fire (happened to me, thankfully I noticed the smoke)
$endgroup$
– slebetman
yesterday
$begingroup$
No, it's good. The opposite is bad - in extreme cases the cable can melt and catch fire (happened to me, thankfully I noticed the smoke)
$endgroup$
– slebetman
yesterday
$begingroup$
No, it's good. The opposite is bad - in extreme cases the cable can melt and catch fire (happened to me, thankfully I noticed the smoke)
$endgroup$
– slebetman
yesterday
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
No, only the device should not draw more current than the adapter and the cable can handle.
So the device defines how much current will flow through the circuit (which consists of your adapter and cable).
If the device draws more current, the adapter or the cable may overheat (with a fire hazard).
Btw, it's better to be safe and not use exactly a 2A but at least more, so you are safe with a cable of 3A.
Remarks from others
Also, this yields for most (cheap) adapters. See the comment of Jarrod Christman for an exception.
For USB, there is a negotiation protocol. See the comment of Yakk below.
answered yesterday
Michel KeijzersMichel Keijzers
6,87492971
$endgroup$
$begingroup$
I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
$endgroup$
– Martin Bonner
yesterday
$begingroup$
@MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
$endgroup$
– Michel Keijzers
yesterday
1
$begingroup$
@MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
$endgroup$
– Jarrod Christman
yesterday
2
$begingroup$
Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
$endgroup$
– Yakk
yesterday
1
$begingroup$
(note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
$endgroup$
– Yakk
yesterday
|
show 9 more comments
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
No, only the device should not draw more current than the adapter and the cable can handle.
So the device defines how much current will flow through the circuit (which consists of your adapter and cable).
If the device draws more current, the adapter or the cable may overheat (with a fire hazard).
Btw, it's better to be safe and not use exactly a 2A but at least more, so you are safe with a cable of 3A.
Remarks from others
Also, this yields for most (cheap) adapters. See the comment of Jarrod Christman for an exception.
For USB, there is a negotiation protocol. See the comment of Yakk below.
answered yesterday
Michel KeijzersMichel Keijzers
6,87492971
$endgroup$
$begingroup$
I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
$endgroup$
– Martin Bonner
yesterday
$begingroup$
@MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
$endgroup$
– Michel Keijzers
yesterday
1
$begingroup$
@MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
$endgroup$
– Jarrod Christman
yesterday
2
$begingroup$
Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
$endgroup$
– Yakk
yesterday
1
$begingroup$
(note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
$endgroup$
– Yakk
yesterday
|
show 9 more comments
$begingroup$
No, only the device should not draw more current than the adapter and the cable can handle.
So the device defines how much current will flow through the circuit (which consists of your adapter and cable).
If the device draws more current, the adapter or the cable may overheat (with a fire hazard).
Btw, it's better to be safe and not use exactly a 2A but at least more, so you are safe with a cable of 3A.
Remarks from others
Also, this yields for most (cheap) adapters. See the comment of Jarrod Christman for an exception.
For USB, there is a negotiation protocol. See the comment of Yakk below.
answered yesterday
Michel KeijzersMichel Keijzers
6,87492971
$endgroup$
$begingroup$
I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
$endgroup$
– Martin Bonner
yesterday
$begingroup$
@MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
$endgroup$
– Michel Keijzers
yesterday
1
$begingroup$
@MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
$endgroup$
– Jarrod Christman
yesterday
2
$begingroup$
Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
$endgroup$
– Yakk
yesterday
1
$begingroup$
(note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
$endgroup$
– Yakk
yesterday
|
show 9 more comments
$begingroup$
No, only the device should not draw more current than the adapter and the cable can handle.
So the device defines how much current will flow through the circuit (which consists of your adapter and cable).
If the device draws more current, the adapter or the cable may overheat (with a fire hazard).
Btw, it's better to be safe and not use exactly a 2A but at least more, so you are safe with a cable of 3A.
Remarks from others
Also, this yields for most (cheap) adapters. See the comment of Jarrod Christman for an exception.
For USB, there is a negotiation protocol. See the comment of Yakk below.
answered yesterday
Michel KeijzersMichel Keijzers
6,87492971
$endgroup$
No, only the device should not draw more current than the adapter and the cable can handle.
So the device defines how much current will flow through the circuit (which consists of your adapter and cable).
If the device draws more current, the adapter or the cable may overheat (with a fire hazard).
Btw, it's better to be safe and not use exactly a 2A but at least more, so you are safe with a cable of 3A.
Remarks from others
Also, this yields for most (cheap) adapters. See the comment of Jarrod Christman for an exception.
For USB, there is a negotiation protocol. See the comment of Yakk below.
answered yesterday
Michel KeijzersMichel Keijzers
6,87492971
edited yesterday
answered yesterday
Michel KeijzersMichel Keijzers
6,87492971
answered yesterday
Michel KeijzersMichel Keijzers
6,87492971
answered yesterday
Michel KeijzersMichel Keijzers
6,87492971
6,87492971
$begingroup$
I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
$endgroup$
– Martin Bonner
yesterday
$begingroup$
@MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
$endgroup$
– Michel Keijzers
yesterday
1
$begingroup$
@MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
$endgroup$
– Jarrod Christman
yesterday
2
$begingroup$
Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
$endgroup$
– Yakk
yesterday
1
$begingroup$
(note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
$endgroup$
– Yakk
yesterday
|
show 9 more comments
$begingroup$
I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
$endgroup$
– Martin Bonner
yesterday
$begingroup$
@MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
$endgroup$
– Michel Keijzers
yesterday
1
$begingroup$
@MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
$endgroup$
– Jarrod Christman
yesterday
2
$begingroup$
Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
$endgroup$
– Yakk
yesterday
1
$begingroup$
(note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
$endgroup$
– Yakk
yesterday
$begingroup$
I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
$endgroup$
– Martin Bonner
yesterday
$begingroup$
I don't think this is right. If the device tries to draw more than 2A, the adaptor should drop the voltage to keep the current down (until it reaches the point where the voltage is so low that the adaptor cuts out altogether).
$endgroup$
– Martin Bonner
yesterday
$begingroup$
@MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
$endgroup$
– Michel Keijzers
yesterday
$begingroup$
@MartinBonner I don't have the theoretical knowledge, but afaik an adapter just 'gives' the current the load needs, and if the load requests more, the adapter delivers more, even if it cannot handle it. Of course, it might be possible there is some kind of safety circuit built in the adapter, but this is not common (for cheap adapters at least).
$endgroup$
– Michel Keijzers
yesterday
1
1
$begingroup$
@MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
$endgroup$
– Jarrod Christman
yesterday
$begingroup$
@MartinBonner, that depends entirely on the adapter design and intent. Some power supplies will attempt to keep voltage constant and allow more current even beyond their own spec and die. This coupled with intentionally underrating for a safety buffer (a 3A power supply may actually do 3.5A fine), it is best to assume the worst case. Thus your power supply and cables should be oversized to some extent for your use, so you're not constantly against their max rating.
$endgroup$
– Jarrod Christman
yesterday
2
2
$begingroup$
Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
$endgroup$
– Yakk
yesterday
$begingroup$
Are you aware of how USB-C devices "negotate" with USB-C cables to determine how much current they can draw? Your answer seems to completely ignore this issue, which is at the core of the OP's problem. I believe 56k resistor in the cable communicates to the attached USB device how much current it can safely draw; barring something I don't know (which is plenty) that cable might convince the USB device into thinking "ok, drawing 3A is ok from this", frying the charger. This isn't a "dumb cable"; for a dumb cable your answer seems correct (more A=more safe)
$endgroup$
– Yakk
yesterday
1
1
$begingroup$
(note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
$endgroup$
– Yakk
yesterday
$begingroup$
(note: I am not an expert at this. Possibly there is a way that the other end of the USB connection (the charger) communicates to the USB-C device the current it supports, and/or handles being asked for more power than it is rated for gracefully)
$endgroup$
– Yakk
yesterday
|
show 9 more comments
$begingroup$
No, it's good. The opposite is bad - in extreme cases the cable can melt and catch fire (happened to me, thankfully I noticed the smoke)
$endgroup$
– slebetman
yesterday