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3

1

I am working with Landusefc and Class columns (ref table).

What I want is: Selecting all water from "Class" and giving a value say '8' in the "Landusefc" column for these selected features.

Table looks like

I have tried the following code, it works till the selection part but doesn't seem to change the attribute value using the ChangeAttributeValue.

from qgis.core import *
import processing
layer=processing.getObject('test1')
query= ' "class" = 'Water' '
selection = layer.getFeatures(QgsFeatureRequest().setFilterExpression(query))
layer.setSelectedFeatures([k.id() for k in selection])

#using change Attribute to change the value of the selected feature

layer.startEditing()
for feat in selection:
 layer.changeAttributeValue(feat.id(), 5, 8)

layer.commitChanges()

qgis pyqgis select-by-attribute

share|improve this question

edited Apr 11 at 7:48

Kadir Şahbaz

4,69221531

asked Apr 11 at 6:45

ShellyShelly

262

add a comment | 

3

1

I am working with Landusefc and Class columns (ref table).

What I want is: Selecting all water from "Class" and giving a value say '8' in the "Landusefc" column for these selected features.

Table looks like

I have tried the following code, it works till the selection part but doesn't seem to change the attribute value using the ChangeAttributeValue.

from qgis.core import *
import processing
layer=processing.getObject('test1')
query= ' "class" = 'Water' '
selection = layer.getFeatures(QgsFeatureRequest().setFilterExpression(query))
layer.setSelectedFeatures([k.id() for k in selection])

#using change Attribute to change the value of the selected feature

layer.startEditing()
for feat in selection:
 layer.changeAttributeValue(feat.id(), 5, 8)

layer.commitChanges()

qgis pyqgis select-by-attribute

share|improve this question

edited Apr 11 at 7:48

Kadir Şahbaz

4,69221531

asked Apr 11 at 6:45

ShellyShelly

262

add a comment | 

I am working with Landusefc and Class columns (ref table).

What I want is: Selecting all water from "Class" and giving a value say '8' in the "Landusefc" column for these selected features.

Table looks like

I have tried the following code, it works till the selection part but doesn't seem to change the attribute value using the ChangeAttributeValue.

from qgis.core import *
import processing
layer=processing.getObject('test1')
query= ' "class" = 'Water' '
selection = layer.getFeatures(QgsFeatureRequest().setFilterExpression(query))
layer.setSelectedFeatures([k.id() for k in selection])

#using change Attribute to change the value of the selected feature

layer.startEditing()
for feat in selection:
 layer.changeAttributeValue(feat.id(), 5, 8)

layer.commitChanges()

qgis pyqgis select-by-attribute

share|improve this question

edited Apr 11 at 7:48

Kadir Şahbaz

4,69221531

asked Apr 11 at 6:45

ShellyShelly

262

from qgis.core import *
import processing
layer=processing.getObject('test1')
query= ' "class" = 'Water' '
selection = layer.getFeatures(QgsFeatureRequest().setFilterExpression(query))
layer.setSelectedFeatures([k.id() for k in selection])

#using change Attribute to change the value of the selected feature

layer.startEditing()
for feat in selection:
 layer.changeAttributeValue(feat.id(), 5, 8)

layer.commitChanges()

share|improve this question

edited Apr 11 at 7:48

Kadir Şahbaz

4,69221531

asked Apr 11 at 6:45

ShellyShelly

262

share|improve this question

edited Apr 11 at 7:48

Kadir Şahbaz

4,69221531

asked Apr 11 at 6:45

ShellyShelly

262

edited Apr 11 at 7:48

Kadir Şahbaz

4,69221531

edited Apr 11 at 7:48

Kadir Şahbaz

4,69221531

asked Apr 11 at 6:45

ShellyShelly

262

asked Apr 11 at 6:45

ShellyShelly

262

1 Answer
1

active

oldest

votes

3

SOLUTION 1:

You have to remove layer.setSelectedFeatures([k.id() for k in selection]).

Because selection = layer.getFeatures(QgsFeatureRequest().setFilterExpression(query)) line gives you a QgsFeatureIterator, that's an iterator. When you use that iterator once, you reach the end of the iterator. Then, if you use it again, you get nothing.

In your case, when you use selection variable (it's an iterator now) in [k.id() for k in selection], you reach the end. If you use selection in for loop, since you are at the end of the iterator, you don't have any feature now. If you want to be certain, you can add a print("Foo") line to for loop.

SOLUTION 2:

Change for feat in selection: into for feat in layer.selectedFeatures():. This solution works only on QGIS 2.x.

share|improve this answer

edited Apr 11 at 9:08

answered Apr 11 at 7:46

Kadir ŞahbazKadir Şahbaz

4,69221531

add a comment | 

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3

SOLUTION 1:

You have to remove layer.setSelectedFeatures([k.id() for k in selection]).

Because selection = layer.getFeatures(QgsFeatureRequest().setFilterExpression(query)) line gives you a QgsFeatureIterator, that's an iterator. When you use that iterator once, you reach the end of the iterator. Then, if you use it again, you get nothing.

In your case, when you use selection variable (it's an iterator now) in [k.id() for k in selection], you reach the end. If you use selection in for loop, since you are at the end of the iterator, you don't have any feature now. If you want to be certain, you can add a print("Foo") line to for loop.

SOLUTION 2:

Change for feat in selection: into for feat in layer.selectedFeatures():. This solution works only on QGIS 2.x.

share|improve this answer

edited Apr 11 at 9:08

answered Apr 11 at 7:46

Kadir ŞahbazKadir Şahbaz

4,69221531

add a comment | 

3

SOLUTION 1:

You have to remove layer.setSelectedFeatures([k.id() for k in selection]).

Because selection = layer.getFeatures(QgsFeatureRequest().setFilterExpression(query)) line gives you a QgsFeatureIterator, that's an iterator. When you use that iterator once, you reach the end of the iterator. Then, if you use it again, you get nothing.

In your case, when you use selection variable (it's an iterator now) in [k.id() for k in selection], you reach the end. If you use selection in for loop, since you are at the end of the iterator, you don't have any feature now. If you want to be certain, you can add a print("Foo") line to for loop.

SOLUTION 2:

Change for feat in selection: into for feat in layer.selectedFeatures():. This solution works only on QGIS 2.x.

share|improve this answer

edited Apr 11 at 9:08

answered Apr 11 at 7:46

Kadir ŞahbazKadir Şahbaz

4,69221531

add a comment | 

SOLUTION 1:

You have to remove layer.setSelectedFeatures([k.id() for k in selection]).

Because selection = layer.getFeatures(QgsFeatureRequest().setFilterExpression(query)) line gives you a QgsFeatureIterator, that's an iterator. When you use that iterator once, you reach the end of the iterator. Then, if you use it again, you get nothing.

In your case, when you use selection variable (it's an iterator now) in [k.id() for k in selection], you reach the end. If you use selection in for loop, since you are at the end of the iterator, you don't have any feature now. If you want to be certain, you can add a print("Foo") line to for loop.

SOLUTION 2:

Change for feat in selection: into for feat in layer.selectedFeatures():. This solution works only on QGIS 2.x.

share|improve this answer

edited Apr 11 at 9:08

answered Apr 11 at 7:46

Kadir ŞahbazKadir Şahbaz

4,69221531

share|improve this answer

edited Apr 11 at 9:08

answered Apr 11 at 7:46

Kadir ŞahbazKadir Şahbaz

4,69221531

answered Apr 11 at 7:46

Kadir ŞahbazKadir Şahbaz

4,69221531

answered Apr 11 at 7:46

Kadir ŞahbazKadir Şahbaz

4,69221531