Least quadratic residue under GRH: an explicit bound The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)explicit lower bounds on $|L(1,chi)|$Explicit bound on $sum_Nmathfrak p leq xchi(mathfrak p)ln(Nmathfrak p)$Explicit bounds for exceptional zeros and/or $L(1,chi)$ for real $chi$Effective bound of $L(1,chi)$Property of Dirichlet characterOn a sequence of L-functions having same zeros in critical strip and GRHQuestion about the term $sum_ rho fracX^rhorho$ in the explicit formula of $sum_n leq X Lambda(n) chi(n)$Questions about the exceptional zeros of Dirichlet $L$-functionsPrime character sumsExplicit Version of the Burgess Theorem

Least quadratic residue under GRH: an explicit bound



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)explicit lower bounds on $|L(1,chi)|$Explicit bound on $sum_Nmathfrak p leq xchi(mathfrak p)ln(Nmathfrak p)$Explicit bounds for exceptional zeros and/or $L(1,chi)$ for real $chi$Effective bound of $L(1,chi)$Property of Dirichlet characterOn a sequence of L-functions having same zeros in critical strip and GRHQuestion about the term $sum_ rho fracX^rhorho$ in the explicit formula of $sum_n leq X Lambda(n) chi(n)$Questions about the exceptional zeros of Dirichlet $L$-functionsPrime character sumsExplicit Version of the Burgess Theorem










10












$begingroup$


Let $m$ be a positive integer and $chi$ a primitive character mod $m$. Let $x$ be such that $chi(p)ne 1$ for all primes $p<x$. Assume GRH. How can one bound $x$ in terms of $m$ ? I do not need the best possible bound, but I need a good quality bound which is totally explicit in all parameters.



A related question: what is an explicit lower bound for $L(1,chi)$ under GRH?










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Yuri Bilu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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    10












    $begingroup$


    Let $m$ be a positive integer and $chi$ a primitive character mod $m$. Let $x$ be such that $chi(p)ne 1$ for all primes $p<x$. Assume GRH. How can one bound $x$ in terms of $m$ ? I do not need the best possible bound, but I need a good quality bound which is totally explicit in all parameters.



    A related question: what is an explicit lower bound for $L(1,chi)$ under GRH?










    share|cite|improve this question









    New contributor




    Yuri Bilu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      10












      10








      10





      $begingroup$


      Let $m$ be a positive integer and $chi$ a primitive character mod $m$. Let $x$ be such that $chi(p)ne 1$ for all primes $p<x$. Assume GRH. How can one bound $x$ in terms of $m$ ? I do not need the best possible bound, but I need a good quality bound which is totally explicit in all parameters.



      A related question: what is an explicit lower bound for $L(1,chi)$ under GRH?










      share|cite|improve this question









      New contributor




      Yuri Bilu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      Let $m$ be a positive integer and $chi$ a primitive character mod $m$. Let $x$ be such that $chi(p)ne 1$ for all primes $p<x$. Assume GRH. How can one bound $x$ in terms of $m$ ? I do not need the best possible bound, but I need a good quality bound which is totally explicit in all parameters.



      A related question: what is an explicit lower bound for $L(1,chi)$ under GRH?







      nt.number-theory analytic-number-theory l-functions






      share|cite|improve this question









      New contributor




      Yuri Bilu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question









      New contributor




      Yuri Bilu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|cite|improve this question




      share|cite|improve this question








      edited Apr 8 at 14:07









      YCor

      29.1k486140




      29.1k486140






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      Yuri Bilu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked Apr 8 at 1:21









      Yuri BiluYuri Bilu

      835




      835




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      New contributor





      Yuri Bilu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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          1 Answer
          1






          active

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          20












          $begingroup$

          See the work of Lamzouri, Li, and Soundararajan (I link the arXiv version; the paper appeared in Math. Comp.). Assuming that $chi$ is a primitive quadratic character (as the title suggests) then Theorem 1.4 of that paper gives an explicit bound on the least prime quadratic residue on GRH. (Indeed that theorem gives an explicit bound on the least prime in any coset of a subgroup of $(Bbb Z/qBbb Z)^times$.) Theorem 1.5 there gives explicit upper and lower bounds for $|L(1,chi)|$ for any primitive character $chi pmod q$ (not necessarily quadratic).






          share|cite|improve this answer









          $endgroup$








          • 1




            $begingroup$
            Lucia, many thanks! This is exactly what I am looking for!
            $endgroup$
            – Yuri Bilu
            Apr 8 at 2:37






          • 2




            $begingroup$
            @YuriBilu: If you like Lucia's answer, please accept it officially (so that it turns green). Thanks! (And welcome to MO!)
            $endgroup$
            – GH from MO
            Apr 8 at 9:30












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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          20












          $begingroup$

          See the work of Lamzouri, Li, and Soundararajan (I link the arXiv version; the paper appeared in Math. Comp.). Assuming that $chi$ is a primitive quadratic character (as the title suggests) then Theorem 1.4 of that paper gives an explicit bound on the least prime quadratic residue on GRH. (Indeed that theorem gives an explicit bound on the least prime in any coset of a subgroup of $(Bbb Z/qBbb Z)^times$.) Theorem 1.5 there gives explicit upper and lower bounds for $|L(1,chi)|$ for any primitive character $chi pmod q$ (not necessarily quadratic).






          share|cite|improve this answer









          $endgroup$








          • 1




            $begingroup$
            Lucia, many thanks! This is exactly what I am looking for!
            $endgroup$
            – Yuri Bilu
            Apr 8 at 2:37






          • 2




            $begingroup$
            @YuriBilu: If you like Lucia's answer, please accept it officially (so that it turns green). Thanks! (And welcome to MO!)
            $endgroup$
            – GH from MO
            Apr 8 at 9:30
















          20












          $begingroup$

          See the work of Lamzouri, Li, and Soundararajan (I link the arXiv version; the paper appeared in Math. Comp.). Assuming that $chi$ is a primitive quadratic character (as the title suggests) then Theorem 1.4 of that paper gives an explicit bound on the least prime quadratic residue on GRH. (Indeed that theorem gives an explicit bound on the least prime in any coset of a subgroup of $(Bbb Z/qBbb Z)^times$.) Theorem 1.5 there gives explicit upper and lower bounds for $|L(1,chi)|$ for any primitive character $chi pmod q$ (not necessarily quadratic).






          share|cite|improve this answer









          $endgroup$








          • 1




            $begingroup$
            Lucia, many thanks! This is exactly what I am looking for!
            $endgroup$
            – Yuri Bilu
            Apr 8 at 2:37






          • 2




            $begingroup$
            @YuriBilu: If you like Lucia's answer, please accept it officially (so that it turns green). Thanks! (And welcome to MO!)
            $endgroup$
            – GH from MO
            Apr 8 at 9:30














          20












          20








          20





          $begingroup$

          See the work of Lamzouri, Li, and Soundararajan (I link the arXiv version; the paper appeared in Math. Comp.). Assuming that $chi$ is a primitive quadratic character (as the title suggests) then Theorem 1.4 of that paper gives an explicit bound on the least prime quadratic residue on GRH. (Indeed that theorem gives an explicit bound on the least prime in any coset of a subgroup of $(Bbb Z/qBbb Z)^times$.) Theorem 1.5 there gives explicit upper and lower bounds for $|L(1,chi)|$ for any primitive character $chi pmod q$ (not necessarily quadratic).






          share|cite|improve this answer









          $endgroup$



          See the work of Lamzouri, Li, and Soundararajan (I link the arXiv version; the paper appeared in Math. Comp.). Assuming that $chi$ is a primitive quadratic character (as the title suggests) then Theorem 1.4 of that paper gives an explicit bound on the least prime quadratic residue on GRH. (Indeed that theorem gives an explicit bound on the least prime in any coset of a subgroup of $(Bbb Z/qBbb Z)^times$.) Theorem 1.5 there gives explicit upper and lower bounds for $|L(1,chi)|$ for any primitive character $chi pmod q$ (not necessarily quadratic).







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Apr 8 at 2:05









          LuciaLucia

          34.9k5151177




          34.9k5151177







          • 1




            $begingroup$
            Lucia, many thanks! This is exactly what I am looking for!
            $endgroup$
            – Yuri Bilu
            Apr 8 at 2:37






          • 2




            $begingroup$
            @YuriBilu: If you like Lucia's answer, please accept it officially (so that it turns green). Thanks! (And welcome to MO!)
            $endgroup$
            – GH from MO
            Apr 8 at 9:30













          • 1




            $begingroup$
            Lucia, many thanks! This is exactly what I am looking for!
            $endgroup$
            – Yuri Bilu
            Apr 8 at 2:37






          • 2




            $begingroup$
            @YuriBilu: If you like Lucia's answer, please accept it officially (so that it turns green). Thanks! (And welcome to MO!)
            $endgroup$
            – GH from MO
            Apr 8 at 9:30








          1




          1




          $begingroup$
          Lucia, many thanks! This is exactly what I am looking for!
          $endgroup$
          – Yuri Bilu
          Apr 8 at 2:37




          $begingroup$
          Lucia, many thanks! This is exactly what I am looking for!
          $endgroup$
          – Yuri Bilu
          Apr 8 at 2:37




          2




          2




          $begingroup$
          @YuriBilu: If you like Lucia's answer, please accept it officially (so that it turns green). Thanks! (And welcome to MO!)
          $endgroup$
          – GH from MO
          Apr 8 at 9:30





          $begingroup$
          @YuriBilu: If you like Lucia's answer, please accept it officially (so that it turns green). Thanks! (And welcome to MO!)
          $endgroup$
          – GH from MO
          Apr 8 at 9:30











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