Chess with symmetric move-square The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Copycat chess is backHow many Chess Pieces are needed to control every square on the board?Equal Chess ControlEqual Chess Control With One ColorThe Knight Checker or Football ChessFairy Chess #1- The MastermindA Battle of Dysfunctional Kings (Chess)Mate in one with NO PIECES?A Chess Lock Puzzle?The ability-swap-circle chessCopycat chess is back
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Chess with symmetric move-square
The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Copycat chess is backHow many Chess Pieces are needed to control every square on the board?Equal Chess ControlEqual Chess Control With One ColorThe Knight Checker or Football ChessFairy Chess #1- The MastermindA Battle of Dysfunctional Kings (Chess)Mate in one with NO PIECES?A Chess Lock Puzzle?The ability-swap-circle chessCopycat chess is back
$begingroup$
Every move in chess involves moving a piece to a square. Let us call this square the "move-square" for that turn.
In the following, the move-square of the black player must be symmetrical (over the obvious center-horizontal) to the move-square by white on that turn. The requirements may be met with a white move, but an additional valid move for black must be shown to exist. This extra move is not included when counting the number of moves taken to reach one of the below conditions.
What is the shortest sequence (with symmetrical move-squares) resulting in a Rook x Rook capture?
Resulting in a Knight x Rook capture?
Resulting in Queen x Bishop capture?
chess checkerboard knight-moves
New contributor
$endgroup$
|
show 4 more comments
$begingroup$
Every move in chess involves moving a piece to a square. Let us call this square the "move-square" for that turn.
In the following, the move-square of the black player must be symmetrical (over the obvious center-horizontal) to the move-square by white on that turn. The requirements may be met with a white move, but an additional valid move for black must be shown to exist. This extra move is not included when counting the number of moves taken to reach one of the below conditions.
What is the shortest sequence (with symmetrical move-squares) resulting in a Rook x Rook capture?
Resulting in a Knight x Rook capture?
Resulting in Queen x Bishop capture?
chess checkerboard knight-moves
New contributor
$endgroup$
$begingroup$
Hi @ArtemLugin, welcome to Puzzling SE! (Take the tour if you haven't already!) Can you clarify if the same piece has to occupy black's move-square as white's, or can any piece count? For example, would something like 1. e4 e5 2. Be2 Ne2 be acceptable? Or is only Be7 by black possible?
$endgroup$
– PiIsNot3
Apr 8 at 0:59
1
$begingroup$
@PiIsNot3 Its doesn't have to be the same piece. Only the corresponding symmetric square. Assuming you mean Ne7 not Ne2 yes, thats acceptable
$endgroup$
– Artem Lugin
Apr 8 at 1:08
1
$begingroup$
Thanks for the welcome
$endgroup$
– Artem Lugin
Apr 8 at 1:08
2
$begingroup$
I can't accept your edit as it contains improper grammar and is inaccurate. I'm open to suggestions and edits to improve understandability
$endgroup$
– Artem Lugin
Apr 8 at 1:19
1
$begingroup$
I think the question is clear enough, perhaps some terminology can be fixed but at least I can tell what’s being asked
$endgroup$
– PiIsNot3
Apr 8 at 1:32
|
show 4 more comments
$begingroup$
Every move in chess involves moving a piece to a square. Let us call this square the "move-square" for that turn.
In the following, the move-square of the black player must be symmetrical (over the obvious center-horizontal) to the move-square by white on that turn. The requirements may be met with a white move, but an additional valid move for black must be shown to exist. This extra move is not included when counting the number of moves taken to reach one of the below conditions.
What is the shortest sequence (with symmetrical move-squares) resulting in a Rook x Rook capture?
Resulting in a Knight x Rook capture?
Resulting in Queen x Bishop capture?
chess checkerboard knight-moves
New contributor
$endgroup$
Every move in chess involves moving a piece to a square. Let us call this square the "move-square" for that turn.
In the following, the move-square of the black player must be symmetrical (over the obvious center-horizontal) to the move-square by white on that turn. The requirements may be met with a white move, but an additional valid move for black must be shown to exist. This extra move is not included when counting the number of moves taken to reach one of the below conditions.
What is the shortest sequence (with symmetrical move-squares) resulting in a Rook x Rook capture?
Resulting in a Knight x Rook capture?
Resulting in Queen x Bishop capture?
chess checkerboard knight-moves
chess checkerboard knight-moves
New contributor
New contributor
edited Apr 8 at 1:47
Brandon_J
3,712245
3,712245
New contributor
asked Apr 8 at 0:48
Artem LuginArtem Lugin
38510
38510
New contributor
New contributor
$begingroup$
Hi @ArtemLugin, welcome to Puzzling SE! (Take the tour if you haven't already!) Can you clarify if the same piece has to occupy black's move-square as white's, or can any piece count? For example, would something like 1. e4 e5 2. Be2 Ne2 be acceptable? Or is only Be7 by black possible?
$endgroup$
– PiIsNot3
Apr 8 at 0:59
1
$begingroup$
@PiIsNot3 Its doesn't have to be the same piece. Only the corresponding symmetric square. Assuming you mean Ne7 not Ne2 yes, thats acceptable
$endgroup$
– Artem Lugin
Apr 8 at 1:08
1
$begingroup$
Thanks for the welcome
$endgroup$
– Artem Lugin
Apr 8 at 1:08
2
$begingroup$
I can't accept your edit as it contains improper grammar and is inaccurate. I'm open to suggestions and edits to improve understandability
$endgroup$
– Artem Lugin
Apr 8 at 1:19
1
$begingroup$
I think the question is clear enough, perhaps some terminology can be fixed but at least I can tell what’s being asked
$endgroup$
– PiIsNot3
Apr 8 at 1:32
|
show 4 more comments
$begingroup$
Hi @ArtemLugin, welcome to Puzzling SE! (Take the tour if you haven't already!) Can you clarify if the same piece has to occupy black's move-square as white's, or can any piece count? For example, would something like 1. e4 e5 2. Be2 Ne2 be acceptable? Or is only Be7 by black possible?
$endgroup$
– PiIsNot3
Apr 8 at 0:59
1
$begingroup$
@PiIsNot3 Its doesn't have to be the same piece. Only the corresponding symmetric square. Assuming you mean Ne7 not Ne2 yes, thats acceptable
$endgroup$
– Artem Lugin
Apr 8 at 1:08
1
$begingroup$
Thanks for the welcome
$endgroup$
– Artem Lugin
Apr 8 at 1:08
2
$begingroup$
I can't accept your edit as it contains improper grammar and is inaccurate. I'm open to suggestions and edits to improve understandability
$endgroup$
– Artem Lugin
Apr 8 at 1:19
1
$begingroup$
I think the question is clear enough, perhaps some terminology can be fixed but at least I can tell what’s being asked
$endgroup$
– PiIsNot3
Apr 8 at 1:32
$begingroup$
Hi @ArtemLugin, welcome to Puzzling SE! (Take the tour if you haven't already!) Can you clarify if the same piece has to occupy black's move-square as white's, or can any piece count? For example, would something like 1. e4 e5 2. Be2 Ne2 be acceptable? Or is only Be7 by black possible?
$endgroup$
– PiIsNot3
Apr 8 at 0:59
$begingroup$
Hi @ArtemLugin, welcome to Puzzling SE! (Take the tour if you haven't already!) Can you clarify if the same piece has to occupy black's move-square as white's, or can any piece count? For example, would something like 1. e4 e5 2. Be2 Ne2 be acceptable? Or is only Be7 by black possible?
$endgroup$
– PiIsNot3
Apr 8 at 0:59
1
1
$begingroup$
@PiIsNot3 Its doesn't have to be the same piece. Only the corresponding symmetric square. Assuming you mean Ne7 not Ne2 yes, thats acceptable
$endgroup$
– Artem Lugin
Apr 8 at 1:08
$begingroup$
@PiIsNot3 Its doesn't have to be the same piece. Only the corresponding symmetric square. Assuming you mean Ne7 not Ne2 yes, thats acceptable
$endgroup$
– Artem Lugin
Apr 8 at 1:08
1
1
$begingroup$
Thanks for the welcome
$endgroup$
– Artem Lugin
Apr 8 at 1:08
$begingroup$
Thanks for the welcome
$endgroup$
– Artem Lugin
Apr 8 at 1:08
2
2
$begingroup$
I can't accept your edit as it contains improper grammar and is inaccurate. I'm open to suggestions and edits to improve understandability
$endgroup$
– Artem Lugin
Apr 8 at 1:19
$begingroup$
I can't accept your edit as it contains improper grammar and is inaccurate. I'm open to suggestions and edits to improve understandability
$endgroup$
– Artem Lugin
Apr 8 at 1:19
1
1
$begingroup$
I think the question is clear enough, perhaps some terminology can be fixed but at least I can tell what’s being asked
$endgroup$
– PiIsNot3
Apr 8 at 1:32
$begingroup$
I think the question is clear enough, perhaps some terminology can be fixed but at least I can tell what’s being asked
$endgroup$
– PiIsNot3
Apr 8 at 1:32
|
show 4 more comments
2 Answers
2
active
oldest
votes
$begingroup$
Partial (will update as I go)
R x R (3rd attempt)
I got it! 5 moves:
1. a4 a5 2. Ra3 Ra6 3. Rh3 Rh6 4. d3 d6 5. Rxh6 Apronus link
The h3 square is covered by the black bishop.
Note that 5 is the absolute minimum number of moves needed, since it takes at least 3 moves to make the rooks attack each other, and they can’t directly take each other on the 4th move.
R x R (2nd attempt)
I found a 6 move solution:
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. c3 Nc6 5. Rb5 Nb4 6. cxb4 Rxb5
Apronus link
R x R (1st attempt)
This question demonstrates a 7 move sequence, but since we don’t have to copy each others’ moves, only the squares, we can also do the more interesting
1. a4 a5 2. Ra3 Ra6 3. Rc3 Nc6 4. e4 Ne5 5. Rc5 Nc4 6. c3 Rc6 7. Bxc4 Rxc5
Apronus link
$endgroup$
$begingroup$
You're on the right track. There are several ways to get it in 5 moves with white capturing the piece
$endgroup$
– Artem Lugin
Apr 8 at 2:30
$begingroup$
The question you linked was the inspiration. Thought I'd spice it up. a-Rook takes h-rook looks very interesting as well
$endgroup$
– Artem Lugin
Apr 8 at 2:36
$begingroup$
I don’t see any alternative for black here....help please.
$endgroup$
– Rewan Demontay
Apr 8 at 2:43
$begingroup$
Great job! Marked as correct
$endgroup$
– Artem Lugin
Apr 8 at 2:51
$begingroup$
@ArtemLugin While you're free to Accept whichever answer you think best addresses the puzzle, it's a bit unclear why you would select one that only answers one of the three parts of your question. Did you mean to pick this one?
$endgroup$
– Rubio♦
Apr 8 at 5:22
|
show 2 more comments
$begingroup$
Under your rules, here are my answers.
Rook X Rook:
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rgxh8
Proof Game:
Apronus
Knight X Rook:
1. Nf3 Nf6 2. Nh4 Nh5 3. Ng6 Ng3 4. Nxh8
Proof Game:
Apronus
Queen X Bishop:
1. e4 e5 2. d4 d5 3. Bg5 Bg4 4. Qxg4
Proof Game:
Apronus
UPDATE: Do you mean improve my Rook X Rook game like this?
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. Rxb6
Proof Game:
https://www.apronus.com/chess/pgnviewer/?m=a4_a5_Ra3_Ra6_Rb3_Rb6_Rxb6
$endgroup$
$begingroup$
The game only has to end with one side capturing. So therefore it is correct.
$endgroup$
– Rewan Demontay
Apr 8 at 1:32
1
$begingroup$
Fixed. Your point has been well recievedl
$endgroup$
– Rewan Demontay
Apr 8 at 1:35
$begingroup$
True, but generally any variant will suffice.
$endgroup$
– Rewan Demontay
Apr 8 at 1:57
1
$begingroup$
Oooh, I found one I really like. Looks kind of flashy IMO: 1.e4 e5 2. Qe2 Be7 3. Qb5 Bb4 4. Qxb4
$endgroup$
– Brandon_J
Apr 8 at 2:03
2
$begingroup$
The shortest is 5 white moves
$endgroup$
– Artem Lugin
Apr 8 at 2:28
|
show 10 more comments
Your Answer
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2 Answers
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2 Answers
2
active
oldest
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active
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oldest
votes
$begingroup$
Partial (will update as I go)
R x R (3rd attempt)
I got it! 5 moves:
1. a4 a5 2. Ra3 Ra6 3. Rh3 Rh6 4. d3 d6 5. Rxh6 Apronus link
The h3 square is covered by the black bishop.
Note that 5 is the absolute minimum number of moves needed, since it takes at least 3 moves to make the rooks attack each other, and they can’t directly take each other on the 4th move.
R x R (2nd attempt)
I found a 6 move solution:
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. c3 Nc6 5. Rb5 Nb4 6. cxb4 Rxb5
Apronus link
R x R (1st attempt)
This question demonstrates a 7 move sequence, but since we don’t have to copy each others’ moves, only the squares, we can also do the more interesting
1. a4 a5 2. Ra3 Ra6 3. Rc3 Nc6 4. e4 Ne5 5. Rc5 Nc4 6. c3 Rc6 7. Bxc4 Rxc5
Apronus link
$endgroup$
$begingroup$
You're on the right track. There are several ways to get it in 5 moves with white capturing the piece
$endgroup$
– Artem Lugin
Apr 8 at 2:30
$begingroup$
The question you linked was the inspiration. Thought I'd spice it up. a-Rook takes h-rook looks very interesting as well
$endgroup$
– Artem Lugin
Apr 8 at 2:36
$begingroup$
I don’t see any alternative for black here....help please.
$endgroup$
– Rewan Demontay
Apr 8 at 2:43
$begingroup$
Great job! Marked as correct
$endgroup$
– Artem Lugin
Apr 8 at 2:51
$begingroup$
@ArtemLugin While you're free to Accept whichever answer you think best addresses the puzzle, it's a bit unclear why you would select one that only answers one of the three parts of your question. Did you mean to pick this one?
$endgroup$
– Rubio♦
Apr 8 at 5:22
|
show 2 more comments
$begingroup$
Partial (will update as I go)
R x R (3rd attempt)
I got it! 5 moves:
1. a4 a5 2. Ra3 Ra6 3. Rh3 Rh6 4. d3 d6 5. Rxh6 Apronus link
The h3 square is covered by the black bishop.
Note that 5 is the absolute minimum number of moves needed, since it takes at least 3 moves to make the rooks attack each other, and they can’t directly take each other on the 4th move.
R x R (2nd attempt)
I found a 6 move solution:
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. c3 Nc6 5. Rb5 Nb4 6. cxb4 Rxb5
Apronus link
R x R (1st attempt)
This question demonstrates a 7 move sequence, but since we don’t have to copy each others’ moves, only the squares, we can also do the more interesting
1. a4 a5 2. Ra3 Ra6 3. Rc3 Nc6 4. e4 Ne5 5. Rc5 Nc4 6. c3 Rc6 7. Bxc4 Rxc5
Apronus link
$endgroup$
$begingroup$
You're on the right track. There are several ways to get it in 5 moves with white capturing the piece
$endgroup$
– Artem Lugin
Apr 8 at 2:30
$begingroup$
The question you linked was the inspiration. Thought I'd spice it up. a-Rook takes h-rook looks very interesting as well
$endgroup$
– Artem Lugin
Apr 8 at 2:36
$begingroup$
I don’t see any alternative for black here....help please.
$endgroup$
– Rewan Demontay
Apr 8 at 2:43
$begingroup$
Great job! Marked as correct
$endgroup$
– Artem Lugin
Apr 8 at 2:51
$begingroup$
@ArtemLugin While you're free to Accept whichever answer you think best addresses the puzzle, it's a bit unclear why you would select one that only answers one of the three parts of your question. Did you mean to pick this one?
$endgroup$
– Rubio♦
Apr 8 at 5:22
|
show 2 more comments
$begingroup$
Partial (will update as I go)
R x R (3rd attempt)
I got it! 5 moves:
1. a4 a5 2. Ra3 Ra6 3. Rh3 Rh6 4. d3 d6 5. Rxh6 Apronus link
The h3 square is covered by the black bishop.
Note that 5 is the absolute minimum number of moves needed, since it takes at least 3 moves to make the rooks attack each other, and they can’t directly take each other on the 4th move.
R x R (2nd attempt)
I found a 6 move solution:
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. c3 Nc6 5. Rb5 Nb4 6. cxb4 Rxb5
Apronus link
R x R (1st attempt)
This question demonstrates a 7 move sequence, but since we don’t have to copy each others’ moves, only the squares, we can also do the more interesting
1. a4 a5 2. Ra3 Ra6 3. Rc3 Nc6 4. e4 Ne5 5. Rc5 Nc4 6. c3 Rc6 7. Bxc4 Rxc5
Apronus link
$endgroup$
Partial (will update as I go)
R x R (3rd attempt)
I got it! 5 moves:
1. a4 a5 2. Ra3 Ra6 3. Rh3 Rh6 4. d3 d6 5. Rxh6 Apronus link
The h3 square is covered by the black bishop.
Note that 5 is the absolute minimum number of moves needed, since it takes at least 3 moves to make the rooks attack each other, and they can’t directly take each other on the 4th move.
R x R (2nd attempt)
I found a 6 move solution:
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. c3 Nc6 5. Rb5 Nb4 6. cxb4 Rxb5
Apronus link
R x R (1st attempt)
This question demonstrates a 7 move sequence, but since we don’t have to copy each others’ moves, only the squares, we can also do the more interesting
1. a4 a5 2. Ra3 Ra6 3. Rc3 Nc6 4. e4 Ne5 5. Rc5 Nc4 6. c3 Rc6 7. Bxc4 Rxc5
Apronus link
edited Apr 8 at 2:37
answered Apr 8 at 1:24
PiIsNot3PiIsNot3
2,512437
2,512437
$begingroup$
You're on the right track. There are several ways to get it in 5 moves with white capturing the piece
$endgroup$
– Artem Lugin
Apr 8 at 2:30
$begingroup$
The question you linked was the inspiration. Thought I'd spice it up. a-Rook takes h-rook looks very interesting as well
$endgroup$
– Artem Lugin
Apr 8 at 2:36
$begingroup$
I don’t see any alternative for black here....help please.
$endgroup$
– Rewan Demontay
Apr 8 at 2:43
$begingroup$
Great job! Marked as correct
$endgroup$
– Artem Lugin
Apr 8 at 2:51
$begingroup$
@ArtemLugin While you're free to Accept whichever answer you think best addresses the puzzle, it's a bit unclear why you would select one that only answers one of the three parts of your question. Did you mean to pick this one?
$endgroup$
– Rubio♦
Apr 8 at 5:22
|
show 2 more comments
$begingroup$
You're on the right track. There are several ways to get it in 5 moves with white capturing the piece
$endgroup$
– Artem Lugin
Apr 8 at 2:30
$begingroup$
The question you linked was the inspiration. Thought I'd spice it up. a-Rook takes h-rook looks very interesting as well
$endgroup$
– Artem Lugin
Apr 8 at 2:36
$begingroup$
I don’t see any alternative for black here....help please.
$endgroup$
– Rewan Demontay
Apr 8 at 2:43
$begingroup$
Great job! Marked as correct
$endgroup$
– Artem Lugin
Apr 8 at 2:51
$begingroup$
@ArtemLugin While you're free to Accept whichever answer you think best addresses the puzzle, it's a bit unclear why you would select one that only answers one of the three parts of your question. Did you mean to pick this one?
$endgroup$
– Rubio♦
Apr 8 at 5:22
$begingroup$
You're on the right track. There are several ways to get it in 5 moves with white capturing the piece
$endgroup$
– Artem Lugin
Apr 8 at 2:30
$begingroup$
You're on the right track. There are several ways to get it in 5 moves with white capturing the piece
$endgroup$
– Artem Lugin
Apr 8 at 2:30
$begingroup$
The question you linked was the inspiration. Thought I'd spice it up. a-Rook takes h-rook looks very interesting as well
$endgroup$
– Artem Lugin
Apr 8 at 2:36
$begingroup$
The question you linked was the inspiration. Thought I'd spice it up. a-Rook takes h-rook looks very interesting as well
$endgroup$
– Artem Lugin
Apr 8 at 2:36
$begingroup$
I don’t see any alternative for black here....help please.
$endgroup$
– Rewan Demontay
Apr 8 at 2:43
$begingroup$
I don’t see any alternative for black here....help please.
$endgroup$
– Rewan Demontay
Apr 8 at 2:43
$begingroup$
Great job! Marked as correct
$endgroup$
– Artem Lugin
Apr 8 at 2:51
$begingroup$
Great job! Marked as correct
$endgroup$
– Artem Lugin
Apr 8 at 2:51
$begingroup$
@ArtemLugin While you're free to Accept whichever answer you think best addresses the puzzle, it's a bit unclear why you would select one that only answers one of the three parts of your question. Did you mean to pick this one?
$endgroup$
– Rubio♦
Apr 8 at 5:22
$begingroup$
@ArtemLugin While you're free to Accept whichever answer you think best addresses the puzzle, it's a bit unclear why you would select one that only answers one of the three parts of your question. Did you mean to pick this one?
$endgroup$
– Rubio♦
Apr 8 at 5:22
|
show 2 more comments
$begingroup$
Under your rules, here are my answers.
Rook X Rook:
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rgxh8
Proof Game:
Apronus
Knight X Rook:
1. Nf3 Nf6 2. Nh4 Nh5 3. Ng6 Ng3 4. Nxh8
Proof Game:
Apronus
Queen X Bishop:
1. e4 e5 2. d4 d5 3. Bg5 Bg4 4. Qxg4
Proof Game:
Apronus
UPDATE: Do you mean improve my Rook X Rook game like this?
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. Rxb6
Proof Game:
https://www.apronus.com/chess/pgnviewer/?m=a4_a5_Ra3_Ra6_Rb3_Rb6_Rxb6
$endgroup$
$begingroup$
The game only has to end with one side capturing. So therefore it is correct.
$endgroup$
– Rewan Demontay
Apr 8 at 1:32
1
$begingroup$
Fixed. Your point has been well recievedl
$endgroup$
– Rewan Demontay
Apr 8 at 1:35
$begingroup$
True, but generally any variant will suffice.
$endgroup$
– Rewan Demontay
Apr 8 at 1:57
1
$begingroup$
Oooh, I found one I really like. Looks kind of flashy IMO: 1.e4 e5 2. Qe2 Be7 3. Qb5 Bb4 4. Qxb4
$endgroup$
– Brandon_J
Apr 8 at 2:03
2
$begingroup$
The shortest is 5 white moves
$endgroup$
– Artem Lugin
Apr 8 at 2:28
|
show 10 more comments
$begingroup$
Under your rules, here are my answers.
Rook X Rook:
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rgxh8
Proof Game:
Apronus
Knight X Rook:
1. Nf3 Nf6 2. Nh4 Nh5 3. Ng6 Ng3 4. Nxh8
Proof Game:
Apronus
Queen X Bishop:
1. e4 e5 2. d4 d5 3. Bg5 Bg4 4. Qxg4
Proof Game:
Apronus
UPDATE: Do you mean improve my Rook X Rook game like this?
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. Rxb6
Proof Game:
https://www.apronus.com/chess/pgnviewer/?m=a4_a5_Ra3_Ra6_Rb3_Rb6_Rxb6
$endgroup$
$begingroup$
The game only has to end with one side capturing. So therefore it is correct.
$endgroup$
– Rewan Demontay
Apr 8 at 1:32
1
$begingroup$
Fixed. Your point has been well recievedl
$endgroup$
– Rewan Demontay
Apr 8 at 1:35
$begingroup$
True, but generally any variant will suffice.
$endgroup$
– Rewan Demontay
Apr 8 at 1:57
1
$begingroup$
Oooh, I found one I really like. Looks kind of flashy IMO: 1.e4 e5 2. Qe2 Be7 3. Qb5 Bb4 4. Qxb4
$endgroup$
– Brandon_J
Apr 8 at 2:03
2
$begingroup$
The shortest is 5 white moves
$endgroup$
– Artem Lugin
Apr 8 at 2:28
|
show 10 more comments
$begingroup$
Under your rules, here are my answers.
Rook X Rook:
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rgxh8
Proof Game:
Apronus
Knight X Rook:
1. Nf3 Nf6 2. Nh4 Nh5 3. Ng6 Ng3 4. Nxh8
Proof Game:
Apronus
Queen X Bishop:
1. e4 e5 2. d4 d5 3. Bg5 Bg4 4. Qxg4
Proof Game:
Apronus
UPDATE: Do you mean improve my Rook X Rook game like this?
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. Rxb6
Proof Game:
https://www.apronus.com/chess/pgnviewer/?m=a4_a5_Ra3_Ra6_Rb3_Rb6_Rxb6
$endgroup$
Under your rules, here are my answers.
Rook X Rook:
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rgxh8
Proof Game:
Apronus
Knight X Rook:
1. Nf3 Nf6 2. Nh4 Nh5 3. Ng6 Ng3 4. Nxh8
Proof Game:
Apronus
Queen X Bishop:
1. e4 e5 2. d4 d5 3. Bg5 Bg4 4. Qxg4
Proof Game:
Apronus
UPDATE: Do you mean improve my Rook X Rook game like this?
1. a4 a5 2. Ra3 Ra6 3. Rb3 Rb6 4. Rxb6
Proof Game:
https://www.apronus.com/chess/pgnviewer/?m=a4_a5_Ra3_Ra6_Rb3_Rb6_Rxb6
edited Apr 8 at 2:17
answered Apr 8 at 1:26
Rewan DemontayRewan Demontay
69415
69415
$begingroup$
The game only has to end with one side capturing. So therefore it is correct.
$endgroup$
– Rewan Demontay
Apr 8 at 1:32
1
$begingroup$
Fixed. Your point has been well recievedl
$endgroup$
– Rewan Demontay
Apr 8 at 1:35
$begingroup$
True, but generally any variant will suffice.
$endgroup$
– Rewan Demontay
Apr 8 at 1:57
1
$begingroup$
Oooh, I found one I really like. Looks kind of flashy IMO: 1.e4 e5 2. Qe2 Be7 3. Qb5 Bb4 4. Qxb4
$endgroup$
– Brandon_J
Apr 8 at 2:03
2
$begingroup$
The shortest is 5 white moves
$endgroup$
– Artem Lugin
Apr 8 at 2:28
|
show 10 more comments
$begingroup$
The game only has to end with one side capturing. So therefore it is correct.
$endgroup$
– Rewan Demontay
Apr 8 at 1:32
1
$begingroup$
Fixed. Your point has been well recievedl
$endgroup$
– Rewan Demontay
Apr 8 at 1:35
$begingroup$
True, but generally any variant will suffice.
$endgroup$
– Rewan Demontay
Apr 8 at 1:57
1
$begingroup$
Oooh, I found one I really like. Looks kind of flashy IMO: 1.e4 e5 2. Qe2 Be7 3. Qb5 Bb4 4. Qxb4
$endgroup$
– Brandon_J
Apr 8 at 2:03
2
$begingroup$
The shortest is 5 white moves
$endgroup$
– Artem Lugin
Apr 8 at 2:28
$begingroup$
The game only has to end with one side capturing. So therefore it is correct.
$endgroup$
– Rewan Demontay
Apr 8 at 1:32
$begingroup$
The game only has to end with one side capturing. So therefore it is correct.
$endgroup$
– Rewan Demontay
Apr 8 at 1:32
1
1
$begingroup$
Fixed. Your point has been well recievedl
$endgroup$
– Rewan Demontay
Apr 8 at 1:35
$begingroup$
Fixed. Your point has been well recievedl
$endgroup$
– Rewan Demontay
Apr 8 at 1:35
$begingroup$
True, but generally any variant will suffice.
$endgroup$
– Rewan Demontay
Apr 8 at 1:57
$begingroup$
True, but generally any variant will suffice.
$endgroup$
– Rewan Demontay
Apr 8 at 1:57
1
1
$begingroup$
Oooh, I found one I really like. Looks kind of flashy IMO: 1.e4 e5 2. Qe2 Be7 3. Qb5 Bb4 4. Qxb4
$endgroup$
– Brandon_J
Apr 8 at 2:03
$begingroup$
Oooh, I found one I really like. Looks kind of flashy IMO: 1.e4 e5 2. Qe2 Be7 3. Qb5 Bb4 4. Qxb4
$endgroup$
– Brandon_J
Apr 8 at 2:03
2
2
$begingroup$
The shortest is 5 white moves
$endgroup$
– Artem Lugin
Apr 8 at 2:28
$begingroup$
The shortest is 5 white moves
$endgroup$
– Artem Lugin
Apr 8 at 2:28
|
show 10 more comments
Artem Lugin is a new contributor. Be nice, and check out our Code of Conduct.
Artem Lugin is a new contributor. Be nice, and check out our Code of Conduct.
Artem Lugin is a new contributor. Be nice, and check out our Code of Conduct.
Artem Lugin is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Hi @ArtemLugin, welcome to Puzzling SE! (Take the tour if you haven't already!) Can you clarify if the same piece has to occupy black's move-square as white's, or can any piece count? For example, would something like 1. e4 e5 2. Be2 Ne2 be acceptable? Or is only Be7 by black possible?
$endgroup$
– PiIsNot3
Apr 8 at 0:59
1
$begingroup$
@PiIsNot3 Its doesn't have to be the same piece. Only the corresponding symmetric square. Assuming you mean Ne7 not Ne2 yes, thats acceptable
$endgroup$
– Artem Lugin
Apr 8 at 1:08
1
$begingroup$
Thanks for the welcome
$endgroup$
– Artem Lugin
Apr 8 at 1:08
2
$begingroup$
I can't accept your edit as it contains improper grammar and is inaccurate. I'm open to suggestions and edits to improve understandability
$endgroup$
– Artem Lugin
Apr 8 at 1:19
1
$begingroup$
I think the question is clear enough, perhaps some terminology can be fixed but at least I can tell what’s being asked
$endgroup$
– PiIsNot3
Apr 8 at 1:32