How to get the end in algorithm2e The Next CEO of Stack OverflowEnd word is hidden in algorithm blockalgorithm2e problemRemove “end” in algorithm2eHow to resolve the error: “Missing { inserted.” inside an algorithm2eMissing end statement in algorithm2e environmentIndent the block with the algorithm2e usepackageWrite the else if block with algorithm2eHow to get a “tight” boxed algorithm with the algorithm2e packagealgorithm2e - Undefined control sequence. endHow to show up “end” in algorithm2e?Remove the semicolon at the end of the line (algorithm2e)
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How to get the end in algorithm2e
The Next CEO of Stack OverflowEnd word is hidden in algorithm blockalgorithm2e problemRemove “end” in algorithm2eHow to resolve the error: “Missing { inserted.” inside an algorithm2eMissing end statement in algorithm2e environmentIndent the block with the algorithm2e usepackageWrite the else if block with algorithm2eHow to get a “tight” boxed algorithm with the algorithm2e packagealgorithm2e - Undefined control sequence. endHow to show up “end” in algorithm2e?Remove the semicolon at the end of the line (algorithm2e)
I am using algorithm2e to typeset an algorithm. I like the appearance of the following, but I am not able to get the end to close the `
begin
`. Any way to do this?
documentclassarticle
usepackage[longend,ruled,vlined]algorithm2e
begindocument
beginalgorithm
captionPHORIZONTAL Algorithmlabelalg:phorizontal
KwIn$R$: relation; $Pr$: set of simple predicates
KwOut$F_R$: set of horizontal fragments of $R$
Begin
$Pr' leftarrow $COM_MIN($R, Pr$) ;
determine the set $M$ of minterm predicates ;
determine the set $I$ of implications among $p_i in Pr'$ ;
ForEach$m_i in M$
If $m_i$ is contradictory according to $I$$M leftarrow M - m_i$
$F_R = sigma_m_i R, m_i in M, forall m_i in M$ ;
endalgorithm
enddocument
algorithm2e
asked 2 days ago
ozsuozsu
1,13111126
add a comment |
I am using algorithm2e to typeset an algorithm. I like the appearance of the following, but I am not able to get the end to close the `
begin
`. Any way to do this?
documentclassarticle
usepackage[longend,ruled,vlined]algorithm2e
begindocument
beginalgorithm
captionPHORIZONTAL Algorithmlabelalg:phorizontal
KwIn$R$: relation; $Pr$: set of simple predicates
KwOut$F_R$: set of horizontal fragments of $R$
Begin
$Pr' leftarrow $COM_MIN($R, Pr$) ;
determine the set $M$ of minterm predicates ;
determine the set $I$ of implications among $p_i in Pr'$ ;
ForEach$m_i in M$
If $m_i$ is contradictory according to $I$$M leftarrow M - m_i$
$F_R = sigma_m_i R, m_i in M, forall m_i in M$ ;
endalgorithm
enddocument
algorithm2e
asked 2 days ago
ozsuozsu
1,13111126
PlaceSetAlgoLinedat the inception point of your algorithm.
– Siba Mishra
2 days ago
THanks. Will try that as well.
– ozsu
2 days ago
add a comment |
I am using algorithm2e to typeset an algorithm. I like the appearance of the following, but I am not able to get the end to close the `
begin
`. Any way to do this?
documentclassarticle
usepackage[longend,ruled,vlined]algorithm2e
begindocument
beginalgorithm
captionPHORIZONTAL Algorithmlabelalg:phorizontal
KwIn$R$: relation; $Pr$: set of simple predicates
KwOut$F_R$: set of horizontal fragments of $R$
Begin
$Pr' leftarrow $COM_MIN($R, Pr$) ;
determine the set $M$ of minterm predicates ;
determine the set $I$ of implications among $p_i in Pr'$ ;
ForEach$m_i in M$
If $m_i$ is contradictory according to $I$$M leftarrow M - m_i$
$F_R = sigma_m_i R, m_i in M, forall m_i in M$ ;
endalgorithm
enddocument
algorithm2e
asked 2 days ago
ozsuozsu
1,13111126
I am using algorithm2e to typeset an algorithm. I like the appearance of the following, but I am not able to get the end to close the `
begin
`. Any way to do this?
documentclassarticle
usepackage[longend,ruled,vlined]algorithm2e
begindocument
beginalgorithm
captionPHORIZONTAL Algorithmlabelalg:phorizontal
KwIn$R$: relation; $Pr$: set of simple predicates
KwOut$F_R$: set of horizontal fragments of $R$
Begin
$Pr' leftarrow $COM_MIN($R, Pr$) ;
determine the set $M$ of minterm predicates ;
determine the set $I$ of implications among $p_i in Pr'$ ;
ForEach$m_i in M$
If $m_i$ is contradictory according to $I$$M leftarrow M - m_i$
$F_R = sigma_m_i R, m_i in M, forall m_i in M$ ;
endalgorithm
enddocument
algorithm2e
algorithm2e
asked 2 days ago
ozsuozsu
1,13111126
asked 2 days ago
ozsuozsu
1,13111126
asked 2 days ago
ozsuozsu
1,13111126
asked 2 days ago
ozsuozsu
1,13111126
asked 2 days ago
ozsuozsu
1,13111126
1,13111126
PlaceSetAlgoLinedat the inception point of your algorithm.
– Siba Mishra
2 days ago
THanks. Will try that as well.
– ozsu
2 days ago
add a comment |
PlaceSetAlgoLinedat the inception point of your algorithm.
– Siba Mishra
2 days ago
THanks. Will try that as well.
– ozsu
2 days ago
Place
SetAlgoLined at the inception point of your algorithm.– Siba Mishra
2 days ago
Place
SetAlgoLined at the inception point of your algorithm.– Siba Mishra
2 days ago
THanks. Will try that as well.
– ozsu
2 days ago
THanks. Will try that as well.
– ozsu
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
Referring to the answert by @egreg in End word is hidden in algorithm block , the vlined option suppresses the printing of “end”. Just remove the option:
documentclassarticle
usepackage[longend,ruled]algorithm2e
begindocument
beginalgorithm
captionPHORIZONTAL Algorithmlabelalg:phorizontal
KwIn$R$: relation; $Pr$: set of simple predicates
KwOut$F_R$: set of horizontal fragments of $R$
Begin
$Pr' leftarrow $COM_MIN($R, Pr$) ;
determine the set $M$ of minterm predicates ;
determine the set $I$ of implications among $p_i in Pr'$ ;
ForEach$m_i in M$
If $m_i$ is contradictory according to $I$$M leftarrow M - m_i$
$F_R = sigma_m_i R, m_i in M, forall m_i in M$ ;
endalgorithm
enddocument
answered 2 days ago
subham sonisubham soni
4,86683187
Thank you. I was hoping I could keep both, but apparently that is not possible.
– ozsu
2 days ago
add a comment |
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1 Answer
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active
oldest
votes
Referring to the answert by @egreg in End word is hidden in algorithm block , the vlined option suppresses the printing of “end”. Just remove the option:
documentclassarticle
usepackage[longend,ruled]algorithm2e
begindocument
beginalgorithm
captionPHORIZONTAL Algorithmlabelalg:phorizontal
KwIn$R$: relation; $Pr$: set of simple predicates
KwOut$F_R$: set of horizontal fragments of $R$
Begin
$Pr' leftarrow $COM_MIN($R, Pr$) ;
determine the set $M$ of minterm predicates ;
determine the set $I$ of implications among $p_i in Pr'$ ;
ForEach$m_i in M$
If $m_i$ is contradictory according to $I$$M leftarrow M - m_i$
$F_R = sigma_m_i R, m_i in M, forall m_i in M$ ;
endalgorithm
enddocument
answered 2 days ago
subham sonisubham soni
4,86683187
Thank you. I was hoping I could keep both, but apparently that is not possible.
– ozsu
2 days ago
add a comment |
Referring to the answert by @egreg in End word is hidden in algorithm block , the vlined option suppresses the printing of “end”. Just remove the option:
documentclassarticle
usepackage[longend,ruled]algorithm2e
begindocument
beginalgorithm
captionPHORIZONTAL Algorithmlabelalg:phorizontal
KwIn$R$: relation; $Pr$: set of simple predicates
KwOut$F_R$: set of horizontal fragments of $R$
Begin
$Pr' leftarrow $COM_MIN($R, Pr$) ;
determine the set $M$ of minterm predicates ;
determine the set $I$ of implications among $p_i in Pr'$ ;
ForEach$m_i in M$
If $m_i$ is contradictory according to $I$$M leftarrow M - m_i$
$F_R = sigma_m_i R, m_i in M, forall m_i in M$ ;
endalgorithm
enddocument
answered 2 days ago
subham sonisubham soni
4,86683187
Thank you. I was hoping I could keep both, but apparently that is not possible.
– ozsu
2 days ago
add a comment |
Referring to the answert by @egreg in End word is hidden in algorithm block , the vlined option suppresses the printing of “end”. Just remove the option:
documentclassarticle
usepackage[longend,ruled]algorithm2e
begindocument
beginalgorithm
captionPHORIZONTAL Algorithmlabelalg:phorizontal
KwIn$R$: relation; $Pr$: set of simple predicates
KwOut$F_R$: set of horizontal fragments of $R$
Begin
$Pr' leftarrow $COM_MIN($R, Pr$) ;
determine the set $M$ of minterm predicates ;
determine the set $I$ of implications among $p_i in Pr'$ ;
ForEach$m_i in M$
If $m_i$ is contradictory according to $I$$M leftarrow M - m_i$
$F_R = sigma_m_i R, m_i in M, forall m_i in M$ ;
endalgorithm
enddocument
answered 2 days ago
subham sonisubham soni
4,86683187
Referring to the answert by @egreg in End word is hidden in algorithm block , the vlined option suppresses the printing of “end”. Just remove the option:
documentclassarticle
usepackage[longend,ruled]algorithm2e
begindocument
beginalgorithm
captionPHORIZONTAL Algorithmlabelalg:phorizontal
KwIn$R$: relation; $Pr$: set of simple predicates
KwOut$F_R$: set of horizontal fragments of $R$
Begin
$Pr' leftarrow $COM_MIN($R, Pr$) ;
determine the set $M$ of minterm predicates ;
determine the set $I$ of implications among $p_i in Pr'$ ;
ForEach$m_i in M$
If $m_i$ is contradictory according to $I$$M leftarrow M - m_i$
$F_R = sigma_m_i R, m_i in M, forall m_i in M$ ;
endalgorithm
enddocument
answered 2 days ago
subham sonisubham soni
4,86683187
answered 2 days ago
subham sonisubham soni
4,86683187
answered 2 days ago
subham sonisubham soni
4,86683187
answered 2 days ago
subham sonisubham soni
4,86683187
4,86683187
Thank you. I was hoping I could keep both, but apparently that is not possible.
– ozsu
2 days ago
add a comment |
Thank you. I was hoping I could keep both, but apparently that is not possible.
– ozsu
2 days ago
Thank you. I was hoping I could keep both, but apparently that is not possible.
– ozsu
2 days ago
Thank you. I was hoping I could keep both, but apparently that is not possible.
– ozsu
2 days ago
add a comment |
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Place
SetAlgoLinedat the inception point of your algorithm.– Siba Mishra
2 days ago
THanks. Will try that as well.
– ozsu
2 days ago