Detecting if an element is found inside a container The Next CEO of Stack Overflowcontains() algorithm for std::vectorSimple container class with templatesPolymorphic STL foreach without passing the container typeGeneric container assignmentC++11 Quicksort any containerTriple-type template containerCreating a custom template container class (vector alike)Shift an element in a circular containerNon-sequential template class container C++Internal Zip-like IteratorBasic binary number container
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Detecting if an element is found inside a container
The Next CEO of Stack Overflowcontains() algorithm for std::vectorSimple container class with templatesPolymorphic STL foreach without passing the container typeGeneric container assignmentC++11 Quicksort any containerTriple-type template containerCreating a custom template container class (vector alike)Shift an element in a circular containerNon-sequential template class container C++Internal Zip-like IteratorBasic binary number container
$begingroup$
I just wrote this template to detect if a given element is found inside a container:
template <typename Iterator> bool is_contained(Iterator begin, Iterator end, decltype(*begin) object)
for (; begin != end; ++begin)
if (*begin == object)
return true;
return false;
Which then would be called for examples as:
bool test = is_contained<decltype(container.begin())>(container.begin(), container.end(), anything);
This works fine, but I believe it is not so readable. I am also new to using decltype
which makes me wonder if this would crash, and somehow I wont be calling the template correctly. Any feedback is highly appreciated.
c++ beginner template
New contributor
$endgroup$
add a comment |
$begingroup$
I just wrote this template to detect if a given element is found inside a container:
template <typename Iterator> bool is_contained(Iterator begin, Iterator end, decltype(*begin) object)
for (; begin != end; ++begin)
if (*begin == object)
return true;
return false;
Which then would be called for examples as:
bool test = is_contained<decltype(container.begin())>(container.begin(), container.end(), anything);
This works fine, but I believe it is not so readable. I am also new to using decltype
which makes me wonder if this would crash, and somehow I wont be calling the template correctly. Any feedback is highly appreciated.
c++ beginner template
New contributor
$endgroup$
add a comment |
$begingroup$
I just wrote this template to detect if a given element is found inside a container:
template <typename Iterator> bool is_contained(Iterator begin, Iterator end, decltype(*begin) object)
for (; begin != end; ++begin)
if (*begin == object)
return true;
return false;
Which then would be called for examples as:
bool test = is_contained<decltype(container.begin())>(container.begin(), container.end(), anything);
This works fine, but I believe it is not so readable. I am also new to using decltype
which makes me wonder if this would crash, and somehow I wont be calling the template correctly. Any feedback is highly appreciated.
c++ beginner template
New contributor
$endgroup$
I just wrote this template to detect if a given element is found inside a container:
template <typename Iterator> bool is_contained(Iterator begin, Iterator end, decltype(*begin) object)
for (; begin != end; ++begin)
if (*begin == object)
return true;
return false;
Which then would be called for examples as:
bool test = is_contained<decltype(container.begin())>(container.begin(), container.end(), anything);
This works fine, but I believe it is not so readable. I am also new to using decltype
which makes me wonder if this would crash, and somehow I wont be calling the template correctly. Any feedback is highly appreciated.
c++ beginner template
c++ beginner template
New contributor
New contributor
New contributor
asked yesterday
Daniel DuqueDaniel Duque
555
555
New contributor
New contributor
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Note that for functions the compiler will detect the template types based on the parameters.
So you can simply write:
bool test = is_contained(container.begin(), container.end(), anything);
I don't particularly like the use of decltype
in your function. I would simply make it another template parameter.
template <typename Iterator, typename Value>
bool is_contained(Iterator begin, Iterator end, Value const& object);
Because of the compiler deducing the names you can use any type. Also this is more flexable as it allows you to use any type that is comparable to the type inside the container (rather than only allowing values that are the same type (or trivial convertible)).
$endgroup$
add a comment |
$begingroup$
Do you want to test whether an element is in a container, or an iterator-range?
- The first allows for optimisation (taking advantage of the container's peculiarities). See "contains() algorithm for std::vector" for an example.
- The second is more general in the absence of any range-library, like the one expected for the C++20 standard, and available for earlier versions.
Constraining the needle to the type
decltype(*begin)
is very problematic:- It forces pass-by-value, which while it should be possible, at least with moveing, might be inefficient.
- You cannot take advantage of transparent comparators (a C++14 feature), forcing the creation of a useless temporary. On the flip-side, if transparent comparators are not used, only a single temporary is constructed.
- If the type is a proxy like with the dreaded
std::vector <bool>
, hilarity ensues.
Consider taking advantage of the standard library, specifically
std::find ()
.C++ will deduce the function's template-arguments perfectly fine, no need for error-prone verbosity.
$endgroup$
$begingroup$
On point 2, it's even worse: you can't pass a value that's convertible todecltype(*begin)
, because templates need exact matches.
$endgroup$
– Toby Speight
4 hours ago
add a comment |
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2 Answers
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active
oldest
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2 Answers
2
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
Note that for functions the compiler will detect the template types based on the parameters.
So you can simply write:
bool test = is_contained(container.begin(), container.end(), anything);
I don't particularly like the use of decltype
in your function. I would simply make it another template parameter.
template <typename Iterator, typename Value>
bool is_contained(Iterator begin, Iterator end, Value const& object);
Because of the compiler deducing the names you can use any type. Also this is more flexable as it allows you to use any type that is comparable to the type inside the container (rather than only allowing values that are the same type (or trivial convertible)).
$endgroup$
add a comment |
$begingroup$
Note that for functions the compiler will detect the template types based on the parameters.
So you can simply write:
bool test = is_contained(container.begin(), container.end(), anything);
I don't particularly like the use of decltype
in your function. I would simply make it another template parameter.
template <typename Iterator, typename Value>
bool is_contained(Iterator begin, Iterator end, Value const& object);
Because of the compiler deducing the names you can use any type. Also this is more flexable as it allows you to use any type that is comparable to the type inside the container (rather than only allowing values that are the same type (or trivial convertible)).
$endgroup$
add a comment |
$begingroup$
Note that for functions the compiler will detect the template types based on the parameters.
So you can simply write:
bool test = is_contained(container.begin(), container.end(), anything);
I don't particularly like the use of decltype
in your function. I would simply make it another template parameter.
template <typename Iterator, typename Value>
bool is_contained(Iterator begin, Iterator end, Value const& object);
Because of the compiler deducing the names you can use any type. Also this is more flexable as it allows you to use any type that is comparable to the type inside the container (rather than only allowing values that are the same type (or trivial convertible)).
$endgroup$
Note that for functions the compiler will detect the template types based on the parameters.
So you can simply write:
bool test = is_contained(container.begin(), container.end(), anything);
I don't particularly like the use of decltype
in your function. I would simply make it another template parameter.
template <typename Iterator, typename Value>
bool is_contained(Iterator begin, Iterator end, Value const& object);
Because of the compiler deducing the names you can use any type. Also this is more flexable as it allows you to use any type that is comparable to the type inside the container (rather than only allowing values that are the same type (or trivial convertible)).
answered yesterday
Martin YorkMartin York
74.1k488272
74.1k488272
add a comment |
add a comment |
$begingroup$
Do you want to test whether an element is in a container, or an iterator-range?
- The first allows for optimisation (taking advantage of the container's peculiarities). See "contains() algorithm for std::vector" for an example.
- The second is more general in the absence of any range-library, like the one expected for the C++20 standard, and available for earlier versions.
Constraining the needle to the type
decltype(*begin)
is very problematic:- It forces pass-by-value, which while it should be possible, at least with moveing, might be inefficient.
- You cannot take advantage of transparent comparators (a C++14 feature), forcing the creation of a useless temporary. On the flip-side, if transparent comparators are not used, only a single temporary is constructed.
- If the type is a proxy like with the dreaded
std::vector <bool>
, hilarity ensues.
Consider taking advantage of the standard library, specifically
std::find ()
.C++ will deduce the function's template-arguments perfectly fine, no need for error-prone verbosity.
$endgroup$
$begingroup$
On point 2, it's even worse: you can't pass a value that's convertible todecltype(*begin)
, because templates need exact matches.
$endgroup$
– Toby Speight
4 hours ago
add a comment |
$begingroup$
Do you want to test whether an element is in a container, or an iterator-range?
- The first allows for optimisation (taking advantage of the container's peculiarities). See "contains() algorithm for std::vector" for an example.
- The second is more general in the absence of any range-library, like the one expected for the C++20 standard, and available for earlier versions.
Constraining the needle to the type
decltype(*begin)
is very problematic:- It forces pass-by-value, which while it should be possible, at least with moveing, might be inefficient.
- You cannot take advantage of transparent comparators (a C++14 feature), forcing the creation of a useless temporary. On the flip-side, if transparent comparators are not used, only a single temporary is constructed.
- If the type is a proxy like with the dreaded
std::vector <bool>
, hilarity ensues.
Consider taking advantage of the standard library, specifically
std::find ()
.C++ will deduce the function's template-arguments perfectly fine, no need for error-prone verbosity.
$endgroup$
$begingroup$
On point 2, it's even worse: you can't pass a value that's convertible todecltype(*begin)
, because templates need exact matches.
$endgroup$
– Toby Speight
4 hours ago
add a comment |
$begingroup$
Do you want to test whether an element is in a container, or an iterator-range?
- The first allows for optimisation (taking advantage of the container's peculiarities). See "contains() algorithm for std::vector" for an example.
- The second is more general in the absence of any range-library, like the one expected for the C++20 standard, and available for earlier versions.
Constraining the needle to the type
decltype(*begin)
is very problematic:- It forces pass-by-value, which while it should be possible, at least with moveing, might be inefficient.
- You cannot take advantage of transparent comparators (a C++14 feature), forcing the creation of a useless temporary. On the flip-side, if transparent comparators are not used, only a single temporary is constructed.
- If the type is a proxy like with the dreaded
std::vector <bool>
, hilarity ensues.
Consider taking advantage of the standard library, specifically
std::find ()
.C++ will deduce the function's template-arguments perfectly fine, no need for error-prone verbosity.
$endgroup$
Do you want to test whether an element is in a container, or an iterator-range?
- The first allows for optimisation (taking advantage of the container's peculiarities). See "contains() algorithm for std::vector" for an example.
- The second is more general in the absence of any range-library, like the one expected for the C++20 standard, and available for earlier versions.
Constraining the needle to the type
decltype(*begin)
is very problematic:- It forces pass-by-value, which while it should be possible, at least with moveing, might be inefficient.
- You cannot take advantage of transparent comparators (a C++14 feature), forcing the creation of a useless temporary. On the flip-side, if transparent comparators are not used, only a single temporary is constructed.
- If the type is a proxy like with the dreaded
std::vector <bool>
, hilarity ensues.
Consider taking advantage of the standard library, specifically
std::find ()
.C++ will deduce the function's template-arguments perfectly fine, no need for error-prone verbosity.
answered yesterday
DeduplicatorDeduplicator
11.8k1950
11.8k1950
$begingroup$
On point 2, it's even worse: you can't pass a value that's convertible todecltype(*begin)
, because templates need exact matches.
$endgroup$
– Toby Speight
4 hours ago
add a comment |
$begingroup$
On point 2, it's even worse: you can't pass a value that's convertible todecltype(*begin)
, because templates need exact matches.
$endgroup$
– Toby Speight
4 hours ago
$begingroup$
On point 2, it's even worse: you can't pass a value that's convertible to
decltype(*begin)
, because templates need exact matches.$endgroup$
– Toby Speight
4 hours ago
$begingroup$
On point 2, it's even worse: you can't pass a value that's convertible to
decltype(*begin)
, because templates need exact matches.$endgroup$
– Toby Speight
4 hours ago
add a comment |
Daniel Duque is a new contributor. Be nice, and check out our Code of Conduct.
Daniel Duque is a new contributor. Be nice, and check out our Code of Conduct.
Daniel Duque is a new contributor. Be nice, and check out our Code of Conduct.
Daniel Duque is a new contributor. Be nice, and check out our Code of Conduct.
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