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Using cursor.next() is resetting “row in cursor” causing it to skip every other row



The Next CEO of Stack OverflowHow would I group values in a field based on range of number using python, and then update the attribute table?How to check for empty values in fields of a featureclass?Calculate and Restart Sequential ID for Unique Values in a Fieldarcpy.UpdateCursor updates every rowCursor update row operatorWriting Data Driven Pages' scale into driving layer's attribute table with arcpyPopulate field with information from a different field based on matching recordStratified random point sampling in PythonComparing value with value from the next rowDeleting row using ArcPy cursor?










0















I'm trying to update a column based on the value in the next row, but cursor.next() is giving unexpected behavior. When I identify the next_row using cursor.next(), it is resetting my row in cursor! The result is my loop goes over every other row, not every row. What am I missing? (Code below is just to show cursor behavior; code for row update for column has been stripped.)



Code



import arcpy
temp1 = r'mypathmypointfile.shp'
with arcpy.da.UpdateCursor(temp1, ['OID@']) as cursor:
for row in cursor:
try:
row_next = cursor.next()
print 'current_oid=', row[0], 'next_oid=', row_next[0]
except StopIteration:
print 'no rows'
except:
print 'something else went wrong'


Actual Prints



current_oid= 0 next_oid= 1
current_oid= 2 next_oid= 3
current_oid= 4 next_oid= 5
current_oid= 6 next_oid= 7
current_oid= 8 next_oid= 9


Expected Prints



current_oid= 0 next_oid= 1
current_oid= 1 next_oid= 2
current_oid= 2 next_oid= 3
current_oid= 3 next_oid= 4
current_oid= 4 next_oid= 5


UPDATE



Purpose of this is to only keep rows that are the first or last point in the group.



Example attributes:



oid group id
0 1 1
1 1 2
2 1 3
3 2 1
4 2 2
5 3 1
6 3 2
7 3 3
8 3 4
9 3 5


Desired attributes:



group id
1 1
1 3
2 1
2 2
3 1
3 5


Original code, that didn't work because cursor.next() skips rows:



with arcpy.da.UpdateCursor(temp1, ['OID@', 'group', 'id']) as cursor:
for row in cursor:
group_current = row[1]
id_current = row[2]
if id_current == 1:
check = "keep"
else:
try:
row_next = cursor.next()
group_next = row_next[1]
id_next = row_next[2]
if id_next == 1:
check = "keep"
else:
check = "remove"
except StopIteration:
check = "keep"
except:
print 'something else went wrong'
if check != "keep":
cursor.deleteRow()









share|improve this question



















  • 2





    next isn't needed, because you're in a for loop. You can't read ahead, but you can preserve the current in previous then act on that later.

    – Vince
    yesterday












  • @Vince As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior. I will be calculating the value in "mycol" in row4 based on the value in "myotherCol" in row5.

    – AlexS1
    yesterday






  • 1





    No, you can't read ahead without losing the current row. You need to use cursor as it actually operates, not how you wish it did. What you can do is save your values in a dictionary with a SearchCursor scan with an OID key, the run an update pass later. I've cached tens of millions of rows with a 32-bit Python and hundreds of millions with 64-bit Python, so 15k rows is a drop in the bucket.

    – Vince
    yesterday















0















I'm trying to update a column based on the value in the next row, but cursor.next() is giving unexpected behavior. When I identify the next_row using cursor.next(), it is resetting my row in cursor! The result is my loop goes over every other row, not every row. What am I missing? (Code below is just to show cursor behavior; code for row update for column has been stripped.)



Code



import arcpy
temp1 = r'mypathmypointfile.shp'
with arcpy.da.UpdateCursor(temp1, ['OID@']) as cursor:
for row in cursor:
try:
row_next = cursor.next()
print 'current_oid=', row[0], 'next_oid=', row_next[0]
except StopIteration:
print 'no rows'
except:
print 'something else went wrong'


Actual Prints



current_oid= 0 next_oid= 1
current_oid= 2 next_oid= 3
current_oid= 4 next_oid= 5
current_oid= 6 next_oid= 7
current_oid= 8 next_oid= 9


Expected Prints



current_oid= 0 next_oid= 1
current_oid= 1 next_oid= 2
current_oid= 2 next_oid= 3
current_oid= 3 next_oid= 4
current_oid= 4 next_oid= 5


UPDATE



Purpose of this is to only keep rows that are the first or last point in the group.



Example attributes:



oid group id
0 1 1
1 1 2
2 1 3
3 2 1
4 2 2
5 3 1
6 3 2
7 3 3
8 3 4
9 3 5


Desired attributes:



group id
1 1
1 3
2 1
2 2
3 1
3 5


Original code, that didn't work because cursor.next() skips rows:



with arcpy.da.UpdateCursor(temp1, ['OID@', 'group', 'id']) as cursor:
for row in cursor:
group_current = row[1]
id_current = row[2]
if id_current == 1:
check = "keep"
else:
try:
row_next = cursor.next()
group_next = row_next[1]
id_next = row_next[2]
if id_next == 1:
check = "keep"
else:
check = "remove"
except StopIteration:
check = "keep"
except:
print 'something else went wrong'
if check != "keep":
cursor.deleteRow()









share|improve this question



















  • 2





    next isn't needed, because you're in a for loop. You can't read ahead, but you can preserve the current in previous then act on that later.

    – Vince
    yesterday












  • @Vince As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior. I will be calculating the value in "mycol" in row4 based on the value in "myotherCol" in row5.

    – AlexS1
    yesterday






  • 1





    No, you can't read ahead without losing the current row. You need to use cursor as it actually operates, not how you wish it did. What you can do is save your values in a dictionary with a SearchCursor scan with an OID key, the run an update pass later. I've cached tens of millions of rows with a 32-bit Python and hundreds of millions with 64-bit Python, so 15k rows is a drop in the bucket.

    – Vince
    yesterday













0












0








0








I'm trying to update a column based on the value in the next row, but cursor.next() is giving unexpected behavior. When I identify the next_row using cursor.next(), it is resetting my row in cursor! The result is my loop goes over every other row, not every row. What am I missing? (Code below is just to show cursor behavior; code for row update for column has been stripped.)



Code



import arcpy
temp1 = r'mypathmypointfile.shp'
with arcpy.da.UpdateCursor(temp1, ['OID@']) as cursor:
for row in cursor:
try:
row_next = cursor.next()
print 'current_oid=', row[0], 'next_oid=', row_next[0]
except StopIteration:
print 'no rows'
except:
print 'something else went wrong'


Actual Prints



current_oid= 0 next_oid= 1
current_oid= 2 next_oid= 3
current_oid= 4 next_oid= 5
current_oid= 6 next_oid= 7
current_oid= 8 next_oid= 9


Expected Prints



current_oid= 0 next_oid= 1
current_oid= 1 next_oid= 2
current_oid= 2 next_oid= 3
current_oid= 3 next_oid= 4
current_oid= 4 next_oid= 5


UPDATE



Purpose of this is to only keep rows that are the first or last point in the group.



Example attributes:



oid group id
0 1 1
1 1 2
2 1 3
3 2 1
4 2 2
5 3 1
6 3 2
7 3 3
8 3 4
9 3 5


Desired attributes:



group id
1 1
1 3
2 1
2 2
3 1
3 5


Original code, that didn't work because cursor.next() skips rows:



with arcpy.da.UpdateCursor(temp1, ['OID@', 'group', 'id']) as cursor:
for row in cursor:
group_current = row[1]
id_current = row[2]
if id_current == 1:
check = "keep"
else:
try:
row_next = cursor.next()
group_next = row_next[1]
id_next = row_next[2]
if id_next == 1:
check = "keep"
else:
check = "remove"
except StopIteration:
check = "keep"
except:
print 'something else went wrong'
if check != "keep":
cursor.deleteRow()









share|improve this question
















I'm trying to update a column based on the value in the next row, but cursor.next() is giving unexpected behavior. When I identify the next_row using cursor.next(), it is resetting my row in cursor! The result is my loop goes over every other row, not every row. What am I missing? (Code below is just to show cursor behavior; code for row update for column has been stripped.)



Code



import arcpy
temp1 = r'mypathmypointfile.shp'
with arcpy.da.UpdateCursor(temp1, ['OID@']) as cursor:
for row in cursor:
try:
row_next = cursor.next()
print 'current_oid=', row[0], 'next_oid=', row_next[0]
except StopIteration:
print 'no rows'
except:
print 'something else went wrong'


Actual Prints



current_oid= 0 next_oid= 1
current_oid= 2 next_oid= 3
current_oid= 4 next_oid= 5
current_oid= 6 next_oid= 7
current_oid= 8 next_oid= 9


Expected Prints



current_oid= 0 next_oid= 1
current_oid= 1 next_oid= 2
current_oid= 2 next_oid= 3
current_oid= 3 next_oid= 4
current_oid= 4 next_oid= 5


UPDATE



Purpose of this is to only keep rows that are the first or last point in the group.



Example attributes:



oid group id
0 1 1
1 1 2
2 1 3
3 2 1
4 2 2
5 3 1
6 3 2
7 3 3
8 3 4
9 3 5


Desired attributes:



group id
1 1
1 3
2 1
2 2
3 1
3 5


Original code, that didn't work because cursor.next() skips rows:



with arcpy.da.UpdateCursor(temp1, ['OID@', 'group', 'id']) as cursor:
for row in cursor:
group_current = row[1]
id_current = row[2]
if id_current == 1:
check = "keep"
else:
try:
row_next = cursor.next()
group_next = row_next[1]
id_next = row_next[2]
if id_next == 1:
check = "keep"
else:
check = "remove"
except StopIteration:
check = "keep"
except:
print 'something else went wrong'
if check != "keep":
cursor.deleteRow()






arcpy cursor arcgis-10.6






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited yesterday







AlexS1

















asked yesterday









AlexS1AlexS1

16710




16710







  • 2





    next isn't needed, because you're in a for loop. You can't read ahead, but you can preserve the current in previous then act on that later.

    – Vince
    yesterday












  • @Vince As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior. I will be calculating the value in "mycol" in row4 based on the value in "myotherCol" in row5.

    – AlexS1
    yesterday






  • 1





    No, you can't read ahead without losing the current row. You need to use cursor as it actually operates, not how you wish it did. What you can do is save your values in a dictionary with a SearchCursor scan with an OID key, the run an update pass later. I've cached tens of millions of rows with a 32-bit Python and hundreds of millions with 64-bit Python, so 15k rows is a drop in the bucket.

    – Vince
    yesterday












  • 2





    next isn't needed, because you're in a for loop. You can't read ahead, but you can preserve the current in previous then act on that later.

    – Vince
    yesterday












  • @Vince As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior. I will be calculating the value in "mycol" in row4 based on the value in "myotherCol" in row5.

    – AlexS1
    yesterday






  • 1





    No, you can't read ahead without losing the current row. You need to use cursor as it actually operates, not how you wish it did. What you can do is save your values in a dictionary with a SearchCursor scan with an OID key, the run an update pass later. I've cached tens of millions of rows with a 32-bit Python and hundreds of millions with 64-bit Python, so 15k rows is a drop in the bucket.

    – Vince
    yesterday







2




2





next isn't needed, because you're in a for loop. You can't read ahead, but you can preserve the current in previous then act on that later.

– Vince
yesterday






next isn't needed, because you're in a for loop. You can't read ahead, but you can preserve the current in previous then act on that later.

– Vince
yesterday














@Vince As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior. I will be calculating the value in "mycol" in row4 based on the value in "myotherCol" in row5.

– AlexS1
yesterday





@Vince As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior. I will be calculating the value in "mycol" in row4 based on the value in "myotherCol" in row5.

– AlexS1
yesterday




1




1





No, you can't read ahead without losing the current row. You need to use cursor as it actually operates, not how you wish it did. What you can do is save your values in a dictionary with a SearchCursor scan with an OID key, the run an update pass later. I've cached tens of millions of rows with a 32-bit Python and hundreds of millions with 64-bit Python, so 15k rows is a drop in the bucket.

– Vince
yesterday





No, you can't read ahead without losing the current row. You need to use cursor as it actually operates, not how you wish it did. What you can do is save your values in a dictionary with a SearchCursor scan with an OID key, the run an update pass later. I've cached tens of millions of rows with a 32-bit Python and hundreds of millions with 64-bit Python, so 15k rows is a drop in the bucket.

– Vince
yesterday










2 Answers
2






active

oldest

votes


















0














Yes, this is expected as it's how python generators work, once a value is consumed, it's gone. If your feature class isn't toooo big, pull all the rows into a list, then use enumerate and indexing to access the next row. E.g.



cursor = ((i,) for i in range(10)) # Fake a cursor as I'm not at a PC with ArcGIS
rows = list(cursor) # Exhaust the generator
for i, row in enumerate(rows):
try:
row_next = rows[i+1]
print(row[0],row_next[0])
except IndexError:
print('no rows')


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9
no rows


Or... turn it around, grab the first row before the loop then refer to the previous row instead of the next row:



prev_row = next(cursor)
for row in cursor:
print(prev_row[0], row[0])
prev_row = row


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9





share|improve this answer























  • I'm doing this for many files, and my smallest one has about 15k rows. As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior.

    – AlexS1
    yesterday












  • Either method should work. Use a SearchCursor to get the list before using the UpdateCursor, a few million values in a list isn't going to be an issue (unless you pull in geometry as well).

    – user2856
    yesterday











  • answer accepted because it addresses cursor behavior in original question; in case anyone has a similar issue, I posted working code below as another answer

    – AlexS1
    yesterday


















0














Thanks to Vince's comments and user2856's answer/comments, the following worked. Elapsed time = 30.17 seconds for 52,000 row, which seems slow.



temp1 = r'mypathmypointfile.shp'
import datetime
now = datetime.datetime.now()

cursor = arcpy.da.SearchCursor(temp1, ['OID@', 'group', 'id'])
rows = list(cursor)
dict_ids =
for i, row in enumerate(rows):
oid = row[0]
group_current = row[1]
id_current = row[2]
if id_current == 1:
check = "keep"
else:
try:
row_next = rows[i + 1]
id_next = row_next[2]
if vid_next == 1:
check = "keep"
else:
check = "remove"
except IndexError:
check = "keep"
except:
print 'something else went wrong'
dict_ids.update([(oid, check)])
del i, row, check
with arcpy.da.UpdateCursor(temp1, ['OID@']) as cursor:
for row in cursor:
oid = row[0]
if oid in dict_ids:
check = dict_ids.get(oid)
else:
print 'error with dictionary'
sys.exit()
if check != "keep":
cursor.deleteRow()

later = datetime.datetime.now()
elapsed = later - now
print elapsed





share|improve this answer























  • That is slow, your code takes 2 seconds for me on a local FGDB feature class with 52,000 records. Make sure you're not running it on data on a network drive.

    – user2856
    3 hours ago











  • yes, it is slow. no network, all local.

    – AlexS1
    2 hours ago











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Yes, this is expected as it's how python generators work, once a value is consumed, it's gone. If your feature class isn't toooo big, pull all the rows into a list, then use enumerate and indexing to access the next row. E.g.



cursor = ((i,) for i in range(10)) # Fake a cursor as I'm not at a PC with ArcGIS
rows = list(cursor) # Exhaust the generator
for i, row in enumerate(rows):
try:
row_next = rows[i+1]
print(row[0],row_next[0])
except IndexError:
print('no rows')


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9
no rows


Or... turn it around, grab the first row before the loop then refer to the previous row instead of the next row:



prev_row = next(cursor)
for row in cursor:
print(prev_row[0], row[0])
prev_row = row


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9





share|improve this answer























  • I'm doing this for many files, and my smallest one has about 15k rows. As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior.

    – AlexS1
    yesterday












  • Either method should work. Use a SearchCursor to get the list before using the UpdateCursor, a few million values in a list isn't going to be an issue (unless you pull in geometry as well).

    – user2856
    yesterday











  • answer accepted because it addresses cursor behavior in original question; in case anyone has a similar issue, I posted working code below as another answer

    – AlexS1
    yesterday















0














Yes, this is expected as it's how python generators work, once a value is consumed, it's gone. If your feature class isn't toooo big, pull all the rows into a list, then use enumerate and indexing to access the next row. E.g.



cursor = ((i,) for i in range(10)) # Fake a cursor as I'm not at a PC with ArcGIS
rows = list(cursor) # Exhaust the generator
for i, row in enumerate(rows):
try:
row_next = rows[i+1]
print(row[0],row_next[0])
except IndexError:
print('no rows')


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9
no rows


Or... turn it around, grab the first row before the loop then refer to the previous row instead of the next row:



prev_row = next(cursor)
for row in cursor:
print(prev_row[0], row[0])
prev_row = row


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9





share|improve this answer























  • I'm doing this for many files, and my smallest one has about 15k rows. As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior.

    – AlexS1
    yesterday












  • Either method should work. Use a SearchCursor to get the list before using the UpdateCursor, a few million values in a list isn't going to be an issue (unless you pull in geometry as well).

    – user2856
    yesterday











  • answer accepted because it addresses cursor behavior in original question; in case anyone has a similar issue, I posted working code below as another answer

    – AlexS1
    yesterday













0












0








0







Yes, this is expected as it's how python generators work, once a value is consumed, it's gone. If your feature class isn't toooo big, pull all the rows into a list, then use enumerate and indexing to access the next row. E.g.



cursor = ((i,) for i in range(10)) # Fake a cursor as I'm not at a PC with ArcGIS
rows = list(cursor) # Exhaust the generator
for i, row in enumerate(rows):
try:
row_next = rows[i+1]
print(row[0],row_next[0])
except IndexError:
print('no rows')


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9
no rows


Or... turn it around, grab the first row before the loop then refer to the previous row instead of the next row:



prev_row = next(cursor)
for row in cursor:
print(prev_row[0], row[0])
prev_row = row


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9





share|improve this answer













Yes, this is expected as it's how python generators work, once a value is consumed, it's gone. If your feature class isn't toooo big, pull all the rows into a list, then use enumerate and indexing to access the next row. E.g.



cursor = ((i,) for i in range(10)) # Fake a cursor as I'm not at a PC with ArcGIS
rows = list(cursor) # Exhaust the generator
for i, row in enumerate(rows):
try:
row_next = rows[i+1]
print(row[0],row_next[0])
except IndexError:
print('no rows')


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9
no rows


Or... turn it around, grab the first row before the loop then refer to the previous row instead of the next row:



prev_row = next(cursor)
for row in cursor:
print(prev_row[0], row[0])
prev_row = row


Output:



0 1
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9






share|improve this answer












share|improve this answer



share|improve this answer










answered yesterday









user2856user2856

30.6k258106




30.6k258106












  • I'm doing this for many files, and my smallest one has about 15k rows. As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior.

    – AlexS1
    yesterday












  • Either method should work. Use a SearchCursor to get the list before using the UpdateCursor, a few million values in a list isn't going to be an issue (unless you pull in geometry as well).

    – user2856
    yesterday











  • answer accepted because it addresses cursor behavior in original question; in case anyone has a similar issue, I posted working code below as another answer

    – AlexS1
    yesterday

















  • I'm doing this for many files, and my smallest one has about 15k rows. As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior.

    – AlexS1
    yesterday












  • Either method should work. Use a SearchCursor to get the list before using the UpdateCursor, a few million values in a list isn't going to be an issue (unless you pull in geometry as well).

    – user2856
    yesterday











  • answer accepted because it addresses cursor behavior in original question; in case anyone has a similar issue, I posted working code below as another answer

    – AlexS1
    yesterday
















I'm doing this for many files, and my smallest one has about 15k rows. As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior.

– AlexS1
yesterday






I'm doing this for many files, and my smallest one has about 15k rows. As stated in question, purpose is to perform UpdateCursor on a specific column based on values in another column. The printing of the oid values was for illustration of skipping behavior.

– AlexS1
yesterday














Either method should work. Use a SearchCursor to get the list before using the UpdateCursor, a few million values in a list isn't going to be an issue (unless you pull in geometry as well).

– user2856
yesterday





Either method should work. Use a SearchCursor to get the list before using the UpdateCursor, a few million values in a list isn't going to be an issue (unless you pull in geometry as well).

– user2856
yesterday













answer accepted because it addresses cursor behavior in original question; in case anyone has a similar issue, I posted working code below as another answer

– AlexS1
yesterday





answer accepted because it addresses cursor behavior in original question; in case anyone has a similar issue, I posted working code below as another answer

– AlexS1
yesterday













0














Thanks to Vince's comments and user2856's answer/comments, the following worked. Elapsed time = 30.17 seconds for 52,000 row, which seems slow.



temp1 = r'mypathmypointfile.shp'
import datetime
now = datetime.datetime.now()

cursor = arcpy.da.SearchCursor(temp1, ['OID@', 'group', 'id'])
rows = list(cursor)
dict_ids =
for i, row in enumerate(rows):
oid = row[0]
group_current = row[1]
id_current = row[2]
if id_current == 1:
check = "keep"
else:
try:
row_next = rows[i + 1]
id_next = row_next[2]
if vid_next == 1:
check = "keep"
else:
check = "remove"
except IndexError:
check = "keep"
except:
print 'something else went wrong'
dict_ids.update([(oid, check)])
del i, row, check
with arcpy.da.UpdateCursor(temp1, ['OID@']) as cursor:
for row in cursor:
oid = row[0]
if oid in dict_ids:
check = dict_ids.get(oid)
else:
print 'error with dictionary'
sys.exit()
if check != "keep":
cursor.deleteRow()

later = datetime.datetime.now()
elapsed = later - now
print elapsed





share|improve this answer























  • That is slow, your code takes 2 seconds for me on a local FGDB feature class with 52,000 records. Make sure you're not running it on data on a network drive.

    – user2856
    3 hours ago











  • yes, it is slow. no network, all local.

    – AlexS1
    2 hours ago















0














Thanks to Vince's comments and user2856's answer/comments, the following worked. Elapsed time = 30.17 seconds for 52,000 row, which seems slow.



temp1 = r'mypathmypointfile.shp'
import datetime
now = datetime.datetime.now()

cursor = arcpy.da.SearchCursor(temp1, ['OID@', 'group', 'id'])
rows = list(cursor)
dict_ids =
for i, row in enumerate(rows):
oid = row[0]
group_current = row[1]
id_current = row[2]
if id_current == 1:
check = "keep"
else:
try:
row_next = rows[i + 1]
id_next = row_next[2]
if vid_next == 1:
check = "keep"
else:
check = "remove"
except IndexError:
check = "keep"
except:
print 'something else went wrong'
dict_ids.update([(oid, check)])
del i, row, check
with arcpy.da.UpdateCursor(temp1, ['OID@']) as cursor:
for row in cursor:
oid = row[0]
if oid in dict_ids:
check = dict_ids.get(oid)
else:
print 'error with dictionary'
sys.exit()
if check != "keep":
cursor.deleteRow()

later = datetime.datetime.now()
elapsed = later - now
print elapsed





share|improve this answer























  • That is slow, your code takes 2 seconds for me on a local FGDB feature class with 52,000 records. Make sure you're not running it on data on a network drive.

    – user2856
    3 hours ago











  • yes, it is slow. no network, all local.

    – AlexS1
    2 hours ago













0












0








0







Thanks to Vince's comments and user2856's answer/comments, the following worked. Elapsed time = 30.17 seconds for 52,000 row, which seems slow.



temp1 = r'mypathmypointfile.shp'
import datetime
now = datetime.datetime.now()

cursor = arcpy.da.SearchCursor(temp1, ['OID@', 'group', 'id'])
rows = list(cursor)
dict_ids =
for i, row in enumerate(rows):
oid = row[0]
group_current = row[1]
id_current = row[2]
if id_current == 1:
check = "keep"
else:
try:
row_next = rows[i + 1]
id_next = row_next[2]
if vid_next == 1:
check = "keep"
else:
check = "remove"
except IndexError:
check = "keep"
except:
print 'something else went wrong'
dict_ids.update([(oid, check)])
del i, row, check
with arcpy.da.UpdateCursor(temp1, ['OID@']) as cursor:
for row in cursor:
oid = row[0]
if oid in dict_ids:
check = dict_ids.get(oid)
else:
print 'error with dictionary'
sys.exit()
if check != "keep":
cursor.deleteRow()

later = datetime.datetime.now()
elapsed = later - now
print elapsed





share|improve this answer













Thanks to Vince's comments and user2856's answer/comments, the following worked. Elapsed time = 30.17 seconds for 52,000 row, which seems slow.



temp1 = r'mypathmypointfile.shp'
import datetime
now = datetime.datetime.now()

cursor = arcpy.da.SearchCursor(temp1, ['OID@', 'group', 'id'])
rows = list(cursor)
dict_ids =
for i, row in enumerate(rows):
oid = row[0]
group_current = row[1]
id_current = row[2]
if id_current == 1:
check = "keep"
else:
try:
row_next = rows[i + 1]
id_next = row_next[2]
if vid_next == 1:
check = "keep"
else:
check = "remove"
except IndexError:
check = "keep"
except:
print 'something else went wrong'
dict_ids.update([(oid, check)])
del i, row, check
with arcpy.da.UpdateCursor(temp1, ['OID@']) as cursor:
for row in cursor:
oid = row[0]
if oid in dict_ids:
check = dict_ids.get(oid)
else:
print 'error with dictionary'
sys.exit()
if check != "keep":
cursor.deleteRow()

later = datetime.datetime.now()
elapsed = later - now
print elapsed






share|improve this answer












share|improve this answer



share|improve this answer










answered yesterday









AlexS1AlexS1

16710




16710












  • That is slow, your code takes 2 seconds for me on a local FGDB feature class with 52,000 records. Make sure you're not running it on data on a network drive.

    – user2856
    3 hours ago











  • yes, it is slow. no network, all local.

    – AlexS1
    2 hours ago

















  • That is slow, your code takes 2 seconds for me on a local FGDB feature class with 52,000 records. Make sure you're not running it on data on a network drive.

    – user2856
    3 hours ago











  • yes, it is slow. no network, all local.

    – AlexS1
    2 hours ago
















That is slow, your code takes 2 seconds for me on a local FGDB feature class with 52,000 records. Make sure you're not running it on data on a network drive.

– user2856
3 hours ago





That is slow, your code takes 2 seconds for me on a local FGDB feature class with 52,000 records. Make sure you're not running it on data on a network drive.

– user2856
3 hours ago













yes, it is slow. no network, all local.

– AlexS1
2 hours ago





yes, it is slow. no network, all local.

– AlexS1
2 hours ago

















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