Clustering points and summing up attributes per cluster in QGIS The Next CEO of Stack OverflowHow to divide my area into adjacent polygons containing 80 points each?MYSQL 5.6 Cluster / chain points by distance to any other point without millions of calculations?Get a single cluster from cloud of points with specified maximum diameter in postgisIdentify points in a shapefile that have no other point within x km with QGISAlgorithm for clustering points into pairs (exactly two) by proximity without re-useHow can I cluster all points in a postgis table together based on their distance from each other?Clustering point data to obtain maximum count groups using QGIS?Reading attribute popup information from cluster presented points in the map generated via qgis2web?Cluster Points on spatial network in R/QGISGrouped “labels” for QGIS 3.0 Point Cluster styling?

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Clustering points and summing up attributes per cluster in QGIS



The Next CEO of Stack OverflowHow to divide my area into adjacent polygons containing 80 points each?MYSQL 5.6 Cluster / chain points by distance to any other point without millions of calculations?Get a single cluster from cloud of points with specified maximum diameter in postgisIdentify points in a shapefile that have no other point within x km with QGISAlgorithm for clustering points into pairs (exactly two) by proximity without re-useHow can I cluster all points in a postgis table together based on their distance from each other?Clustering point data to obtain maximum count groups using QGIS?Reading attribute popup information from cluster presented points in the map generated via qgis2web?Cluster Points on spatial network in R/QGISGrouped “labels” for QGIS 3.0 Point Cluster styling?










7















We want to find out the ideal location for sheds and the required dimensions of each shed. As input, we have a point layer with locations (each representing one arable field) and the estimated yield per point (per arable field).



What we now try to do is first to create four clusters for these fields. This should serve as an approximation of the ideal location for a new shed. We've done this by simply using the "point cluster" option in the "symbology" section and adjusting the distance until only four cluster points remained. These cluster points were then saved as new point shapefile.



How do we determine what points are actually clustered in each of the cluster points?



With this information, we can then sum up the estimated yields for all the single points per cluster. This would allow us to calculate whether the shed has to be designed for 10 tons or 100 tons of grain.










share|improve this question




























    7















    We want to find out the ideal location for sheds and the required dimensions of each shed. As input, we have a point layer with locations (each representing one arable field) and the estimated yield per point (per arable field).



    What we now try to do is first to create four clusters for these fields. This should serve as an approximation of the ideal location for a new shed. We've done this by simply using the "point cluster" option in the "symbology" section and adjusting the distance until only four cluster points remained. These cluster points were then saved as new point shapefile.



    How do we determine what points are actually clustered in each of the cluster points?



    With this information, we can then sum up the estimated yields for all the single points per cluster. This would allow us to calculate whether the shed has to be designed for 10 tons or 100 tons of grain.










    share|improve this question


























      7












      7








      7


      1






      We want to find out the ideal location for sheds and the required dimensions of each shed. As input, we have a point layer with locations (each representing one arable field) and the estimated yield per point (per arable field).



      What we now try to do is first to create four clusters for these fields. This should serve as an approximation of the ideal location for a new shed. We've done this by simply using the "point cluster" option in the "symbology" section and adjusting the distance until only four cluster points remained. These cluster points were then saved as new point shapefile.



      How do we determine what points are actually clustered in each of the cluster points?



      With this information, we can then sum up the estimated yields for all the single points per cluster. This would allow us to calculate whether the shed has to be designed for 10 tons or 100 tons of grain.










      share|improve this question
















      We want to find out the ideal location for sheds and the required dimensions of each shed. As input, we have a point layer with locations (each representing one arable field) and the estimated yield per point (per arable field).



      What we now try to do is first to create four clusters for these fields. This should serve as an approximation of the ideal location for a new shed. We've done this by simply using the "point cluster" option in the "symbology" section and adjusting the distance until only four cluster points remained. These cluster points were then saved as new point shapefile.



      How do we determine what points are actually clustered in each of the cluster points?



      With this information, we can then sum up the estimated yields for all the single points per cluster. This would allow us to calculate whether the shed has to be designed for 10 tons or 100 tons of grain.







      qgis clustering connectivity-analysis






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited yesterday









      PolyGeo

      53.8k1781245




      53.8k1781245










      asked yesterday









      cbrcbr

      434




      434




















          1 Answer
          1






          active

          oldest

          votes


















          5














          I would try K-means clustering algorithm in the QGIS Processing Toolbox (under Vector analysis group).



          Just by setting the Number of clusters as 4, it will produce a new Clusters layer with an attribute field CLUSTER_ID (values= 0, 1, 2, 3).



          enter image description here



          Then an expression like SUM("yield", "CLUSTER_ID") in the Field Calculator will return the total yield for each cluster. (E.G. the Sum_per_Cluster in the below example).



          enter image description here




          [Update]



          To obtain center point per the group (cluster), please try Mean coordinate(s) geoalgorithm in Processing Toolbox > Vector analysis.



          Mean coordinates dialog window will show an option Unique ID field. Select CLUSTER_ID field.






          share|improve this answer

























          • Thank you very much for the quick and helpful reply! How did you create the center points of the clusters? When I use the method I described in my initial post (using "Symbology" and "Cluster"), I get center points completely off the actual cluster center (see [ibb.co/VmkhS0x]). This may stem from the different calculation methods. What approach did you use in your example? Furthermore, I get a lot of "NULL" results when I do the K-means clustering (see [ibb.co/VNdQ7bS]). Do you have a solution for this issue? Thank you very much!

            – cbr
            yesterday












          • Since I only get error pages when trying to access the uploaded images but cannot edit the comment anymore (>5 min), here other links: Cluster center -> imgur.com/a/fs3R1K1 ; NULL -> imgur.com/a/Cv7IuCr

            – cbr
            yesterday












          • @cbr To create center point for each cluster, please use Centroids geoalgorithm. I will update my post. As to the center points (red circles) in my example, they were Point cluster symbology just for comparison.

            – Kazuhito
            yesterday











          • @cbr Your upperleft (north western) cluster in the provided image has only two locations in that cluster, which does not seem right. (You would not build shed just for those two). I am not sure what happened with locations with NULL outputs; they may be outliers. Perhaps I would check their locations visually, and manually assign most appropriate cluster id.

            – Kazuhito
            yesterday












          • Thanks very much for your reply! The centroids algorithm only returns the same location for each of the selected points (so the output is a layer with the same amount of points as the input layer). I assume that the center point for each point was calculated but not one single point for the whole cluster... Is there another intermediate step necessary I made have missed?

            – cbr
            20 hours ago











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          1 Answer
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          active

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          5














          I would try K-means clustering algorithm in the QGIS Processing Toolbox (under Vector analysis group).



          Just by setting the Number of clusters as 4, it will produce a new Clusters layer with an attribute field CLUSTER_ID (values= 0, 1, 2, 3).



          enter image description here



          Then an expression like SUM("yield", "CLUSTER_ID") in the Field Calculator will return the total yield for each cluster. (E.G. the Sum_per_Cluster in the below example).



          enter image description here




          [Update]



          To obtain center point per the group (cluster), please try Mean coordinate(s) geoalgorithm in Processing Toolbox > Vector analysis.



          Mean coordinates dialog window will show an option Unique ID field. Select CLUSTER_ID field.






          share|improve this answer

























          • Thank you very much for the quick and helpful reply! How did you create the center points of the clusters? When I use the method I described in my initial post (using "Symbology" and "Cluster"), I get center points completely off the actual cluster center (see [ibb.co/VmkhS0x]). This may stem from the different calculation methods. What approach did you use in your example? Furthermore, I get a lot of "NULL" results when I do the K-means clustering (see [ibb.co/VNdQ7bS]). Do you have a solution for this issue? Thank you very much!

            – cbr
            yesterday












          • Since I only get error pages when trying to access the uploaded images but cannot edit the comment anymore (>5 min), here other links: Cluster center -> imgur.com/a/fs3R1K1 ; NULL -> imgur.com/a/Cv7IuCr

            – cbr
            yesterday












          • @cbr To create center point for each cluster, please use Centroids geoalgorithm. I will update my post. As to the center points (red circles) in my example, they were Point cluster symbology just for comparison.

            – Kazuhito
            yesterday











          • @cbr Your upperleft (north western) cluster in the provided image has only two locations in that cluster, which does not seem right. (You would not build shed just for those two). I am not sure what happened with locations with NULL outputs; they may be outliers. Perhaps I would check their locations visually, and manually assign most appropriate cluster id.

            – Kazuhito
            yesterday












          • Thanks very much for your reply! The centroids algorithm only returns the same location for each of the selected points (so the output is a layer with the same amount of points as the input layer). I assume that the center point for each point was calculated but not one single point for the whole cluster... Is there another intermediate step necessary I made have missed?

            – cbr
            20 hours ago















          5














          I would try K-means clustering algorithm in the QGIS Processing Toolbox (under Vector analysis group).



          Just by setting the Number of clusters as 4, it will produce a new Clusters layer with an attribute field CLUSTER_ID (values= 0, 1, 2, 3).



          enter image description here



          Then an expression like SUM("yield", "CLUSTER_ID") in the Field Calculator will return the total yield for each cluster. (E.G. the Sum_per_Cluster in the below example).



          enter image description here




          [Update]



          To obtain center point per the group (cluster), please try Mean coordinate(s) geoalgorithm in Processing Toolbox > Vector analysis.



          Mean coordinates dialog window will show an option Unique ID field. Select CLUSTER_ID field.






          share|improve this answer

























          • Thank you very much for the quick and helpful reply! How did you create the center points of the clusters? When I use the method I described in my initial post (using "Symbology" and "Cluster"), I get center points completely off the actual cluster center (see [ibb.co/VmkhS0x]). This may stem from the different calculation methods. What approach did you use in your example? Furthermore, I get a lot of "NULL" results when I do the K-means clustering (see [ibb.co/VNdQ7bS]). Do you have a solution for this issue? Thank you very much!

            – cbr
            yesterday












          • Since I only get error pages when trying to access the uploaded images but cannot edit the comment anymore (>5 min), here other links: Cluster center -> imgur.com/a/fs3R1K1 ; NULL -> imgur.com/a/Cv7IuCr

            – cbr
            yesterday












          • @cbr To create center point for each cluster, please use Centroids geoalgorithm. I will update my post. As to the center points (red circles) in my example, they were Point cluster symbology just for comparison.

            – Kazuhito
            yesterday











          • @cbr Your upperleft (north western) cluster in the provided image has only two locations in that cluster, which does not seem right. (You would not build shed just for those two). I am not sure what happened with locations with NULL outputs; they may be outliers. Perhaps I would check their locations visually, and manually assign most appropriate cluster id.

            – Kazuhito
            yesterday












          • Thanks very much for your reply! The centroids algorithm only returns the same location for each of the selected points (so the output is a layer with the same amount of points as the input layer). I assume that the center point for each point was calculated but not one single point for the whole cluster... Is there another intermediate step necessary I made have missed?

            – cbr
            20 hours ago













          5












          5








          5







          I would try K-means clustering algorithm in the QGIS Processing Toolbox (under Vector analysis group).



          Just by setting the Number of clusters as 4, it will produce a new Clusters layer with an attribute field CLUSTER_ID (values= 0, 1, 2, 3).



          enter image description here



          Then an expression like SUM("yield", "CLUSTER_ID") in the Field Calculator will return the total yield for each cluster. (E.G. the Sum_per_Cluster in the below example).



          enter image description here




          [Update]



          To obtain center point per the group (cluster), please try Mean coordinate(s) geoalgorithm in Processing Toolbox > Vector analysis.



          Mean coordinates dialog window will show an option Unique ID field. Select CLUSTER_ID field.






          share|improve this answer















          I would try K-means clustering algorithm in the QGIS Processing Toolbox (under Vector analysis group).



          Just by setting the Number of clusters as 4, it will produce a new Clusters layer with an attribute field CLUSTER_ID (values= 0, 1, 2, 3).



          enter image description here



          Then an expression like SUM("yield", "CLUSTER_ID") in the Field Calculator will return the total yield for each cluster. (E.G. the Sum_per_Cluster in the below example).



          enter image description here




          [Update]



          To obtain center point per the group (cluster), please try Mean coordinate(s) geoalgorithm in Processing Toolbox > Vector analysis.



          Mean coordinates dialog window will show an option Unique ID field. Select CLUSTER_ID field.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 6 hours ago

























          answered yesterday









          KazuhitoKazuhito

          16.3k41884




          16.3k41884












          • Thank you very much for the quick and helpful reply! How did you create the center points of the clusters? When I use the method I described in my initial post (using "Symbology" and "Cluster"), I get center points completely off the actual cluster center (see [ibb.co/VmkhS0x]). This may stem from the different calculation methods. What approach did you use in your example? Furthermore, I get a lot of "NULL" results when I do the K-means clustering (see [ibb.co/VNdQ7bS]). Do you have a solution for this issue? Thank you very much!

            – cbr
            yesterday












          • Since I only get error pages when trying to access the uploaded images but cannot edit the comment anymore (>5 min), here other links: Cluster center -> imgur.com/a/fs3R1K1 ; NULL -> imgur.com/a/Cv7IuCr

            – cbr
            yesterday












          • @cbr To create center point for each cluster, please use Centroids geoalgorithm. I will update my post. As to the center points (red circles) in my example, they were Point cluster symbology just for comparison.

            – Kazuhito
            yesterday











          • @cbr Your upperleft (north western) cluster in the provided image has only two locations in that cluster, which does not seem right. (You would not build shed just for those two). I am not sure what happened with locations with NULL outputs; they may be outliers. Perhaps I would check their locations visually, and manually assign most appropriate cluster id.

            – Kazuhito
            yesterday












          • Thanks very much for your reply! The centroids algorithm only returns the same location for each of the selected points (so the output is a layer with the same amount of points as the input layer). I assume that the center point for each point was calculated but not one single point for the whole cluster... Is there another intermediate step necessary I made have missed?

            – cbr
            20 hours ago

















          • Thank you very much for the quick and helpful reply! How did you create the center points of the clusters? When I use the method I described in my initial post (using "Symbology" and "Cluster"), I get center points completely off the actual cluster center (see [ibb.co/VmkhS0x]). This may stem from the different calculation methods. What approach did you use in your example? Furthermore, I get a lot of "NULL" results when I do the K-means clustering (see [ibb.co/VNdQ7bS]). Do you have a solution for this issue? Thank you very much!

            – cbr
            yesterday












          • Since I only get error pages when trying to access the uploaded images but cannot edit the comment anymore (>5 min), here other links: Cluster center -> imgur.com/a/fs3R1K1 ; NULL -> imgur.com/a/Cv7IuCr

            – cbr
            yesterday












          • @cbr To create center point for each cluster, please use Centroids geoalgorithm. I will update my post. As to the center points (red circles) in my example, they were Point cluster symbology just for comparison.

            – Kazuhito
            yesterday











          • @cbr Your upperleft (north western) cluster in the provided image has only two locations in that cluster, which does not seem right. (You would not build shed just for those two). I am not sure what happened with locations with NULL outputs; they may be outliers. Perhaps I would check their locations visually, and manually assign most appropriate cluster id.

            – Kazuhito
            yesterday












          • Thanks very much for your reply! The centroids algorithm only returns the same location for each of the selected points (so the output is a layer with the same amount of points as the input layer). I assume that the center point for each point was calculated but not one single point for the whole cluster... Is there another intermediate step necessary I made have missed?

            – cbr
            20 hours ago
















          Thank you very much for the quick and helpful reply! How did you create the center points of the clusters? When I use the method I described in my initial post (using "Symbology" and "Cluster"), I get center points completely off the actual cluster center (see [ibb.co/VmkhS0x]). This may stem from the different calculation methods. What approach did you use in your example? Furthermore, I get a lot of "NULL" results when I do the K-means clustering (see [ibb.co/VNdQ7bS]). Do you have a solution for this issue? Thank you very much!

          – cbr
          yesterday






          Thank you very much for the quick and helpful reply! How did you create the center points of the clusters? When I use the method I described in my initial post (using "Symbology" and "Cluster"), I get center points completely off the actual cluster center (see [ibb.co/VmkhS0x]). This may stem from the different calculation methods. What approach did you use in your example? Furthermore, I get a lot of "NULL" results when I do the K-means clustering (see [ibb.co/VNdQ7bS]). Do you have a solution for this issue? Thank you very much!

          – cbr
          yesterday














          Since I only get error pages when trying to access the uploaded images but cannot edit the comment anymore (>5 min), here other links: Cluster center -> imgur.com/a/fs3R1K1 ; NULL -> imgur.com/a/Cv7IuCr

          – cbr
          yesterday






          Since I only get error pages when trying to access the uploaded images but cannot edit the comment anymore (>5 min), here other links: Cluster center -> imgur.com/a/fs3R1K1 ; NULL -> imgur.com/a/Cv7IuCr

          – cbr
          yesterday














          @cbr To create center point for each cluster, please use Centroids geoalgorithm. I will update my post. As to the center points (red circles) in my example, they were Point cluster symbology just for comparison.

          – Kazuhito
          yesterday





          @cbr To create center point for each cluster, please use Centroids geoalgorithm. I will update my post. As to the center points (red circles) in my example, they were Point cluster symbology just for comparison.

          – Kazuhito
          yesterday













          @cbr Your upperleft (north western) cluster in the provided image has only two locations in that cluster, which does not seem right. (You would not build shed just for those two). I am not sure what happened with locations with NULL outputs; they may be outliers. Perhaps I would check their locations visually, and manually assign most appropriate cluster id.

          – Kazuhito
          yesterday






          @cbr Your upperleft (north western) cluster in the provided image has only two locations in that cluster, which does not seem right. (You would not build shed just for those two). I am not sure what happened with locations with NULL outputs; they may be outliers. Perhaps I would check their locations visually, and manually assign most appropriate cluster id.

          – Kazuhito
          yesterday














          Thanks very much for your reply! The centroids algorithm only returns the same location for each of the selected points (so the output is a layer with the same amount of points as the input layer). I assume that the center point for each point was calculated but not one single point for the whole cluster... Is there another intermediate step necessary I made have missed?

          – cbr
          20 hours ago





          Thanks very much for your reply! The centroids algorithm only returns the same location for each of the selected points (so the output is a layer with the same amount of points as the input layer). I assume that the center point for each point was calculated but not one single point for the whole cluster... Is there another intermediate step necessary I made have missed?

          – cbr
          20 hours ago

















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          Romeo and Juliet ContentsCharactersSynopsisSourcesDate and textThemes and motifsCriticism and interpretationLegacyScene by sceneSee alsoNotes and referencesSourcesExternal linksNavigation menu"Consumer Price Index (estimate) 1800–"10.2307/28710160037-3222287101610.1093/res/II.5.31910.2307/45967845967810.2307/2869925286992510.1525/jams.1982.35.3.03a00050"Dada Masilo: South African dancer who breaks the rules"10.1093/res/os-XV.57.1610.2307/28680942868094"Sweet Sorrow: Mann-Korman's Romeo and Juliet Closes Sept. 5 at MN's Ordway"the original10.2307/45957745957710.1017/CCOL0521570476.009"Ram Leela box office collections hit massive Rs 100 crore, pulverises prediction"Archived"Broadway Revival of Romeo and Juliet, Starring Orlando Bloom and Condola Rashad, Will Close Dec. 8"Archived10.1075/jhp.7.1.04hon"Wherefore art thou, Romeo? To make us laugh at Navy Pier"the original10.1093/gmo/9781561592630.article.O006772"Ram-leela Review Roundup: Critics Hail Film as Best Adaptation of Romeo and Juliet"Archived10.2307/31946310047-77293194631"Romeo and Juliet get Twitter treatment""Juliet's Nurse by Lois Leveen""Romeo and Juliet: Orlando Bloom's Broadway Debut Released in Theaters for Valentine's Day"Archived"Romeo and Juliet Has No Balcony"10.1093/gmo/9781561592630.article.O00778110.2307/2867423286742310.1076/enst.82.2.115.959510.1080/00138380601042675"A plague o' both your houses: error in GCSE exam paper forces apology""Juliet of the Five O'Clock Shadow, and Other Wonders"10.2307/33912430027-4321339124310.2307/28487440038-7134284874410.2307/29123140149-661129123144728341M"Weekender Guide: Shakespeare on The Drive""balcony"UK public library membership"romeo"UK public library membership10.1017/CCOL9780521844291"Post-Zionist Critique on Israel and the Palestinians Part III: Popular Culture"10.2307/25379071533-86140377-919X2537907"Capulets and Montagues: UK exam board admit mixing names up in Romeo and Juliet paper"Istoria Novellamente Ritrovata di Due Nobili Amanti2027/mdp.390150822329610820-750X"GCSE exam error: Board accidentally rewrites Shakespeare"10.2307/29176390149-66112917639"Exam board apologises after error in English GCSE paper which confused characters in Shakespeare's Romeo and Juliet""From Mariotto and Ganozza to Romeo and Guilietta: Metamorphoses of a Renaissance Tale"10.2307/37323537323510.2307/2867455286745510.2307/28678912867891"10 Questions for Taylor Swift"10.2307/28680922868092"Haymarket Theatre""The Zeffirelli Way: Revealing Talk by Florentine Director""Michael Smuin: 1938-2007 / Prolific dance director had showy career"The Life and Art of Edwin BoothRomeo and JulietRomeo and JulietRomeo and JulietRomeo and JulietEasy Read Romeo and JulietRomeo and Julieteeecb12003684p(data)4099369-3n8211610759dbe00d-a9e2-41a3-b2c1-977dd692899302814385X313670221313670221