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Is every set a filtered colimit of finite sets?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)On colim $Hom_A-alg(B, C_i)$Why is the colimit over this filtered index category the object $F(i_0)$?A filtered poset and a filtered diagram (category)The colimit of all finite-dimensional vector spacesWhy do finite limits commute with filtered colimits in the category of abelian groups?Colimit of collection of finite setsExpressing Representation of a Colimit as a LimitFiltered vs Directed colimitsNot-quite-preservation of not-quite-filtered colimitsAbout a specific step in a proof of the fact that filtered colimits and finite limits commute in $mathbfSet$










2












$begingroup$


Is the following statement correct in the category of sets?




Let $X$ be any set. Then there exists a filtered small category $I$ and a functor $F:Ito mathrmSet$ such that for all $iin I$ the set $F(i)$ is finite, and such that
$$
X ; = ; mathrmcolim_iin I F(i) .
$$




Are there references on results of this type in the literature?










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    One way to generalize this is the notion of a locally finitely presentable category.
    $endgroup$
    – Derek Elkins
    Apr 8 at 12:35















2












$begingroup$


Is the following statement correct in the category of sets?




Let $X$ be any set. Then there exists a filtered small category $I$ and a functor $F:Ito mathrmSet$ such that for all $iin I$ the set $F(i)$ is finite, and such that
$$
X ; = ; mathrmcolim_iin I F(i) .
$$




Are there references on results of this type in the literature?










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    One way to generalize this is the notion of a locally finitely presentable category.
    $endgroup$
    – Derek Elkins
    Apr 8 at 12:35













2












2








2





$begingroup$


Is the following statement correct in the category of sets?




Let $X$ be any set. Then there exists a filtered small category $I$ and a functor $F:Ito mathrmSet$ such that for all $iin I$ the set $F(i)$ is finite, and such that
$$
X ; = ; mathrmcolim_iin I F(i) .
$$




Are there references on results of this type in the literature?










share|cite|improve this question











$endgroup$




Is the following statement correct in the category of sets?




Let $X$ be any set. Then there exists a filtered small category $I$ and a functor $F:Ito mathrmSet$ such that for all $iin I$ the set $F(i)$ is finite, and such that
$$
X ; = ; mathrmcolim_iin I F(i) .
$$




Are there references on results of this type in the literature?







reference-request category-theory limits-colimits






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Apr 8 at 19:10









Andrés E. Caicedo

66k8160252




66k8160252










asked Apr 8 at 12:29









geodudegeodude

4,1911344




4,1911344







  • 1




    $begingroup$
    One way to generalize this is the notion of a locally finitely presentable category.
    $endgroup$
    – Derek Elkins
    Apr 8 at 12:35












  • 1




    $begingroup$
    One way to generalize this is the notion of a locally finitely presentable category.
    $endgroup$
    – Derek Elkins
    Apr 8 at 12:35







1




1




$begingroup$
One way to generalize this is the notion of a locally finitely presentable category.
$endgroup$
– Derek Elkins
Apr 8 at 12:35




$begingroup$
One way to generalize this is the notion of a locally finitely presentable category.
$endgroup$
– Derek Elkins
Apr 8 at 12:35










2 Answers
2






active

oldest

votes


















13












$begingroup$

The answer is yes: every set is the union of its finite subsets.



So take $I = P_textfinite(X)$ with as morphisms the inclusion maps, and $F : I to textSet$ the inclusion.






share|cite|improve this answer









$endgroup$




















    9












    $begingroup$

    One answer already mentions the diagram of finite subsets of $X$. You would have to check that taking the union of this system actually is the colimit (which is an easy exercise).



    Since you asked for a reference, Locally Presentable and Accessible Categories by J. Adámek and J. Rosický is a great book on this kind of stuff. In particular example 1.2(1) already mentions the diagram of finite subsets.






    share|cite|improve this answer








    New contributor




    Mark Kamsma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      13












      $begingroup$

      The answer is yes: every set is the union of its finite subsets.



      So take $I = P_textfinite(X)$ with as morphisms the inclusion maps, and $F : I to textSet$ the inclusion.






      share|cite|improve this answer









      $endgroup$

















        13












        $begingroup$

        The answer is yes: every set is the union of its finite subsets.



        So take $I = P_textfinite(X)$ with as morphisms the inclusion maps, and $F : I to textSet$ the inclusion.






        share|cite|improve this answer









        $endgroup$















          13












          13








          13





          $begingroup$

          The answer is yes: every set is the union of its finite subsets.



          So take $I = P_textfinite(X)$ with as morphisms the inclusion maps, and $F : I to textSet$ the inclusion.






          share|cite|improve this answer









          $endgroup$



          The answer is yes: every set is the union of its finite subsets.



          So take $I = P_textfinite(X)$ with as morphisms the inclusion maps, and $F : I to textSet$ the inclusion.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Apr 8 at 12:31









          rabotarabota

          14.6k32886




          14.6k32886





















              9












              $begingroup$

              One answer already mentions the diagram of finite subsets of $X$. You would have to check that taking the union of this system actually is the colimit (which is an easy exercise).



              Since you asked for a reference, Locally Presentable and Accessible Categories by J. Adámek and J. Rosický is a great book on this kind of stuff. In particular example 1.2(1) already mentions the diagram of finite subsets.






              share|cite|improve this answer








              New contributor




              Mark Kamsma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.






              $endgroup$

















                9












                $begingroup$

                One answer already mentions the diagram of finite subsets of $X$. You would have to check that taking the union of this system actually is the colimit (which is an easy exercise).



                Since you asked for a reference, Locally Presentable and Accessible Categories by J. Adámek and J. Rosický is a great book on this kind of stuff. In particular example 1.2(1) already mentions the diagram of finite subsets.






                share|cite|improve this answer








                New contributor




                Mark Kamsma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$















                  9












                  9








                  9





                  $begingroup$

                  One answer already mentions the diagram of finite subsets of $X$. You would have to check that taking the union of this system actually is the colimit (which is an easy exercise).



                  Since you asked for a reference, Locally Presentable and Accessible Categories by J. Adámek and J. Rosický is a great book on this kind of stuff. In particular example 1.2(1) already mentions the diagram of finite subsets.






                  share|cite|improve this answer








                  New contributor




                  Mark Kamsma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  $endgroup$



                  One answer already mentions the diagram of finite subsets of $X$. You would have to check that taking the union of this system actually is the colimit (which is an easy exercise).



                  Since you asked for a reference, Locally Presentable and Accessible Categories by J. Adámek and J. Rosický is a great book on this kind of stuff. In particular example 1.2(1) already mentions the diagram of finite subsets.







                  share|cite|improve this answer








                  New contributor




                  Mark Kamsma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  share|cite|improve this answer



                  share|cite|improve this answer






                  New contributor




                  Mark Kamsma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  answered Apr 8 at 12:40









                  Mark KamsmaMark Kamsma

                  3616




                  3616




                  New contributor




                  Mark Kamsma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.





                  New contributor





                  Mark Kamsma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  Mark Kamsma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.



























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