Change the label of the ui.Chart.image.seriesByRegion in Google Earth Engine The 2019 Stack Overflow Developer Survey Results Are InGoogle Earth Engine: label objects on mapCount the number of pixel identified as water from a collection of landsat imageCalculating albedo values with landsat 7 ImageCollection/FeatureCollection error in Google Earth Engine?LinearFit with Google Earth EngineCloud mask for Landsat8 on Google Earth EngineDOY chart in Google Earth EngineGoogle Earth Engine - Map.addLayerGoogle Earth Engine, how to distinguish between rivers/streams and ponds/lakes in a water maskChart Series By Region in Google Earth Engine?Cloud Mask Landsat 7 Tier 2 TOA
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Change the label of the ui.Chart.image.seriesByRegion in Google Earth Engine
The 2019 Stack Overflow Developer Survey Results Are InGoogle Earth Engine: label objects on mapCount the number of pixel identified as water from a collection of landsat imageCalculating albedo values with landsat 7 ImageCollection/FeatureCollection error in Google Earth Engine?LinearFit with Google Earth EngineCloud mask for Landsat8 on Google Earth EngineDOY chart in Google Earth EngineGoogle Earth Engine - Map.addLayerGoogle Earth Engine, how to distinguish between rivers/streams and ponds/lakes in a water maskChart Series By Region in Google Earth Engine?Cloud Mask Landsat 7 Tier 2 TOA
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I would like to change the label of the chart in Google Earth Engine. I had the code:
var image= ee.FeatureCollection('ft:1OXpMKiwvIBC__iYcgjyW23A2oMr89IQlC3cLqk3q')
.filter(ee.Filter.or(ee.Filter.eq('name', 'Lake Tekapo')));
print (image);
var collection = ee.ImageCollection('LANDSAT/LC08/C01/T1_SR')
.filterBounds(image)
.filterDate('2017-01-01','2017-05-01');
// Map a function over the Landsat 8 TOA collection to add an NDVI band.
function test(image)
var equation = image.expression(
'(7.27 * B4/B3) - 1.7',
B3: image.select('B4'),
B4: image.select('B3'),
).rename('TEST').float();
return image.addBands(equation).set('system:time_start',
image.get('system:time_start'));
var test =collection.map(test).select(['TEST']);
print (test,'median');
//CHART TIME SERIES
// Define customization options.
var options =
title: 'TEST over time in regions',
hAxis: title: 'Time',
vAxis: title: 'TEST values',
lineWidth: 1,
series:
0: color: '00FF00',
1: color: '0000FF',
;
// Create a time series chart.
var tempTimeSeries = ui.Chart.image.seriesByRegion(
test, image, ee.Reducer.mean(), 'TEST',300)
.setChartType('LineChart')
.setOptions(options);
// Display.
print(tempTimeSeries);
I would like that the chart of the lable is the property name of the feature (name = Lake Tekapo) instead of the Id of the feature (id = 2819) (see the figure attached).
google-earth-engine chart
add a comment |
I would like to change the label of the chart in Google Earth Engine. I had the code:
var image= ee.FeatureCollection('ft:1OXpMKiwvIBC__iYcgjyW23A2oMr89IQlC3cLqk3q')
.filter(ee.Filter.or(ee.Filter.eq('name', 'Lake Tekapo')));
print (image);
var collection = ee.ImageCollection('LANDSAT/LC08/C01/T1_SR')
.filterBounds(image)
.filterDate('2017-01-01','2017-05-01');
// Map a function over the Landsat 8 TOA collection to add an NDVI band.
function test(image)
var equation = image.expression(
'(7.27 * B4/B3) - 1.7',
B3: image.select('B4'),
B4: image.select('B3'),
).rename('TEST').float();
return image.addBands(equation).set('system:time_start',
image.get('system:time_start'));
var test =collection.map(test).select(['TEST']);
print (test,'median');
//CHART TIME SERIES
// Define customization options.
var options =
title: 'TEST over time in regions',
hAxis: title: 'Time',
vAxis: title: 'TEST values',
lineWidth: 1,
series:
0: color: '00FF00',
1: color: '0000FF',
;
// Create a time series chart.
var tempTimeSeries = ui.Chart.image.seriesByRegion(
test, image, ee.Reducer.mean(), 'TEST',300)
.setChartType('LineChart')
.setOptions(options);
// Display.
print(tempTimeSeries);
I would like that the chart of the lable is the property name of the feature (name = Lake Tekapo) instead of the Id of the feature (id = 2819) (see the figure attached).
google-earth-engine chart
1
I got the answer. // Create a time series chart. var tempTimeSeries = ui.Chart.image.seriesByRegion( test, image, ee.Reducer.mean(), 'TEST',300, 'system:time_start','name')
– user30985
Apr 19 '18 at 13:31
Please post this as an answer instead of a comment and mark it as accepted. This way people finding this question in the future will find the answer easier.
– Kersten
Apr 20 '18 at 11:27
add a comment |
I would like to change the label of the chart in Google Earth Engine. I had the code:
var image= ee.FeatureCollection('ft:1OXpMKiwvIBC__iYcgjyW23A2oMr89IQlC3cLqk3q')
.filter(ee.Filter.or(ee.Filter.eq('name', 'Lake Tekapo')));
print (image);
var collection = ee.ImageCollection('LANDSAT/LC08/C01/T1_SR')
.filterBounds(image)
.filterDate('2017-01-01','2017-05-01');
// Map a function over the Landsat 8 TOA collection to add an NDVI band.
function test(image)
var equation = image.expression(
'(7.27 * B4/B3) - 1.7',
B3: image.select('B4'),
B4: image.select('B3'),
).rename('TEST').float();
return image.addBands(equation).set('system:time_start',
image.get('system:time_start'));
var test =collection.map(test).select(['TEST']);
print (test,'median');
//CHART TIME SERIES
// Define customization options.
var options =
title: 'TEST over time in regions',
hAxis: title: 'Time',
vAxis: title: 'TEST values',
lineWidth: 1,
series:
0: color: '00FF00',
1: color: '0000FF',
;
// Create a time series chart.
var tempTimeSeries = ui.Chart.image.seriesByRegion(
test, image, ee.Reducer.mean(), 'TEST',300)
.setChartType('LineChart')
.setOptions(options);
// Display.
print(tempTimeSeries);
I would like that the chart of the lable is the property name of the feature (name = Lake Tekapo) instead of the Id of the feature (id = 2819) (see the figure attached).
google-earth-engine chart
I would like to change the label of the chart in Google Earth Engine. I had the code:
var image= ee.FeatureCollection('ft:1OXpMKiwvIBC__iYcgjyW23A2oMr89IQlC3cLqk3q')
.filter(ee.Filter.or(ee.Filter.eq('name', 'Lake Tekapo')));
print (image);
var collection = ee.ImageCollection('LANDSAT/LC08/C01/T1_SR')
.filterBounds(image)
.filterDate('2017-01-01','2017-05-01');
// Map a function over the Landsat 8 TOA collection to add an NDVI band.
function test(image)
var equation = image.expression(
'(7.27 * B4/B3) - 1.7',
B3: image.select('B4'),
B4: image.select('B3'),
).rename('TEST').float();
return image.addBands(equation).set('system:time_start',
image.get('system:time_start'));
var test =collection.map(test).select(['TEST']);
print (test,'median');
//CHART TIME SERIES
// Define customization options.
var options =
title: 'TEST over time in regions',
hAxis: title: 'Time',
vAxis: title: 'TEST values',
lineWidth: 1,
series:
0: color: '00FF00',
1: color: '0000FF',
;
// Create a time series chart.
var tempTimeSeries = ui.Chart.image.seriesByRegion(
test, image, ee.Reducer.mean(), 'TEST',300)
.setChartType('LineChart')
.setOptions(options);
// Display.
print(tempTimeSeries);
I would like that the chart of the lable is the property name of the feature (name = Lake Tekapo) instead of the Id of the feature (id = 2819) (see the figure attached).
google-earth-engine chart
google-earth-engine chart
edited Apr 19 '18 at 7:20
Kersten
7,39332446
7,39332446
asked Apr 19 '18 at 5:23
user30985user30985
517
517
1
I got the answer. // Create a time series chart. var tempTimeSeries = ui.Chart.image.seriesByRegion( test, image, ee.Reducer.mean(), 'TEST',300, 'system:time_start','name')
– user30985
Apr 19 '18 at 13:31
Please post this as an answer instead of a comment and mark it as accepted. This way people finding this question in the future will find the answer easier.
– Kersten
Apr 20 '18 at 11:27
add a comment |
1
I got the answer. // Create a time series chart. var tempTimeSeries = ui.Chart.image.seriesByRegion( test, image, ee.Reducer.mean(), 'TEST',300, 'system:time_start','name')
– user30985
Apr 19 '18 at 13:31
Please post this as an answer instead of a comment and mark it as accepted. This way people finding this question in the future will find the answer easier.
– Kersten
Apr 20 '18 at 11:27
1
1
I got the answer. // Create a time series chart. var tempTimeSeries = ui.Chart.image.seriesByRegion( test, image, ee.Reducer.mean(), 'TEST',300, 'system:time_start','name')
– user30985
Apr 19 '18 at 13:31
I got the answer. // Create a time series chart. var tempTimeSeries = ui.Chart.image.seriesByRegion( test, image, ee.Reducer.mean(), 'TEST',300, 'system:time_start','name')
– user30985
Apr 19 '18 at 13:31
Please post this as an answer instead of a comment and mark it as accepted. This way people finding this question in the future will find the answer easier.
– Kersten
Apr 20 '18 at 11:27
Please post this as an answer instead of a comment and mark it as accepted. This way people finding this question in the future will find the answer easier.
– Kersten
Apr 20 '18 at 11:27
add a comment |
1 Answer
1
active
oldest
votes
Series labels are defined by the parameter 'seriesProperty' (the 7th 'Argument' in the syntax) for 'ui.Chart.image.seriesByRegion' function. You just have to specify the name of the column that describes names of the lakes and it should work as long as it is specified in the 7th slot. If there are certain arguments which you don't want to specify (and are not mandatory), you can leave them as 'undefined'.
So in your case the following should work,
var tempTimeSeries = ui.Chart.image.seriesByRegion(test, image, ee.Reducer.mean(), 'TEST', 300, undefined, INSERT COLUMN NAME HERE)
add a comment |
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
Series labels are defined by the parameter 'seriesProperty' (the 7th 'Argument' in the syntax) for 'ui.Chart.image.seriesByRegion' function. You just have to specify the name of the column that describes names of the lakes and it should work as long as it is specified in the 7th slot. If there are certain arguments which you don't want to specify (and are not mandatory), you can leave them as 'undefined'.
So in your case the following should work,
var tempTimeSeries = ui.Chart.image.seriesByRegion(test, image, ee.Reducer.mean(), 'TEST', 300, undefined, INSERT COLUMN NAME HERE)
add a comment |
Series labels are defined by the parameter 'seriesProperty' (the 7th 'Argument' in the syntax) for 'ui.Chart.image.seriesByRegion' function. You just have to specify the name of the column that describes names of the lakes and it should work as long as it is specified in the 7th slot. If there are certain arguments which you don't want to specify (and are not mandatory), you can leave them as 'undefined'.
So in your case the following should work,
var tempTimeSeries = ui.Chart.image.seriesByRegion(test, image, ee.Reducer.mean(), 'TEST', 300, undefined, INSERT COLUMN NAME HERE)
add a comment |
Series labels are defined by the parameter 'seriesProperty' (the 7th 'Argument' in the syntax) for 'ui.Chart.image.seriesByRegion' function. You just have to specify the name of the column that describes names of the lakes and it should work as long as it is specified in the 7th slot. If there are certain arguments which you don't want to specify (and are not mandatory), you can leave them as 'undefined'.
So in your case the following should work,
var tempTimeSeries = ui.Chart.image.seriesByRegion(test, image, ee.Reducer.mean(), 'TEST', 300, undefined, INSERT COLUMN NAME HERE)
Series labels are defined by the parameter 'seriesProperty' (the 7th 'Argument' in the syntax) for 'ui.Chart.image.seriesByRegion' function. You just have to specify the name of the column that describes names of the lakes and it should work as long as it is specified in the 7th slot. If there are certain arguments which you don't want to specify (and are not mandatory), you can leave them as 'undefined'.
So in your case the following should work,
var tempTimeSeries = ui.Chart.image.seriesByRegion(test, image, ee.Reducer.mean(), 'TEST', 300, undefined, INSERT COLUMN NAME HERE)
answered Oct 4 '18 at 16:10
TejasTejas
1
1
add a comment |
add a comment |
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I got the answer. // Create a time series chart. var tempTimeSeries = ui.Chart.image.seriesByRegion( test, image, ee.Reducer.mean(), 'TEST',300, 'system:time_start','name')
– user30985
Apr 19 '18 at 13:31
Please post this as an answer instead of a comment and mark it as accepted. This way people finding this question in the future will find the answer easier.
– Kersten
Apr 20 '18 at 11:27