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Find max and min values from a table based on two fields



Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Selection on Feature layer (geoprocessing)Using ListFields and CalculateField to find max value in variable number of fields to populate another field?How to group numbers based on first digits and then find min/max?Debugging syntax error (invalid syntax) from arcpy.SelectLayerByAttribute_management()?Debugging RuntimeError: A column was specified that does not exist from ArcPy?Iterate through a list to use then use SearchCursor to populate new listPass list parameter to SQL expressionSetting up where_clause to select counties one at a time from feature class using ArcPy?SQL Query Syntax gives ERROR 000358: Invalid expression?Finding many intersecting polygons of one layer and listing them in single field using ArcGIS Desktop?



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4















I have a geodatabase table with the following fields: County_Name, State_Name, Date_Time, Customers



Example



Alameda, CA, 8/1/2014 12AM, 6 
Alameda, CA, 8/1/2014 1AM, 1
Alameda, CA, 8/1/2014 2AM, 3
....


Data for all US counties is in the table. I just want to create a new table that contains the



  • county, state, max customers for the day (24 hour period), time of the max customers

  • county, state, min customers for the day (24 hour period), time of the min customers

Many states have the same county names as other states.



Do I need to create a cursor to obtain a list of the unique county and state names first?



This will give me a list of the county names but I also need the state names.



with arcpy.da.SearchCursor(tablesMerged, ["county_nam"]) as cursor:
print sorted(row[0] for rows in cursor)









share|improve this question
























  • Are you looking for a whole script or a few hints how to accomplish this?

    – Stophface
    Aug 12 '14 at 18:44











  • Just a few hints would be great! Thanks. I haven't used Python in a little while but I think I would be able to get going with a few hints.

    – Andrew
    Aug 12 '14 at 18:46






  • 3





    the most straightforward is to use the built in "summary statistics" tools with several case fields

    – radouxju
    Aug 12 '14 at 19:38











  • That may work. I didn't know it allowed for multiple case fields. I will give that a shot! Thanks.

    – Andrew
    Aug 12 '14 at 19:56











  • I agree with @radouxju - Summary Statistics could save you a lot of code here, and should also run faster.

    – PolyGeo
    Aug 12 '14 at 21:46

















4















I have a geodatabase table with the following fields: County_Name, State_Name, Date_Time, Customers



Example



Alameda, CA, 8/1/2014 12AM, 6 
Alameda, CA, 8/1/2014 1AM, 1
Alameda, CA, 8/1/2014 2AM, 3
....


Data for all US counties is in the table. I just want to create a new table that contains the



  • county, state, max customers for the day (24 hour period), time of the max customers

  • county, state, min customers for the day (24 hour period), time of the min customers

Many states have the same county names as other states.



Do I need to create a cursor to obtain a list of the unique county and state names first?



This will give me a list of the county names but I also need the state names.



with arcpy.da.SearchCursor(tablesMerged, ["county_nam"]) as cursor:
print sorted(row[0] for rows in cursor)









share|improve this question
























  • Are you looking for a whole script or a few hints how to accomplish this?

    – Stophface
    Aug 12 '14 at 18:44











  • Just a few hints would be great! Thanks. I haven't used Python in a little while but I think I would be able to get going with a few hints.

    – Andrew
    Aug 12 '14 at 18:46






  • 3





    the most straightforward is to use the built in "summary statistics" tools with several case fields

    – radouxju
    Aug 12 '14 at 19:38











  • That may work. I didn't know it allowed for multiple case fields. I will give that a shot! Thanks.

    – Andrew
    Aug 12 '14 at 19:56











  • I agree with @radouxju - Summary Statistics could save you a lot of code here, and should also run faster.

    – PolyGeo
    Aug 12 '14 at 21:46













4












4








4








I have a geodatabase table with the following fields: County_Name, State_Name, Date_Time, Customers



Example



Alameda, CA, 8/1/2014 12AM, 6 
Alameda, CA, 8/1/2014 1AM, 1
Alameda, CA, 8/1/2014 2AM, 3
....


Data for all US counties is in the table. I just want to create a new table that contains the



  • county, state, max customers for the day (24 hour period), time of the max customers

  • county, state, min customers for the day (24 hour period), time of the min customers

Many states have the same county names as other states.



Do I need to create a cursor to obtain a list of the unique county and state names first?



This will give me a list of the county names but I also need the state names.



with arcpy.da.SearchCursor(tablesMerged, ["county_nam"]) as cursor:
print sorted(row[0] for rows in cursor)









share|improve this question
















I have a geodatabase table with the following fields: County_Name, State_Name, Date_Time, Customers



Example



Alameda, CA, 8/1/2014 12AM, 6 
Alameda, CA, 8/1/2014 1AM, 1
Alameda, CA, 8/1/2014 2AM, 3
....


Data for all US counties is in the table. I just want to create a new table that contains the



  • county, state, max customers for the day (24 hour period), time of the max customers

  • county, state, min customers for the day (24 hour period), time of the min customers

Many states have the same county names as other states.



Do I need to create a cursor to obtain a list of the unique county and state names first?



This will give me a list of the county names but I also need the state names.



with arcpy.da.SearchCursor(tablesMerged, ["county_nam"]) as cursor:
print sorted(row[0] for rows in cursor)






arcpy cursor attribute-joins






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 12 '18 at 9:32









PolyGeo

54k1782246




54k1782246










asked Aug 12 '14 at 18:27









AndrewAndrew

199313




199313












  • Are you looking for a whole script or a few hints how to accomplish this?

    – Stophface
    Aug 12 '14 at 18:44











  • Just a few hints would be great! Thanks. I haven't used Python in a little while but I think I would be able to get going with a few hints.

    – Andrew
    Aug 12 '14 at 18:46






  • 3





    the most straightforward is to use the built in "summary statistics" tools with several case fields

    – radouxju
    Aug 12 '14 at 19:38











  • That may work. I didn't know it allowed for multiple case fields. I will give that a shot! Thanks.

    – Andrew
    Aug 12 '14 at 19:56











  • I agree with @radouxju - Summary Statistics could save you a lot of code here, and should also run faster.

    – PolyGeo
    Aug 12 '14 at 21:46

















  • Are you looking for a whole script or a few hints how to accomplish this?

    – Stophface
    Aug 12 '14 at 18:44











  • Just a few hints would be great! Thanks. I haven't used Python in a little while but I think I would be able to get going with a few hints.

    – Andrew
    Aug 12 '14 at 18:46






  • 3





    the most straightforward is to use the built in "summary statistics" tools with several case fields

    – radouxju
    Aug 12 '14 at 19:38











  • That may work. I didn't know it allowed for multiple case fields. I will give that a shot! Thanks.

    – Andrew
    Aug 12 '14 at 19:56











  • I agree with @radouxju - Summary Statistics could save you a lot of code here, and should also run faster.

    – PolyGeo
    Aug 12 '14 at 21:46
















Are you looking for a whole script or a few hints how to accomplish this?

– Stophface
Aug 12 '14 at 18:44





Are you looking for a whole script or a few hints how to accomplish this?

– Stophface
Aug 12 '14 at 18:44













Just a few hints would be great! Thanks. I haven't used Python in a little while but I think I would be able to get going with a few hints.

– Andrew
Aug 12 '14 at 18:46





Just a few hints would be great! Thanks. I haven't used Python in a little while but I think I would be able to get going with a few hints.

– Andrew
Aug 12 '14 at 18:46




3




3





the most straightforward is to use the built in "summary statistics" tools with several case fields

– radouxju
Aug 12 '14 at 19:38





the most straightforward is to use the built in "summary statistics" tools with several case fields

– radouxju
Aug 12 '14 at 19:38













That may work. I didn't know it allowed for multiple case fields. I will give that a shot! Thanks.

– Andrew
Aug 12 '14 at 19:56





That may work. I didn't know it allowed for multiple case fields. I will give that a shot! Thanks.

– Andrew
Aug 12 '14 at 19:56













I agree with @radouxju - Summary Statistics could save you a lot of code here, and should also run faster.

– PolyGeo
Aug 12 '14 at 21:46





I agree with @radouxju - Summary Statistics could save you a lot of code here, and should also run faster.

– PolyGeo
Aug 12 '14 at 21:46










1 Answer
1






active

oldest

votes


















3














Since you said you just need a hint with python I came up with this:



My test table:



testtable



import arcpy

arcpy.env.workspace = "..." #on windows use \


#SEARCHCURSOR
#SearchCursor (in_table, field_names, where_clause, spatial_reference, explode_to_points, sql_clause)"""
stable = "test2.shp"
sfield = ["county", "state", "date", "Customers"]


namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)) #a set is a collection type which does not allow duplicates
#since there are a lot of duplicates (countynames) we only want each countyname once
#more information on sets can be found here http://www.python-course.eu/sets_frozensets.php

print "Countynames without duplicates: ", namesdb



"""
I only left that in for better understanding what is basically happening in the generator above
The namesdb = set(row.....) replaces all of this:


names = []
namesdb = []

with arcpy.da.SearchCursor(stable, sfield) as scursor: #search for the county names
for srow in scursor:
names.append(srow[0]) #append all found countynames to a list


print "duplicates: ", names


for i in names: #get rid of dublicates in statenames
if i not in namesdb:
namesdb.append(i) #create new list without duplicates


print "without duplicates: ", namesdb

"""


countylist = #create a dict where elements from namesdb are the KEYS
for name in namesdb:
countylist[name] = []

print "dict: ", countylist


with arcpy.da.SearchCursor(stable, sfield) as scursor:
for srow in scursor:
for county in namesdb: #iterate through the namesdb list
if srow [0] == county: #get the value of each defined column in sfield for each row of countyname
countylist[county].append(srow) #append to the matching KEY in dictionary

else:
continue


print "dict with values: ", countylist


from operator import itemgetter
#now the trickiest part (for me, cause I am a python beginner, and that really hurt my head). I went to SO to ask a question. See here for better underatanding whats happening: http://stackoverflow.com/questions/25288927/finding-the-max-value-of-list-in-dictionary?noredirect=1#comment39411443_25288927

maxcostumers = k: max(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns max number of customers, if customers is the last column in your table. If not, adjust the -1
mincostumers = k: min(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns the min number of customers, as see above


print "row from table with max costumers: ", maxcostumers
print "row from table with min costumers: ", mincostumers


Thats the Output generated:



ountynames without duplicates: set([u'New_York', u'Jersy', u'Alameda'])

dict: u'New_York': [], u'Jersy': [], u'Alameda': []

dict with values:
u'New_York': [(u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 4), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3)],
u'Jersy': [(u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6), (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7)],
u'Alameda': [(u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 2), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)]


row from table with max costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3)


row from table with min costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)



Then you only need an UpdateCursor and the formatting for the time.
Information regarding this you will find here:
http://resources.arcgis.com/en/help/main/10.1/index.html#//018w00000014000000
and
http://resources.arcgis.com/en/help/main/10.1/index.html#//001700000046000000






share|improve this answer




















  • 2





    Since dictionaries are orderless, you can just use set() to remove duplicates. You can pass a generator expression directly to it, a la namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)).

    – Paul
    Aug 12 '14 at 20:49











  • @Paul thanks for the further input. Ill check that tomorrow.

    – Stophface
    Aug 12 '14 at 22:12











  • Thank you! I will try and test this out today or tomorrow.

    – Andrew
    Aug 13 '14 at 13:20











  • @Andrew I updated my answere

    – Stophface
    Aug 13 '14 at 16:03











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

votes






active

oldest

votes









3














Since you said you just need a hint with python I came up with this:



My test table:



testtable



import arcpy

arcpy.env.workspace = "..." #on windows use \


#SEARCHCURSOR
#SearchCursor (in_table, field_names, where_clause, spatial_reference, explode_to_points, sql_clause)"""
stable = "test2.shp"
sfield = ["county", "state", "date", "Customers"]


namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)) #a set is a collection type which does not allow duplicates
#since there are a lot of duplicates (countynames) we only want each countyname once
#more information on sets can be found here http://www.python-course.eu/sets_frozensets.php

print "Countynames without duplicates: ", namesdb



"""
I only left that in for better understanding what is basically happening in the generator above
The namesdb = set(row.....) replaces all of this:


names = []
namesdb = []

with arcpy.da.SearchCursor(stable, sfield) as scursor: #search for the county names
for srow in scursor:
names.append(srow[0]) #append all found countynames to a list


print "duplicates: ", names


for i in names: #get rid of dublicates in statenames
if i not in namesdb:
namesdb.append(i) #create new list without duplicates


print "without duplicates: ", namesdb

"""


countylist = #create a dict where elements from namesdb are the KEYS
for name in namesdb:
countylist[name] = []

print "dict: ", countylist


with arcpy.da.SearchCursor(stable, sfield) as scursor:
for srow in scursor:
for county in namesdb: #iterate through the namesdb list
if srow [0] == county: #get the value of each defined column in sfield for each row of countyname
countylist[county].append(srow) #append to the matching KEY in dictionary

else:
continue


print "dict with values: ", countylist


from operator import itemgetter
#now the trickiest part (for me, cause I am a python beginner, and that really hurt my head). I went to SO to ask a question. See here for better underatanding whats happening: http://stackoverflow.com/questions/25288927/finding-the-max-value-of-list-in-dictionary?noredirect=1#comment39411443_25288927

maxcostumers = k: max(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns max number of customers, if customers is the last column in your table. If not, adjust the -1
mincostumers = k: min(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns the min number of customers, as see above


print "row from table with max costumers: ", maxcostumers
print "row from table with min costumers: ", mincostumers


Thats the Output generated:



ountynames without duplicates: set([u'New_York', u'Jersy', u'Alameda'])

dict: u'New_York': [], u'Jersy': [], u'Alameda': []

dict with values:
u'New_York': [(u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 4), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3)],
u'Jersy': [(u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6), (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7)],
u'Alameda': [(u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 2), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)]


row from table with max costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3)


row from table with min costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)



Then you only need an UpdateCursor and the formatting for the time.
Information regarding this you will find here:
http://resources.arcgis.com/en/help/main/10.1/index.html#//018w00000014000000
and
http://resources.arcgis.com/en/help/main/10.1/index.html#//001700000046000000






share|improve this answer




















  • 2





    Since dictionaries are orderless, you can just use set() to remove duplicates. You can pass a generator expression directly to it, a la namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)).

    – Paul
    Aug 12 '14 at 20:49











  • @Paul thanks for the further input. Ill check that tomorrow.

    – Stophface
    Aug 12 '14 at 22:12











  • Thank you! I will try and test this out today or tomorrow.

    – Andrew
    Aug 13 '14 at 13:20











  • @Andrew I updated my answere

    – Stophface
    Aug 13 '14 at 16:03















3














Since you said you just need a hint with python I came up with this:



My test table:



testtable



import arcpy

arcpy.env.workspace = "..." #on windows use \


#SEARCHCURSOR
#SearchCursor (in_table, field_names, where_clause, spatial_reference, explode_to_points, sql_clause)"""
stable = "test2.shp"
sfield = ["county", "state", "date", "Customers"]


namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)) #a set is a collection type which does not allow duplicates
#since there are a lot of duplicates (countynames) we only want each countyname once
#more information on sets can be found here http://www.python-course.eu/sets_frozensets.php

print "Countynames without duplicates: ", namesdb



"""
I only left that in for better understanding what is basically happening in the generator above
The namesdb = set(row.....) replaces all of this:


names = []
namesdb = []

with arcpy.da.SearchCursor(stable, sfield) as scursor: #search for the county names
for srow in scursor:
names.append(srow[0]) #append all found countynames to a list


print "duplicates: ", names


for i in names: #get rid of dublicates in statenames
if i not in namesdb:
namesdb.append(i) #create new list without duplicates


print "without duplicates: ", namesdb

"""


countylist = #create a dict where elements from namesdb are the KEYS
for name in namesdb:
countylist[name] = []

print "dict: ", countylist


with arcpy.da.SearchCursor(stable, sfield) as scursor:
for srow in scursor:
for county in namesdb: #iterate through the namesdb list
if srow [0] == county: #get the value of each defined column in sfield for each row of countyname
countylist[county].append(srow) #append to the matching KEY in dictionary

else:
continue


print "dict with values: ", countylist


from operator import itemgetter
#now the trickiest part (for me, cause I am a python beginner, and that really hurt my head). I went to SO to ask a question. See here for better underatanding whats happening: http://stackoverflow.com/questions/25288927/finding-the-max-value-of-list-in-dictionary?noredirect=1#comment39411443_25288927

maxcostumers = k: max(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns max number of customers, if customers is the last column in your table. If not, adjust the -1
mincostumers = k: min(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns the min number of customers, as see above


print "row from table with max costumers: ", maxcostumers
print "row from table with min costumers: ", mincostumers


Thats the Output generated:



ountynames without duplicates: set([u'New_York', u'Jersy', u'Alameda'])

dict: u'New_York': [], u'Jersy': [], u'Alameda': []

dict with values:
u'New_York': [(u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 4), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3)],
u'Jersy': [(u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6), (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7)],
u'Alameda': [(u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 2), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)]


row from table with max costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3)


row from table with min costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)



Then you only need an UpdateCursor and the formatting for the time.
Information regarding this you will find here:
http://resources.arcgis.com/en/help/main/10.1/index.html#//018w00000014000000
and
http://resources.arcgis.com/en/help/main/10.1/index.html#//001700000046000000






share|improve this answer




















  • 2





    Since dictionaries are orderless, you can just use set() to remove duplicates. You can pass a generator expression directly to it, a la namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)).

    – Paul
    Aug 12 '14 at 20:49











  • @Paul thanks for the further input. Ill check that tomorrow.

    – Stophface
    Aug 12 '14 at 22:12











  • Thank you! I will try and test this out today or tomorrow.

    – Andrew
    Aug 13 '14 at 13:20











  • @Andrew I updated my answere

    – Stophface
    Aug 13 '14 at 16:03













3












3








3







Since you said you just need a hint with python I came up with this:



My test table:



testtable



import arcpy

arcpy.env.workspace = "..." #on windows use \


#SEARCHCURSOR
#SearchCursor (in_table, field_names, where_clause, spatial_reference, explode_to_points, sql_clause)"""
stable = "test2.shp"
sfield = ["county", "state", "date", "Customers"]


namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)) #a set is a collection type which does not allow duplicates
#since there are a lot of duplicates (countynames) we only want each countyname once
#more information on sets can be found here http://www.python-course.eu/sets_frozensets.php

print "Countynames without duplicates: ", namesdb



"""
I only left that in for better understanding what is basically happening in the generator above
The namesdb = set(row.....) replaces all of this:


names = []
namesdb = []

with arcpy.da.SearchCursor(stable, sfield) as scursor: #search for the county names
for srow in scursor:
names.append(srow[0]) #append all found countynames to a list


print "duplicates: ", names


for i in names: #get rid of dublicates in statenames
if i not in namesdb:
namesdb.append(i) #create new list without duplicates


print "without duplicates: ", namesdb

"""


countylist = #create a dict where elements from namesdb are the KEYS
for name in namesdb:
countylist[name] = []

print "dict: ", countylist


with arcpy.da.SearchCursor(stable, sfield) as scursor:
for srow in scursor:
for county in namesdb: #iterate through the namesdb list
if srow [0] == county: #get the value of each defined column in sfield for each row of countyname
countylist[county].append(srow) #append to the matching KEY in dictionary

else:
continue


print "dict with values: ", countylist


from operator import itemgetter
#now the trickiest part (for me, cause I am a python beginner, and that really hurt my head). I went to SO to ask a question. See here for better underatanding whats happening: http://stackoverflow.com/questions/25288927/finding-the-max-value-of-list-in-dictionary?noredirect=1#comment39411443_25288927

maxcostumers = k: max(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns max number of customers, if customers is the last column in your table. If not, adjust the -1
mincostumers = k: min(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns the min number of customers, as see above


print "row from table with max costumers: ", maxcostumers
print "row from table with min costumers: ", mincostumers


Thats the Output generated:



ountynames without duplicates: set([u'New_York', u'Jersy', u'Alameda'])

dict: u'New_York': [], u'Jersy': [], u'Alameda': []

dict with values:
u'New_York': [(u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 4), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3)],
u'Jersy': [(u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6), (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7)],
u'Alameda': [(u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 2), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)]


row from table with max costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3)


row from table with min costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)



Then you only need an UpdateCursor and the formatting for the time.
Information regarding this you will find here:
http://resources.arcgis.com/en/help/main/10.1/index.html#//018w00000014000000
and
http://resources.arcgis.com/en/help/main/10.1/index.html#//001700000046000000






share|improve this answer















Since you said you just need a hint with python I came up with this:



My test table:



testtable



import arcpy

arcpy.env.workspace = "..." #on windows use \


#SEARCHCURSOR
#SearchCursor (in_table, field_names, where_clause, spatial_reference, explode_to_points, sql_clause)"""
stable = "test2.shp"
sfield = ["county", "state", "date", "Customers"]


namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)) #a set is a collection type which does not allow duplicates
#since there are a lot of duplicates (countynames) we only want each countyname once
#more information on sets can be found here http://www.python-course.eu/sets_frozensets.php

print "Countynames without duplicates: ", namesdb



"""
I only left that in for better understanding what is basically happening in the generator above
The namesdb = set(row.....) replaces all of this:


names = []
namesdb = []

with arcpy.da.SearchCursor(stable, sfield) as scursor: #search for the county names
for srow in scursor:
names.append(srow[0]) #append all found countynames to a list


print "duplicates: ", names


for i in names: #get rid of dublicates in statenames
if i not in namesdb:
namesdb.append(i) #create new list without duplicates


print "without duplicates: ", namesdb

"""


countylist = #create a dict where elements from namesdb are the KEYS
for name in namesdb:
countylist[name] = []

print "dict: ", countylist


with arcpy.da.SearchCursor(stable, sfield) as scursor:
for srow in scursor:
for county in namesdb: #iterate through the namesdb list
if srow [0] == county: #get the value of each defined column in sfield for each row of countyname
countylist[county].append(srow) #append to the matching KEY in dictionary

else:
continue


print "dict with values: ", countylist


from operator import itemgetter
#now the trickiest part (for me, cause I am a python beginner, and that really hurt my head). I went to SO to ask a question. See here for better underatanding whats happening: http://stackoverflow.com/questions/25288927/finding-the-max-value-of-list-in-dictionary?noredirect=1#comment39411443_25288927

maxcostumers = k: max(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns max number of customers, if customers is the last column in your table. If not, adjust the -1
mincostumers = k: min(v, key=itemgetter(-1)) for k, v in countylist.iteritems() #returns the min number of customers, as see above


print "row from table with max costumers: ", maxcostumers
print "row from table with min costumers: ", mincostumers


Thats the Output generated:



ountynames without duplicates: set([u'New_York', u'Jersy', u'Alameda'])

dict: u'New_York': [], u'Jersy': [], u'Alameda': []

dict with values:
u'New_York': [(u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 4), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3)],
u'Jersy': [(u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6), (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7)],
u'Alameda': [(u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 2), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)]


row from table with max costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3)


row from table with min costumers:
u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3),
u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6),
u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)



Then you only need an UpdateCursor and the formatting for the time.
Information regarding this you will find here:
http://resources.arcgis.com/en/help/main/10.1/index.html#//018w00000014000000
and
http://resources.arcgis.com/en/help/main/10.1/index.html#//001700000046000000







share|improve this answer














share|improve this answer



share|improve this answer








edited Apr 11 at 17:17









Glorfindel

3011311




3011311










answered Aug 12 '14 at 20:39









StophfaceStophface

1,19811540




1,19811540







  • 2





    Since dictionaries are orderless, you can just use set() to remove duplicates. You can pass a generator expression directly to it, a la namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)).

    – Paul
    Aug 12 '14 at 20:49











  • @Paul thanks for the further input. Ill check that tomorrow.

    – Stophface
    Aug 12 '14 at 22:12











  • Thank you! I will try and test this out today or tomorrow.

    – Andrew
    Aug 13 '14 at 13:20











  • @Andrew I updated my answere

    – Stophface
    Aug 13 '14 at 16:03












  • 2





    Since dictionaries are orderless, you can just use set() to remove duplicates. You can pass a generator expression directly to it, a la namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)).

    – Paul
    Aug 12 '14 at 20:49











  • @Paul thanks for the further input. Ill check that tomorrow.

    – Stophface
    Aug 12 '14 at 22:12











  • Thank you! I will try and test this out today or tomorrow.

    – Andrew
    Aug 13 '14 at 13:20











  • @Andrew I updated my answere

    – Stophface
    Aug 13 '14 at 16:03







2




2





Since dictionaries are orderless, you can just use set() to remove duplicates. You can pass a generator expression directly to it, a la namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)).

– Paul
Aug 12 '14 at 20:49





Since dictionaries are orderless, you can just use set() to remove duplicates. You can pass a generator expression directly to it, a la namesdb = set(row[0] for row in arcpy.da.SearchCursor(stable, sfield)).

– Paul
Aug 12 '14 at 20:49













@Paul thanks for the further input. Ill check that tomorrow.

– Stophface
Aug 12 '14 at 22:12





@Paul thanks for the further input. Ill check that tomorrow.

– Stophface
Aug 12 '14 at 22:12













Thank you! I will try and test this out today or tomorrow.

– Andrew
Aug 13 '14 at 13:20





Thank you! I will try and test this out today or tomorrow.

– Andrew
Aug 13 '14 at 13:20













@Andrew I updated my answere

– Stophface
Aug 13 '14 at 16:03





@Andrew I updated my answere

– Stophface
Aug 13 '14 at 16:03

















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